a) \(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{1.1.5}=\frac{18}{5}\)

b) \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.1.11.1}{1.5.7.1}=\frac{22}{35}\)

a) \(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}\)

b) \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}\)

c) \(\frac{121.75.130.69}{39.60.11.198}=\frac{11^2.3.5^2.2.5.13.23.3}{13.3.2^3.3.5.11.11.3^2.2}\)

\(=\frac{11^2.3^2.5^3.2.13.23}{13.3^4.2^4.5.11^2}=\frac{5^2.23}{3^2.2^3}\)

a,\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.2.3^2.3^2}{2^2.3^2.5}\)\(=\frac{2.3^2}{5}\)

b,\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^2.11.11.7}{2^3.5^2.5.7.7.11}=\frac{2.11}{5.7}\)

\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)

còn câu b cậu ạ

a. \(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2^2.3^2.2.3^2}{2^2.3^2.5}=\frac{2.9}{5}=\frac{18}{5}\)

b. \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.5^2.7.11.2.11}{2^3.5^2.7.11.5.7}=\frac{2.11}{5.7}=\frac{22}{35}\)

7290 câu b tẹo nữa tính tiếp

a. 8

b.8

c.5

làm cả bài làm nha bạn

Câu a:

(7\(^{2017}\) - 7\(^{2015}\)) ⋮ (7\(^{2014}\).7)

= 7\(^{2015}\).(7\(^2\) - 1) ⋮ 7\(^{2015}\)

= (7\(^{2015}\) : 7\(^{2015}\)).(49 - 1)

= 1.48

= 48

Câu b:

(2\(^{13}\) + 2\(^5\)) : (2\(^{10}\) + 2\(^2\))

= 2\(^5.\)(2\(^8\) + 1):[2\(^2\).(2\(^8\) + 1)]

= (2\(^5:2^2\)).[(\(2^8+1):\left(2^8+1\right)\)]

= 2\(^3\).1

= 8