Ta có: \(\frac{-15}{31}>\frac{-15.5}{31}=-\frac12\)

\(\frac{-27}{53}<\frac{-26.5}{53}=-\frac12\)

Do đó: \(-\frac{27}{53}<-\frac{15}{31}<0\) (1)

Ta có: \(\frac{266}{281}=\frac{266}{281};\frac{1}{173}=\frac{1\cdot266}{173\cdot266}=\frac{266}{46018}\) ;

\(\frac{2}{347}=\frac{2\cdot133}{347\cdot133}=\frac{266}{46151}\) ; \(\frac{133}{141}=\frac{266}{282}\)

mà \(\frac{266}{46151}<\frac{266}{46018}<\frac{266}{281}<\frac{266}{282}\)

nên 0<\(\frac{2}{347}<\frac{1}{173}<\frac{266}{281}<\frac{133}{141}\) <1 (2)

Ta có: \(\frac{2015}{2014}>\frac{2014}{2014}\)

=>\(1<\frac{2015}{2014}\) (3)

Từ (1),(2),(3) suy ra \(-\frac{27}{53}<-\frac{15}{31}<\frac{2}{347}<\frac{1}{173}<\frac{266}{281}<\frac{133}{141}<\frac{2015}{2014}\)

\(\frac{163}{32};\frac{158}{31};\frac{141}{34};4\frac{3}{7}\)

a) \(\frac{7}{15};\frac{3}{10};0;-\frac{3}{4};-\frac{5}{6}\)

b) 

1) \(-\frac{7}{5};-\frac{7}{9};0;\frac{4}{5};\frac{9}{11};\frac{3}{2}\)

2) \(-\frac{25}{26};-\frac{18}{19};-\frac{11}{12};-\frac{4}{5};-\frac{3}{4}\)

sắp xếp theo thứ tự tăng dần là:

\(\Rightarrow-\frac{2}{15};-\frac{1}{10};\frac{1}{6};\frac{1}{5};\frac{4}{15};\frac{1}{3}\)

mình nghĩ là ta nên quy đồng trước

-2/15;-1/10;1/6;1/5;4/15,1/3;-2/-5

Vậy...

trả lời giúp mình nha! mình sẽ cho  ^^

11/14   12/13     15/15    33/32    34/31

lấy máy tính mà sắp

A) \(\frac{17}{120}\) ; \(\frac{11}{72}\) ; \(\frac{7}{28}\) 

B) \(\frac{-31}{49}\) ; \(\frac{-62}{97}\) ; \(\frac{-63}{97}\) \(\frac{-93}{140}\) 

17/120 ;11/72 ; 7/28

-93/140 ; -63/97 ; -62/97 ; -31/49