\(\frac{1}{2}+-\frac{1}{5}+-\frac{5}{7}+\frac{1}{6}-\frac{3}{35}+\frac{1}{3}+\frac{1}{41}=\frac{1}{41}\)

1/41 giai ra dai nam cu rut gon roi quy dong

Mình chỉ làm được phần b thôi nhé ! Bạn thông cảm

\(25< 3^n< 250\)

Ta có :

\(3^3\le3^n\le3^5\)

\(\Rightarrow3\le n\le5\)

\(\Rightarrow n=\left\{3;4;5\right\}\)

Vậy \(n=\left\{3;4;5\right\}\)

• (1 +1 +1)! = 6
• 2X2+ 2 = 6
• 3x3 -.3 = 6
• \(\sqrt{4}+\sqrt{4}+\sqrt{4}\)= 6
• 5+( 5: 5 )= 6
• 7 -(7:7 )= 6
• \(\sqrt{\left(8-8\right)+8}!\)= 6
• \(\left(9-9\right)+\sqrt{9}!\)= 6
• \(\sqrt{10-\left(10:10\right)}!\) = 6

thanks bn nha!

$B=\dfrac{4^5\cdot10\cdot5^6+25^5\cdot2^8}{2^8\cdot5^4+5^7\cdot2^5}$

$=\dfrac{2^{10}\cdot2\cdot5\cdot5^6+5^{10}\cdot2^8}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^{11}\cdot5^7+2^8\cdot5^{10}}{2^8\cdot5^4+2^5\cdot5^7}$

$=\dfrac{2^8\cdot5^7(2^3+5^3)}{2^5\cdot5^4(2^3+5^3)}$

$=2^{8-5}\cdot5^{7-4}$

$=2^3\cdot5^3$

$=8\cdot125$

$=1000.$

1)x=10

2)x=58

3)x=3

4)x=53

t minh nhe

a;1

b;0

c;8

cảm ơn nhé

co ai giai dc ko cau 60 % .....

$\textbf{Ta có:}$

$A=\dfrac{-5^2-5\cdot3^2}{5^3+5^2\cdot3^2}$

$=\dfrac{-25-45}{125+225}$

$=\dfrac{-70}{350}$

$=-\dfrac15.$

Và

$B=\dfrac{2^{12}\cdot3^{10}+6^9\cdot120}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}$

$=\dfrac{2^{12}3^{10}+2^{12}3^{10}\cdot5}{2^{11}3^{11}(2\cdot3-1)}$

$=\dfrac{2^{12}3^{10}(1+5)}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^{12}3^{10}\cdot6}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^2}{5}$

$=\dfrac45.$

=> $M=B-A$$=\dfrac45-\left(-\dfrac15\right)$

$=\dfrac55$$=1.$