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a) ta thay 1-2002/2003= 1/2003 va 1-2003/2004=1/2004
ma 1/2003>1/2004 =>2002/2003<2003/2004
b) ta co -2002/2003<1<2005/2004
ta có
\(-\frac{2002}{2003}>-1>\frac{2005}{-2004}.\)
\(\Rightarrow-\frac{2002}{2003}>\frac{2005}{-2004}\)
Ta có :
\(\frac{-2002}{2003}>-1\)
\(-1>\frac{-2005}{2004}\)
\(\Rightarrow\frac{-2002}{2003}>\frac{-2005}{2004}\)
Ta có:
\(-\frac{2002}{2003}>-1\)
\(-\frac{2005}{2004}< -1\)
=> \(-\frac{2002}{2003}>-\frac{2005}{2004}\)
\(P=\frac{\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}-\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)
\(P=\frac{\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}}{5\left(\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}\right)}-\frac{2\left(\frac{1}{2002}+\frac{1}{2003}-\frac{1}{2004}\right)}{3\left(\frac{1}{2002}+\frac{1}{2003}-\frac{1}{2004}\right)}\)
\(P=\frac{1}{5}-\frac{2}{3}=\frac{3-10}{15}=\frac{-7}{15}\)
Do -2002/2003>-1 và -2005/2004<-1
\(\Rightarrow\)-2002/2003>-2005/2004
Ta có 2004/2003 = 2003+ 1/ 2003 = 1 + 1/2003
2003/2002= 2002 + 1/ 2002 = 1+ 1/2002
Do 1/2003 < 1/2002 => 1 + 1/2003 < 1+ 1/2002 hay 2004/2003 < 2003/2002
\(\frac{2004}{2003}\)= 1,0004992
\(\frac{2003}{2002}\)= 1,0004995
Vậy ,\(\frac{2003}{2002}\)lớn hơn \(\frac{2004}{2003}\).
Có \(\frac{2004}{2003}=1+\frac{1}{2003}\)
\(\frac{2003}{2002}=1+\frac{1}{2002}\)
Vì \(\frac{1}{2003}< \frac{1}{2002}\)
=) \(1+\frac{1}{2003}< 1+\frac{1}{2002}\)
=) \(\frac{2004}{2003}< \frac{2003}{2002}\)
So sánh phần hơn nha bạn
Ta có : \(\frac{2004}{2003}=1+\frac{1}{2003}\)
\(\frac{2003}{2002}=1+\frac{1}{2002}\)
Mà 1 = 1 và \(\frac{1}{2003}< \frac{1}{2002}\)
Nên \(\frac{2004}{2003}< \frac{2003}{2002}\)
Ta có:\(\frac{2004}{2003}=1+\frac{1}{2003}\)
Tương tự: \(\frac{2003}{2002}=1+\frac{1}{2002}\)
Mà \(\frac{1}{2003}< \frac{1}{2002}\)
Suy ra \(1+\frac{1}{2003}< 1+\frac{1}{2002}\)
Vậy \(\frac{2004}{2003}< \frac{2003}{2002}\)
Chúc bạn học tốt nhé
Cho A=20032004+20042005; B=2003+20042004+2005
Ta có: B=20032004+2005+20042004+2005
Vì: 20032004+2005<20032004
20042004+2005<20042005
=>20032004+2005+20042004+2004<20032004+20042005
=>2003+20042004+2005<20032004+20042005
=>B<A
Vậy B<A