Ta có: \(30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3\)

\(=2\cdot3\cdot5\cdot2^8\cdot5^8\cdot5^4-5^{12}\cdot2^8\cdot3\)

\(=2^9\cdot3\cdot5^{13}-2^8\cdot3\cdot5^{12}=2^8\cdot3\cdot5^{12}\left(2\cdot5-1\right)=2^8\cdot3^3\cdot5^{12}\)

\(75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2\)

\(=\left(5^2\cdot3\right)^3\cdot\left(2^2\cdot5\right)^4+3^3\cdot5^{10}\cdot2^{10}\)

\(=5^6\cdot3^3\cdot2^8\cdot5^4+3^3\cdot5^{10}\cdot2^{10}=3^3\cdot2^8\cdot5^{10}\left(1+5^2\right)=3^3\cdot2^9\cdot5^{10}\cdot13\)

Ta có: \(\frac{30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3}{75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2}\)

\(=\frac{2^8\cdot3^3\cdot5^{12}}{3^3\cdot2^9\cdot5^{10}\cdot13}=\frac12\cdot\frac{5^2}{13}=\frac12\cdot\frac{25}{13}=\frac{25}{26}\)

a.

\(\frac{11^4\times6-11^5}{11^4-11^5}=\frac{11^4\times\left(6-11\right)}{11^4\times\left(1-11\right)}=\frac{-5}{-10}=\frac{1}{2}\)

b.

\(\frac{9^8\times3-3^{18}}{9^8\times5+9^8\times7}=\frac{9^8\times3-\left(3^2\right)^9}{9^8\times\left(5+7\right)}=\frac{9^8\times3-9^9}{9^8\times12}=\frac{9^8\times\left(3-9\right)}{9^8\times12}=-\frac{6}{12}=-\frac{1}{2}\)

c.

\(\frac{10^5-10^5\times3}{10^5\times11}=\frac{10^5\times\left(1-3\right)}{10^5\times11}=-\frac{2}{11}\)

Chúc bạn học tốt

thanks bn

=-1

=2/5

=38/43

= 3/2

các bạn đâu hết rồi, làm đi để sáng mai mình còn nộp!

\(\frac{2^6.3.5^3.3.2.7}{2^4.3.5^3.6.7}=\frac{2^2}{1}=4\)

mik cần gấp ak

a) \(\frac{3\cdot5\cdot7}{14\cdot55}=\frac{3\cdot5\cdot7}{2\cdot7\cdot11\cdot5}=\frac{3}{2\cdot11}=\frac{3}{22}\)

b) \(\frac{2^7\cdot3^4}{3^6\cdot2^5}=\frac{2^2\cdot2^5\cdot3^4}{3^2\cdot3^4\cdot2^5}=\frac{2^2}{3^2}=\frac{4}{9}\)

c) \(\frac{7\cdot9-7\cdot4}{14\cdot11-14}=\frac{7\left(9-4\right)}{14\cdot\left(11-1\right)}=\frac{7\cdot5}{14\cdot10}=\frac{7\cdot5}{2\cdot7\cdot2\cdot5}=\frac{1}{2\cdot2}=\frac{1}{4}\)