a/\(\frac{2^3\cdot3^4}{2^2\cdot3^2\cdot5}=\frac{18}{5}\)\(\frac{2^4\cdot5^2\cdot11^2\cdot7}{2^3\cdot5^3\cdot7^2\cdot11}=\frac{2\cdot11}{5\cdot7}=\frac{22}{35}\)

b/\(\frac{121\cdot75\cdot130\cdot169}{39\cdot60\cdot11\cdot198}=\frac{11^2\cdot5^3\cdot13^3\cdot2\cdot3}{2^3\cdot3^4\cdot5\cdot11^2\cdot13}=\frac{5^2\cdot13^2}{2^2\cdot3^3}=\frac{4225}{108}\)

c/\(\frac{1998\cdot1990+3978}{1992\cdot1991-3984}=\frac{2^2\cdot3^3\cdot37\cdot5\cdot199+2\cdot3^2\cdot13\cdot17}{2^3\cdot3\cdot83\cdot11\cdot181-2^4\cdot3\cdot83}=\frac{2\cdot3^2\cdot11\cdot20101}{2^3\cdot3^3\cdot13\cdot17\cdot83}=\frac{11\cdot20101}{2^2\cdot3\cdot13\cdot17\cdot83}\)

b: \(B=18\cdot3+16\cdot81\cdot79-8\cdot5\)

=102398

Ta có: \(30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3\)

\(=2\cdot3\cdot5\cdot2^8\cdot5^8\cdot5^4-5^{12}\cdot2^8\cdot3\)

\(=2^9\cdot3\cdot5^{13}-2^8\cdot3\cdot5^{12}=2^8\cdot3\cdot5^{12}\left(2\cdot5-1\right)=2^8\cdot3^3\cdot5^{12}\)

\(75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2\)

\(=\left(5^2\cdot3\right)^3\cdot\left(2^2\cdot5\right)^4+3^3\cdot5^{10}\cdot2^{10}\)

\(=5^6\cdot3^3\cdot2^8\cdot5^4+3^3\cdot5^{10}\cdot2^{10}=3^3\cdot2^8\cdot5^{10}\left(1+5^2\right)=3^3\cdot2^9\cdot5^{10}\cdot13\)

Ta có: \(\frac{30\cdot10^8\cdot5^4-25^6\cdot16^2\cdot3}{75^3\cdot20^4+3^3\cdot5^{10}\cdot32^2}\)

\(=\frac{2^8\cdot3^3\cdot5^{12}}{3^3\cdot2^9\cdot5^{10}\cdot13}=\frac12\cdot\frac{5^2}{13}=\frac12\cdot\frac{25}{13}=\frac{25}{26}\)

ê ku dạng nào z

tui cg l 6

\(\frac{\left(-2\right)^3.3^3.5^3.7.8}{3.5^3.2^4.42}\)

\(=\frac{-8.27.125.7.8}{3.125.16.42}\)

\(=\frac{-8.3.9.125.7.8}{3.125.8.2.7.6}\)

\(=\frac{-72}{12}\)

\(=-6\)

a) \(3.5^2-27:3^2-5^2.4-18:3^2\)

\(=3.\left(5^2-5^2\right).27:\left(3^2-3^2\right)\)

\(=15.0.27.0\)

\(=0.0=0\)

b) 

  2x-1 là bội của x+3

=> 2x-1 chia hết cho x+3

hay [2(x+3)-7] chia hết ho x+ 3

=> 7 chia hết cho x+ 3

x+3 εεƯ(7)={1,-1,7,-7}

x+3=1                     x+3=-1                        x+3=7                    x+3= -7

x    = 1-3                 x    = -1-3                    x    = 7-3                x    = -7-3

x    = -2                  x     =  -4                     x     =4                   x    = -10

Vậy x= -2, x=-4,x= 4, x= -10

c) \(205-\left[1200-\left(4^2-2.3\right)^3\right]:40\)

\(=205-\left[1200-16-6^3\right]:40\)

\(=205-\left[1200-10^3:40\right]\)

\(=205-1200-1000:40\)

\(=205-200:40\)

\(=205-5\)

\(=200\)

a.2/5

b.16/9<24/13             27/28<26/25