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\(=x+10\sqrt{x}+25-20=\left(\sqrt{x}+5\right)^2-\left(2\sqrt{5}\right)^2\\ =\left(\sqrt{x}+5-2\sqrt{5}\right)\left(\sqrt{x}+5+2\sqrt{5}\right)\)
b, <=>(4x)3+13
<=> (4x+1)( 16x2-4x+1)
c, <=> (x.y2.z3)3-53
<=> (xy2z3-5)( x2y4z6+5xy2z3+25)
d, <=> (3x2)3-(2x)3
<=> (3x2-2x)(9x4+6x3+4x2)
d, (x3)2- (y3)2
= (x3+y3)(x3-y3)
\(5-7x^2=\left(\sqrt{5}\right)^2-\left(x\sqrt{7}\right)^2\)
\(=\left(\sqrt{5}-x\sqrt{7}\right)\left(\sqrt{5}+x\sqrt{7}\right)\)
\(3+4x=\left(\sqrt{3}\right)^2-\left(2\sqrt{x}\right)^2\) ( do x<0 )
\(=\left(\sqrt{3}-2\sqrt{x}\right)\left(3+2\sqrt{x}\right)\)
a: \(x^4-6x^2+8\)
\(=x^4-4x^2-2x^2+8\)
\(=\left(x^2-2\right)\left(x^2-4\right)=\left(x^2-2\right)\left(x-2\right)\left(x+2\right)\)
b: \(x^4-5x^2-14\)
\(=x^4-7x^2+2x^2-14\)
\(=x^2\left(x^2-7\right)+2\left(x^2-7\right)=\left(x^2-7\right)\left(x^2+2\right)\)
c: \(4x^4-7x^2+3\)
\(=4x^4-4x^2-3x^2+3\)
\(=\left(x^2-1\right)\left(4x^2-3\right)=\left(x-1\right)\left(x+1\right)\left(4x^2-3\right)\)
d: \(6x^4+7x^2+2\)
\(=6x^4+3x^2+4x^2+2\)
\(=\left(2x^2+1\right)\left(3x^2+2\right)\)
e: \(x^4-8x^2+15\)
\(=x^4-5x^2-3x^2+15\)
\(=x^2\left(x^2-5\right)-3\left(x^2-5\right)=\left(x^2-5\right)\cdot\left(x^2-3\right)\)
4x^2 - 7x -2 = 4x^2 - 8x + x - 2 = 4x(x - 2) + (x - 2) = (x -2)(4x + 1)
\(4x^2-7x-2=4x^2-8x+x-2=4x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(4x+1\right)\)
4x2-7x-2
=4x2+x-8x-2
=x(4x+1)-2(4x+1)
=(x-2)(4x+1)