\(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8=\left(\dfrac{1}{7}\right)^7\times2^{16}\)

\(\left(-\dfrac{1}{7}\right)^4\times125\times5=\left(-\dfrac{1}{7}\right)^4\times5^3\times5=\left(-\dfrac{1}{7}\right)^4\times5^4\)

\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:2^3:2^{-4}=2^0\)

\(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^3\times7^3=1^3\)
 

6, \(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4\)

7,\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8\)

8,\(\left(-\dfrac{1}{7}\right) ^4\times125\times5=\left(\dfrac{1}{7}\right)^4\times5^3\times5\)

9,\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:\left[2^3\times\left(\dfrac{1}{2}\right)^4\right]\)

10, \(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times7^2\)

Câu 1:

16 - 18|x| = - 8 - 14|x|

18|x| - 14|x| = 16 + 8

4|x| = 24

|x| = 24 : 4

|x| = 6

x = - 6 hoăc x = 6

Vậy x ∈ {-6; 6}

e) 15-3|4x +2| = 3

3|4x + 2| = 15 - 3

3|4x + 2| = 12

|4x + 2| = 12 : 3

|4x + 2| = 4

4x + 2 = -4 hoặc 4x + 2 = 4

Th1: 4x + 2 = - 4

4x = - 4 - 2

4x = - 6

x = - 6/4

x = - 3/2

Th2: 4x + 2 = 4

4x = 4 - 2

4x = 2

x = 2/4

x = 1/2

Vậy x ∈ {- 3/2; 1/2}

uk

Câu 1:

16 - 18|x| = - 8 - 14|x|

18|x| - 14|x| = 16 + 8

4|x| = 24

|x| = 24 : 4

|x| = 6

x = - 6 hoăc x = 6

Vậy x ∈ {-6; 6}

a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)

=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)

=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)

b) \(3x^2-2=72\)=> 3x² = 74 => x² = 74/3 => x không thỏa mãn

c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)

=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)

=> \(\left(19x+50\right):14=9\)

=> \(19x+50=126\)

=> \(19x=76\)

=> x = 4

d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)

=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)

=> \(x\left(2+4+8+16+32\right)=343\)

=> x . 62 = 343

=> x = 343/62

a,16-18/x/=-8-14/x/

- 14|x| + 18|x| = 16 + 8

4|x| = 24

|x| = 24 : 4

|x| = 6

x = - 6 hoặc x = 6

Vậy x ∈ {-6; 6}

b,5/x/+7(2/x/-3)=4.(/x/-4)+25

5|x| + 14|x| - 21 = 4|x| - 16 + 25

19|x| = 4|x| - 16 + 25 + 21

19|x| - 4|x| = - 16 + 25 + 21

5|x| = 9 + 21

5|x| = 30

|x| = 30 : 5

|x| = 6

x = - 6 hoặc x = 6

Vậy x ∈ {-6; 6}

thu gọn 7^3*7^5

cặk cặk

a/ x-2+7=-27

x-2=-34

x=-32

b/ Đề bị điên ak?

c/ -2x=2

x=-1

d/ ko hỉu đề

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