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\(\frac{2}{-5}=\frac{-24}{60}\)
\(\frac{3}{-4}=\frac{-45}{60}\)
\(\frac{6}{-24}=\frac{-1}{4}=\frac{-15}{60}\)
\(-\frac{8}{80}=\frac{-1}{10}=\frac{-6}{60}\)
\(\frac{7}{-14}=-\frac{1}{2}=\frac{-30}{60}\)
bài 1 :
\(\frac{2}{3}\)+\(\frac{1}{3}\)=\(\frac{3}{3}\)=1
\(\frac{3}{4}\)+\(\frac{2}{4}\)+\(\frac{1}{4}\)=\(\frac{4}{4}\)=1
\(\frac{4}{5}\)+\(\frac{3}{5}\)+\(\frac{2}{5}\)+\(\frac{1}{5}\)=\(\frac{10}{5}\)= 2
chúc bạn học tốt !!!
a)\(A=\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{2}\right)vaB=\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
+)Ta có:\(A=\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{2}\right)\)
\(\Leftrightarrow A=\frac{31}{23}-\left(\frac{7}{32}+\frac{128}{32}\right)\)
\(\Leftrightarrow A=\frac{31}{23}-\frac{135}{32}\)
\(\Leftrightarrow A=\frac{992}{736}-\frac{3105}{736}\)
\(\Leftrightarrow A=\frac{-2113}{736}\left(1\right)\)
+)Ta lại có:\(B=\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
\(\Leftrightarrow B=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)
\(\Leftrightarrow B=\frac{1}{3}+\left(\frac{12}{67}-\frac{79}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)
\(\Leftrightarrow B=\frac{1}{3}+\frac{-67}{67}+\frac{41}{41}\)
\(\Leftrightarrow B=\frac{1}{3}+\left(-1\right)+1\)
\(\Leftrightarrow B=\frac{1}{3}\left(2\right)\)
+)Từ (1) và (2)
\(\Leftrightarrow A< 0< B\Leftrightarrow A< B\)
Vậy A<B
b)\(\frac{200420042004}{200520052005}va\frac{2004}{2005}\)
+)Ta có \(\frac{200420042004}{200520052005}=\frac{2004.100010001}{2005.100010001}=\frac{2004}{2005}\)
\(\Leftrightarrow\frac{200420042004}{200520052005}=\frac{2004}{2005}\)
c)\(C=\frac{2020^{2006}+1}{2020^{2007}+1}vaD=\frac{2020^{2005}+1}{2020^{2006}+1}\)
\(C=\frac{2020^{2006}+1}{2020^{2007}+1}< 1\)
\(\Leftrightarrow C< \frac{2020^{2006}+1+2019}{2020^{2007}+1+2019}=\frac{2020^{2006}+2020}{2020^{2007}+2020}=\frac{2020.\left(2020^{2005}+1\right)}{2020.\left(2020^{2006}+1\right)}=\frac{2020^{2005}+1}{2020^{2006}+1}\)
\(\Leftrightarrow C< D\)
Chúc bạn học tốt
\(\frac{-3}{14}\) - \(\frac{5}{-14}\)
= \(\frac{-3}{14}+\frac{5}{14}\)
= \(\frac{2}{14}\)
= \(\frac17\)
- \(\frac54\) - \(\frac34\)
= -(\(\frac54+\frac34\))
= - \(\frac84\)
= - 2
\(\frac{15}{6}-\frac{-10}{20}\)
= \(\frac52\) + \(\frac12\)
= \(\frac62\)
= 3
\(\frac{26}{-35}\) - \(\frac{6}{35}\)
= - (\(\frac{26}{35}\) + \(\frac{6}{35}\))
=- \(\frac{32}{35}\)
vậy thi biếng làm
a. Ta có 333/444 = 333:111/444:111=3/4
tick đi mình làm tiếp cho
a) \(\frac{333}{444}=\frac{3.111}{4.111}=\frac{3}{4}\Leftrightarrow\frac{3}{4}=\frac{333}{444}\)
b) \(-\frac{43}{47}<0<\frac{4343}{4745}\Leftrightarrow\frac{-43}{47}<\frac{4343}{4745}\)
Ai tick cho mình tròn 30 với
a,3/4 và 333/444
333/444=3/4
3/4=3/4
=>3/4=3/4
b,-43/47 và 4343/4745
Mà : âm bé hơn dương
Nên : -43/47 (âm)<4343/4715(dương)
c,-1212/2323 và -12/23
-1212/2323=-12/23
-12/23
=>-12/23=-12/23
d,179/197 và 971/917
179/197=0,9086294416
971/917=1,058887677
Mà : 0<1
=>179/197<971/917
a) Ta có :
\(\frac{333}{444}=\frac{3\times111}{4\times111}=\frac{3}{4}\Rightarrow\frac{3}{4}=\frac{3}{4}\)
Vậy \(\frac{333}{444}=\frac{3}{4}\)
b) Ta có :
\(\frac{-43}{47}<0<\frac{4343}{4745}\Rightarrow\frac{-43}{47}<\frac{4343}{4745}\)
Vậy \(\frac{-43}{47}<\frac{4343}{4745}\)
c) Ta có :
\(\frac{-1212}{2323}=\frac{-12\times101}{23\times101}=\frac{-12}{23}\Rightarrow\frac{-1212}{2323}=\frac{-12}{23}\)
Vậy \(\frac{-1212}{2323}=\frac{-12}{23}\)
d) Ta có :
\(\frac{179}{197}<1\)mà \(\frac{971}{917}>1\)\(\Rightarrow\frac{179}{197}<\frac{971}{917}\)
Vậy \(\frac{179}{197}<\frac{971}{917}\)