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\(a/\)
\(4x-4y+x^2-2xy+y^2\)
\(=\left(4x-4y\right)+\left(x^2-2xy+y^2\right)\)
\(=4\left(x-y\right)+\left(x-y\right)^2\)
\(=\left(x-y\right)\left(4+x-y\right)\)
\(b/\)
\(x^4-4x^3-8x^2+8x\)
\(=\left(x^4+8x\right)-\left(4x^3+8x^2\right)\)
\(=x\left(x^3+8\right)-4x^2\left(x+2\right)\)
\(=x\left(x+2\right)\left(x^2-2x+4\right)-4x^2\left(x+2\right)\)
\(=x\left(x+2\right)\left(x^2-2x+4-4x\right)\)
\(=x\left(x+2\right)\left(x^2-6x-4\right)\)
\(d/\)
\(x^4-x^2+2x-1\)
\(=x^4-\left(x-1\right)^2\)
\(=\left(x^2+x-1\right)\left(x^2-x+1\right)\)
\(e/\)(Xem lại đề)
\(x^4+x^3+x^2+2x+1\)
\(=\left(x^4+x^3\right)+\left(x^2+2x+1\right)\)
\(=x^3\left(x+1\right)+\left(x+1\right)^2\)
\(=\left(x+1\right)\left(x^3+x+1\right)\)
\(f/\)
\(x^3-4x^2+4x-1\)
\(=x\left(x^2-4x+4\right)-1^2\)
\(=x\left(x-2\right)^2-1\)
\(=[\sqrt{x}\left(x-2\right)]^2-1\)
\(=[\sqrt{x}\left(x-2\right)-1][\sqrt{x}\left(x-2\right)+1]\)
\(c/\)
\(x^3+x^2-4x-4\)
\(=\left(x^3-2x^2\right)+\left(3x^2-6x\right)+\left(2x-4\right)\)
\(=x^2\left(x-2\right)+3x\left(x-2\right)+2\left(x-2\right)\)
\(=\left(x-2\right)\left(x^2+3x+2\right)\)
\(=\left(x-2\right)[\left(x^2+x\right)+\left(2x+2\right)]\)
\(=\left(x-2\right)\left(x+1\right)\left(x+2\right)\)
a) 2x3 + 8x2 - 8x
= 2x(x2 + 4x - 4)
= 2x(x2 + 4x + 4 - 8)
= 2x[(x + 2)2 - 8]
= \(2x\left(x+2-\sqrt{8}\right)\left(x+2+\sqrt{8}\right)\)
b) a2 - b2 + 4a + 4b
= (a - b)(a + b) + 4(a + b)
= (a + b)(a - b + 4)
c) x2 - 2x - 3
= x2 + x - 3x - 3
= x(x + 1) - 3(x + 1)
= (x + 1)(x - 3)
d) x2 - 4x - 3
= x2 - 4x + 4 - 7
= (x + 2)2 - 7
= \(\left(x+2-\sqrt{7}\right)\left(x+2+\sqrt{7}\right)\)
a)x^2-(a+b)x+ab
= x^2 - ax - bx + ab
= (x^2 - ax) - (bx - ab)
= x(x-a) - b(x-a)
= (x-b)(x-a)
b)7x^3-3xyz-21x^2+9z
=
c)4x+4y-x^2(x+y)
= 4(x + y) - x^2(x+y)
= (4-x^2) (x+y)
= (2-x)(2+x)(x+y)
d) y^2+y-x^2+x
= (y^2 - x^2) + (x+y)
= (y-x)(y+x)+ (x+y)
= (y-x+1) (x+y)
e)4x^2-2x-y^2-y
= [(2x)^2 - y^2] - (2x +y)
= (2x-y)(2x+y) - (2x+y)
= (2x -y -1)(2x+y)
f)9x^2-25y^2-6x+10y
=
a 4x -4y +(x-y)^2
=4(x-y)+(x-y).(x-y)
=(x-y).(4+x-y)
c x^2(x+1)-4(x+1)
(x+1).(x^2-4)
d x^4-(x^2-2x+1)
=x^4-(x-1)^2
=x^2(x-x+1)(x-x-1)
MIK KO BIT DUNG HAY KO CON B THI MIK KO BIET LAM
Câu b dễ thôi
\(x^4-4x^3-8x^2+8x\)
\(=x\left(x^3-4x^2-8x+8\right)\)
\(=x\left(x+2\right)\left(x^2-6x+4\right)\)
Phân tích các đa thức sau thành nhân tử ... c) 6x(x+y)^2+3x^2y(x+y). 2: .... x3 - 5x + 8x - 4=x2 . x -5x + 8x -22 = (x2 - 22) . (x -5x + 8x )=(x-2) . (x+2) . 4x. x3 - 9x2 ..... Phân tích các đa thức sau thành nhân tử : a,x^3+5x^2+8x+4 b, x^3-9x^2+6x+16 .
