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a,\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{2.9}{5}=\frac{18}{5}\)
b, \(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)
c,\(\frac{1998.1990+3978}{1992.1991-3984}=\frac{18.111.1990+18.221}{24.83.1991-166.24}\)
\(=\frac{18.\left(111.1990+221\right)}{24.\left(83.1991-166\right)}\)
\(=\frac{3.221111}{4.165087}=\frac{221111}{4.55029}=\frac{221111}{220116}\)
\(\)
A = ( 71 + x ) - ( -24 - x ) + ( -35 - x )
= 71 + x - ( -24 ) + x + ( -35 ) + x
= 71 - ( -24 ) + ( -35 ) + x . 3
= 60 + 3x
= 3 ( 20 + x )
B = x - 34 - [ ( 15 + x ) - ( 23 - x ) ]
= x - 34 - [ 15 + x - 23 + x ]
= x - 34 - ( 15 - 23 ) - 2x
= x - 34 - ( -8 ) - 2x
= x - 26 - 2x
= ( -x ) - 26
C ) tương tự
\(-\frac{5}{10}=-\frac{1}{2}\)
\(\frac{18}{33}=\frac{6}{11}\)
\(\frac{19}{57}\)
\(\frac{-36}{-12}=\frac{3}{2}\)
MK lm bài 1:
\(\left(a-b\right)\left(a+b\right)=a^2+ab-ab-b^2=a^2-b^2\)
Bài 1:
\(\left(a-b\right)\left(a+b\right)=a^2+ab-ab-b^2\)
\(=a^2-b^2\)
a: \(=\dfrac{-40}{250}=\dfrac{-4}{25}\)
b: \(=\dfrac{-15}{20}\cdot\dfrac{7}{21}\cdot\dfrac{10}{14}=\dfrac{-3}{4}\cdot\dfrac{1}{2}\cdot\dfrac{10}{21}=\dfrac{-30}{8\cdot21}=\dfrac{-5}{28}\)