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a: =(2x-3y)^2-4(2x-3y)
=(2x-3y)(2x-3y-4)
b: =3x^2+21x-x-7
=(x+7)(3x-1)
c: =(3x-1)^4+2(3x-1)^2+1
=[(3x-1)^2+1]^2
d: =2x^3-2x^2-x^2+x+x-1
=(x-1)(2x^2-x+1)
Bài 1:
\(=\left(3x-1\right)^2-9y^2\)
=(3x-1-3y)(3x-1+3y)
=(3x−1)2−9y2=(3x−1)2−9y2
=(3x-1-3y)(3x-1+3y)
Tham khảo ạ
4x^2+2xy-18xy-9y^2
=2x(2x+y)-9y(2x+y)
=(2x-9y)(2x+y)
Sorry bài trên mình làm sai
4x2 - 9y2 + 4x - 6y
= (2x - 3y)(2x + 3y) + 2(2x - 3y)
= (2x - 3y)(2x + 3y + 2)
\(4x^2-9y^2+4x-6y\)
\(=\left(4x^2+4x+1\right)-\left(9y^2+6y+1\right)\)
\(=\left(2x+1\right)^2-\left(3y+1\right)^2\)
\(=\left(2x+1-3y-1\right)\left(2x+1+3y+1\right)\)
\(=\left(2x-3y\right)\left(2x+3y+2\right)\)
\(x^4+6x^3+13x^2+12x+4\)
\(=x^4+x^3+5x^3+5x^2+8x^2+8x+4x+4\)
\(=x^3\left(x+1\right)+5x^2\left(x+1\right)+8x\left(x+1\right)+4\left(x+1\right)\)
\(=\left(x+1\right)\left(x^3+5x^2+8x+4\right)\)
\(=\left(x+1\right)\left(x^3+x^2+4x^2+4x+4x+4\right)\)
\(=\left(x+1\right)\left[x^2\left(x+1\right)+4x\left(x+1\right)+4\left(x+1\right)\right]\)
\(=\left(x+1\right)^2\left(x+2\right)^2\)
x2 + 4x + y - 9y2
<=> x(x + 4) + y(1 + 9y)
<=> (x + y)(x + 4 + 1 + 9y)
<=> (x + y)(x + 9y + 5)
bí rồi
\(a,3x^3-6x^2+3x\)
\(=3x\left(x^2-2x+1\right)\)
\(=3x\left(x-1\right)^2\)
\(b,16x^2y-4xy^2-4x^3\)
\(=-4x\left(x^2-4xy+4y^2-3y^2\right)\)
\(=-4x\left(x-2y+y\sqrt{3}\right)\left(x-2y-y\sqrt{3}\right)\)
\(4x^2-9y^2+6x-9y\)
\(=4x^2-9y^2+2x+4x-9y\)
\(=\left(4x^2+4x\right)-\left(9y^2+9y\right)+2x\)
\(=4x\left(x+1\right)-9y\left(y+1\right)+2x\)
\(=\left(x+1\right)\left(4x-9y\right)+2x\)
\(4x^2-9y^2+4x-6y\)
\(=\left(2x\right)^2-\left(3y\right)^2+2\left(2x-3y\right)\)
\(=\left(2x-3y\right)\left(2x+3y\right)+2\left(2x-3y\right)\)
\(=\left(2x-3y\right)\left(2x+3y+2\right)\)