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\(\frac{8}{15}\)và \(\frac{6}{25}\)với mẫu số chung là 75
Ta thấy: \(75\div25=3\), \(75\div15=5\).
Ta có:
\(\frac{8}{15}=\frac{8\times5}{15\times5}=\frac{40}{75}\); \(\frac{6}{25}=\frac{6\times3}{25\times3}=\frac{18}{75}\).
Vậy: Quy đồng mẫu số của \(\frac{8}{15}\)và \(\frac{6}{25}\)được: \(\frac{40}{75}\)và \(\frac{18}{75}\).
bài3
1. \(\frac{4}{3}\)= \(\frac{4x4}{3x4}\)=\(\frac{20}{12}\)
\(\frac{3}{4}\)=\(\frac{3x3}{4x3}\)=\(\frac{9}{12}\)
2.\(\frac{5}{4}\)=\(\frac{5x6}{4x6}\)=\(\frac{30}{24}\)
\(\frac{5}{6}\)=\(\frac{5x4}{6x4}\)=\(\frac{20}{24}\)
3.\(\frac{3}{8}\)=\(\frac{3x6}{8x6}\)=\(\frac{18}{48}\)
\(\frac{1}{6}\)=\(\frac{1x6}{6x8}\)=\(\frac{6}{48}\)
4.\(\frac{2}{5}\)=\(\frac{2x7}{5x7}\)=\(\frac{14}{35}\)
\(\frac{4}{7}\)=\(\frac{4x5}{7x5}\)=\(\frac{20}{35}\)
Bài 3 :
a: \(MSC:12\\ \dfrac{4}{3}=\dfrac{4\times4}{3\times4}=\dfrac{16}{12};\dfrac{3}{4}=\dfrac{3\times3}{3\times4}=\dfrac{9}{12}\)
b: \(MSC:12\\ \dfrac{5}{4}=\dfrac{5\times3}{4\times3}=\dfrac{15}{12};\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
c:\(MSC:24\\ \dfrac{3}{8}=\dfrac{3\times3}{8\times3}=\dfrac{9}{24};\dfrac{1}{6}=\dfrac{1\times2}{6\times2}=\dfrac{2}{12}\)
d: \(MSC:35\\ \dfrac{2}{5}=\dfrac{2\times7}{5\times7}=\dfrac{14}{35};\dfrac{4}{7}=\dfrac{4\times5}{7\times5}=\dfrac{20}{35}\)
Bài 3:
a: 4/3=16/12
3/4=9/12
b: 5/4=30/24
5/6=20/24
c: 3/8=18/48
1/6=8/48
d: 2/5=14/35
4/7=20/35
Bài 4:
a: 7/12=28/48
5/48=5/48
b: 4/100=4/100
8/25=32/100
Bài 1:
a: Cách 1: \(\frac37=\frac{3\cdot9}{7\cdot9}=\frac{27}{63};\frac59=\frac{5\cdot7}{9\cdot7}=\frac{35}{63}\)
mà 27<35
nên \(\frac37<\frac59\)
Cách 2: Ta có: \(\frac37=\frac{3\cdot5}{7\cdot5}=\frac{15}{35}\)
\(\frac59=\frac{5\cdot3}{9\cdot3}=\frac{15}{27}\)
mà \(\frac{15}{35}<\frac{15}{27}\left(35>27\right)\)
nên \(\frac37<\frac59\)
b: Cách 1: \(\frac{6}{12}=\frac{6\cdot3}{12\cdot3}=\frac{18}{36};\frac49=\frac{4\cdot4}{9\cdot4}=\frac{16}{36}\)
mà 18>16
nên \(\frac{6}{12}>\frac49\)
Cách 2: \(\frac{6}{12}=\frac{6\cdot2}{12\cdot2}=\frac{12}{24};\frac49=\frac{4\cdot3}{9\cdot3}=\frac{12}{27}\)
mà \(\frac{12}{24}>\frac{12}{27}\left(24<27\right)\)
nên \(\frac{6}{12}>\frac49\)
c: Cách 1: \(\frac{15}{25}=\frac{15\cdot18}{25\cdot18}=\frac{270}{450};\frac{54}{90}=\frac{54\cdot5}{90\cdot5}=\frac{270}{450}\)
Do đó: \(\frac{15}{25}=\frac{54}{90}\)
Cách 2: \(\frac{15}{25}=\frac{15:5}{25:5}=\frac35;\frac{54}{90}=\frac{54:18}{90:18}=\frac35\)
do đó: \(\frac{15}{25}=\frac{54}{90}\)
d: Cách 1: \(\frac{25}{30}=\frac{25\cdot3}{30\cdot3}=\frac{75}{90};\frac{75}{28}=\frac{75\cdot1}{28\cdot1}=\frac{75}{28}\)
mà \(\frac{75}{90}<\frac{75}{28}\left(90>28\right)\)
nên \(\frac{25}{30}<\frac{75}{28}\)
Cách 2: \(\frac{25}{30}=\frac{25\cdot14}{30\cdot14}=\frac{350}{420}\)
\(\frac{75}{28}=\frac{75\cdot15}{28\cdot15}=\frac{1125}{420}\)
mà 350<1125
nên \(\frac{25}{30}<\frac{75}{28}\)
e: cách 1: \(\frac{27}{45}=\frac{27\cdot4}{45\cdot4}=\frac{108}{180};\frac{18}{36}=\frac{18\cdot5}{36\cdot5}=\frac{90}{180}\)
mà 108>90
nên \(\frac{27}{45}>\frac{18}{36}\)
Cách 2: \(\frac{27}{45}=\frac{27\cdot2}{45\cdot2}=\frac{54}{90}\)
\(\frac{18}{36}=\frac{18\cdot3}{36\cdot3}=\frac{54}{108}\)
mà \(\frac{54}{90}>\frac{54}{108}\left(90<108\right)\)
nên \(\frac{27}{45}>\frac{18}{36}\)
\(a.\dfrac{5}{10}=\dfrac{1}{2}=\dfrac{1\times3}{2\times3}=\dfrac{3}{6}\)
\(\dfrac{25}{75}=\dfrac{1}{3}=\dfrac{1\times2}{3\times2}=\dfrac{2}{6}\)
\(b.\dfrac{42}{56}=\dfrac{3}{4}=\dfrac{3\times2}{4\times2}=\dfrac{6}{8}\)
\(\dfrac{18}{48}=\dfrac{3}{8}\)
\(c.\dfrac{27}{81}=\dfrac{1}{3}=\dfrac{1\times4}{3\times4}=\dfrac{4}{12}\)
\(\dfrac{57}{76}=\dfrac{3}{4}=\dfrac{3\times3}{4\times3}=\dfrac{9}{12}\)
\(\dfrac{35}{84}=\dfrac{5}{12}\)
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MC : \(75\)
Ta có : \(\frac{4}{25}=\frac{4.3}{25.3}=\frac{12}{75}\)
Vậy quy đồng 2 phân số \(\frac{4}{25}\), \(\frac{3}{75}\) ta được : \(\frac{12}{75}\)và \(\frac{3}{75}\)