\(\frac{\left(-2\right)^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot2^4\cdot5^3\cdot14}\)

\(=\frac{2^2\cdot\left(-2\right)\cdot3^3\cdot5^3\cdot7\cdot2^3}{3\cdot2^4\cdot5^3\cdot7\cdot2}=\frac{\left(-2\right)\cdot3^2}{1}=-18\)

Câu a:

\(\frac{2^{12}.3^5-4^6.9^2}{12^6+8^4.3^5}\)

= \(\frac{2^{12}.3^5-2^{12.3^6}}{2^{12}.3^6+2^{12}.3^5}\)

= \(\frac{2^{12}.3^4.\left(3-1\right)}{2^{12}.3^5.\left(3+1\right)}\)

= \(\frac{2}{3.4}\)

= \(\frac16\)

Câu b:

\(\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)

= \(\frac{5^{10}.7^3-5^{10}.7^4}{5^9.7^3+5^9.2^3.7^3}\)

= \(\frac{5^{10}.7^3.\left(1-7\right)}{5^9.7^3.\left(1+8\right)}\)

= \(\frac{5.\left(-6\right)}{9}\)

=- 10/3

b1 -10/14

b2 -4/5

b3 

a 2/9-7/8.x=1/3

  7/8.x=2/9-1/3=-1/9

  x=-1/9:-7/8=8/63

b 23/7.x-1/8=11/4

23/7.x=11/4+1/8=23/8

x=23/8:23/7=7/8

b4 

Quyển truyện cs số trang:

36:(1−1/4−9/20)=120(trang)

đáp án bằng 120 trang

các bạn ơi giúp mình với mình cần gấp

\(\frac{\left(2^{17}+5^{17}\right)\left(3^{14}-5^{12}\right)\left(2^4-4^2\right)}{15^2+5^3+67^7}=\frac{\left(2^{17}+5^{17}\right)\left(3^{14}-5^{12}\right).0}{15^2+5^3+67^7}=0\)