\(a.=x^2\left(x-y\right)-25\left(x-y\right)\)
\(=\left(x-5\right)\left(x+5\right)\left(x-y\right)\)
\(b.=\left(b-a\right)\left(b+a\right)-4\left(b-a\right)\)
\(=\left(b+a-4\right)\left(b-a\right)\)
a ) x3 - x2y - 25x + 25y
= x2 . ( x - y ) - 25 . ( x - y )
= ( x - y )( x2 - 25 )
= ( x - y )( x - 5 )( x + 5 )
b ) b2 - 4b + 4a - a2
= ( b2 - a2 ) - ( 4b - 4a )
= ( b - a )( a + b ) - 4 . ( b - a )
= ( b - a )( a + b - 4 )
c ) x3 - 4x2 - 8x + 8
= ( x3 + 8 ) - ( 4x2 + 8x )
= ( x + 2 )( x2 - 2x + 4 ) - 4x . ( x + 2 )
= ( x + 2 )( x2 - 2x + 4 - 4x )
= ( x + 2 )( x2 - 6x + 4 )
a) \(x^3-x^2y-25x+25y\)
\(=x^2\left(x-y\right)-25\left(x-y\right)\)
\(=\left(x-y\right)\left(x^2-25\right)\)
\(=\left(x-y\right)\left(x-5\right)\left(x+5\right)\)
b) \(b^2-4b+4a-a^2\)
\(=\left(b^2-a^2\right)-\left(4b-4a\right)\)
\(=\left(b-a\right)\left(b+a\right)-4\left(b-a\right)\)
\(=\left(b-a\right)\left(b+a+4\right)\)
c) \(x^3-4x^2-8x+8\)
\(=\left(x^3+8\right)-\left(4x^2+8x\right)\)
\(=\left(x+2\right)\left(x^2-2x+4\right)-4x\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2-2x+4-4x\right)\)
\(=\left(x+2\right)\left(x^2-6x+4\right)\)
\(=\left(x+2\right)\left(x^2-2.x.3+9-9+4\right)\)
\(=\left(x+2\right)\left[\left(x-3\right)^2-5\right]\)
\(=\left(x+2\right)\left(x-3-\sqrt{5}\right)\left(x-3+\sqrt{5}\right)\)
d) \(x^2\left(x-1\right)-4x^2+8x-4\)
\(=x^3-5x^2+8x-4\)
\(=\left(x^3-4x^2+4x\right)-\left(x^2-4x+4\right)\)
\(=x\left(x^2-4x+4\right)-\left(x^2-4x+4\right)\)
\(=\left(x^2-4x+4\right)\left(x-1\right)\)
\(=\left(x-2\right)^2\left(x-1\right)\)
e) \(x^2-9xy+20y^2\)
ko phân tích được vì lớn hơn 0
f) \(x^2-x-12\)
\(=x^2-4x+3x-12\)
\(=x\left(x-4\right)+3\left(x-4\right)\)
\(=\left(x-4\right)\left(x+3\right)\)
a.=x^2 (x-y) -25(x-y)
=(x-y)(x^2-25)=(x-y)(x+5)(x-5)
b)=b^2 -4b+4a-a^2
=(b-a)(b+a) -4(b-a)
=(b-a)(b+a-4)
c)x^3-4x^2-8x+8
=(x^3+2x^2)-(6x^2+12x)+(4x+8)
=x^2(x+2)-6x(x+2)-4(x+2)
=(x+2)(x^2-6x-4)
=(x+2)[(x^2-6x+9)-13]
=(x+2)[(x-3)^2 -(căn 13)^2]
=(x+2)(x-3+căn 13)(x-3-căn 13)
Hoàng Nguyễn Văn
phần c làm theo bạn này nhé bài mình sai
Lê Tài Bảo Châu
câu e làm được nha
e) x^2-9xy+20y^2
=(x^2-4xy)-(5xy-20y^2)
=x(x-4y) - 5y(x-4y)
=(x-5y)(x-4y)
Hoàng Nguyễn Văn
ok thanks