a: \(-\frac{10}{3}+\frac{13}{10}-\frac16+\frac{7}{10}\)

\(=\left(-\frac{10}{3}-\frac16\right)+\left(\frac{13}{10}+\frac{7}{10}\right)\)

\(=-\frac{21}{6}+\frac{20}{10}=-\frac72+2=-\frac32\)

b: \(1-\frac{20}{6}+\frac{39}{30}-\frac{4}{24}+\frac{34}{50}\)

\(=1-\frac{20}{6}+\frac16+1,3+0,68\)

\(=1-\frac{19}{6}+1,98=2,98-\frac{19}{6}=\frac{298}{100}-\frac{19}{6}=\frac{-56}{300}=\frac{-14}{75}\)

c: \(\frac{15}{24}-\frac{6}{26}+\frac{28}{48}-\frac{30}{39}+\frac{10}{24}\)

\(=\left(\frac{15}{24}+\frac{10}{24}+\frac{28}{48}\right)-\left(\frac{3}{13}+\frac{10}{13}\right)\)

\(=\left(\frac{25}{24}+\frac{14}{24}\right)-1=\frac{39}{24}-1=\frac{15}{24}=\frac58\)

d: \(-\frac{5}{10}+\frac{12}{28}-\frac{3}{27}-\frac{7}{18}+\frac{20}{35}\)

\(=-\frac12+\frac37-\frac19-\frac{7}{18}+\frac47\)

\(=\left(-\frac12-\frac19-\frac{7}{18}\right)+\left(\frac37+\frac47\right)=-1+1=0\)

b/ Ta có 

\(A-B=\frac{3}{8^3}+\frac{7}{8^4}-\frac{7}{8^3}-\frac{3}{8^4}\)

\(=\frac{4}{8^4}-\frac{4}{8^3}< 0\)

Vậy A < B

c/ Đặt \(10^7=a\)thì ta có

\(A=\frac{a+5}{a-8};B=\frac{10a+6}{10a-7}\)

Giả sử A>B thì ta có

\(\frac{a+5}{a-8}>\frac{10a+6}{10a-7}\)

\(\Leftrightarrow10a^2+43a-35>10a^2-574a-348\)

\(\Leftrightarrow617a+313>0\)(đúng)

Vậy A>B

c/ Đặt \(10^{1991}=a\)thì ta có

\(A=\frac{10a+1}{a+1};B=\frac{100a+1}{10a+1}\)

Giả sử A>B thì ta có

\(\frac{10a+1}{a+1}>\frac{100a+1}{10a+1}\)

\(\Leftrightarrow\left(10a+1\right)^2>\left(100a+1\right)\left(a+1\right)\)

\(\Leftrightarrow-81a>0\)(sai)

Vậy A < B

a/ Thì quy đồng là ra nhé

a,b,c,d giống nhau cùng nhân A và B với 1 số nào đấy tách ra r` so sạmh

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