a)   ( 2x + 3)^2 = 121

        2x + 3^2   = 121

         2x + 9      = 121

                 2x    = 121 - 9

                  2x   =   112

                     x  =  112 : 2

                      x = 56

Mấy câu sau tự làm nhé bạn 

a) (2x + 3)² = 121

    (2x + 3)² = 11²

^=>   2x + 3 = 11

     2x       = 11 - 3

     2x       = 8

       x      = 8 : 2

       x       = 4

b) (75 - 3x)³ = 27

    ( 75 - 3x)³ = 3³

=> 75 - 3x     = 3

            3x     = 75- 3

            3x     =  72

              x     = 72 : 3

              x      = 24

Câu b:

B = (3\(^{10}\).11 + 3\(^{10}\).5) : (3\(^9\).2\(^4\))

B = 3\(^{10}\).(11 + 5): (3\(^9\).2\(^4\))

B = 3\(^{10}\).16:(3\(^9\).2\(^4\))

B = (3\(^{10}\) : 3\(^9\)).(16 : 2\(^4\))

B = 3.1

B = 3

Câu c:

C = (2\(^{10}\).13 + 2\(^{10}\).65) : (2\(^8\).104)

C = 2\(^{10}\).(13 + 65):(2\(^8\).104)

C = 2\(^{10}\).78 : (2\(^8\).104)

C = (2\(^{10}\) : 2\(^8\)).(78 : 104)

C = 2\(^2\).\(\frac34\)

C = 3

a/ \(9^{27}=\left(3^2\right)^{27}=3^{54}\) và \(81^{13}=\left(3^4\right)^{13}=3^{52}\Rightarrow3^{54}>3^{52}\Rightarrow9^{27}>81^{13}\)

b/ \(5^{14}=\left(5^2\right)^7=25^7< 27^7\)

d/ \(2^{300}=\left(2^3\right)^{100}=8^{100}\) và \(3^{200}=\left(3^2\right)^{100}=9^{100}\Rightarrow8^{100}< 9^{100}\Rightarrow2^{300}< 3^{200}\)

f/ \(3^{450}=\left(3^3\right)^{150}=27^{150}\) và \(5^{300}=\left(5^2\right)^{150}=25^{150}\Rightarrow27^{150}>25^{150}\Rightarrow3^{450}>5^{300}\)

c/ \(10^{30}=\left(10^3\right)^{10}=1000^{10}\) và \(2^{100}=\left(2^{10}\right)^{10}=1024^{10}\Rightarrow1000^{10}< 1024^{10}\Rightarrow10^{30}< 2^{100}\)

a.

A = 72^3.54^2/108^4

A = (72.54:108)^2:108^2.72

A = 36^2:108^2.72

A = (36:108)^2.72

A = (1/3)^2.72

A = 72/9

A = 8

B = \(\frac{3^{10}.11+3^{10}.5}{3^9.2^4}\)

B = \(\frac{3^{10}.\left(11+5\right)}{3^9.2^4}\)

B = \(\frac{3^{10}.16}{3^9.16}\)

B = 3

cực dễ

ngon mà làm con.........................................................................................

e, \(E=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{2^{12}.3^{12}}\)

\(=\dfrac{3^4.3^{10}}{3^{12}}=3^2=9\)

f, \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}=\dfrac{2^5.\left(2^8+1\right)}{2^2.\left(2^8+1\right)}=2^3=8\)

g, \(G=\dfrac{21^2.141.125}{35^{5.6}}=\dfrac{3^2.7^2.47.3.5^3}{5^{30}.7^{30}}\)

\(=\dfrac{3^3.47}{5^{27}.7^{28}}\)(bạn xem lại đề nha)

Các câu còn lại làm tương tự! Chúc bạn học tốt!!!

g , bn chép sai đề òi kìa'