\(x^2-y^2+6x+9=\left(x+3\right)^2-y^2=\left(x+3+y\right)\left(x+3-y\right)\)

\(x^3+3x^2-9x-27=\left(x-3\right)\left(x^2+3x+9\right)+3x\left(x-3\right)=\left(x-3\right)\left(x^2+6x+9\right)=\left(x-3\right)\left(x+3\right)^2\)

Bài giải:

a) x³ + 2x²y + xy²– 9x = x(x² +2xy + y² – 9)

= x[(x² + 2xy + y²) – 9]

= x[(x + y)² – 3²]

= x(x + y – 3)(x + y + 3)

b) 2x – 2y – x² + 2xy – y² = (2x – 2y) – (x² – 2xy + y²)

= 2(x – y) – (x – y)²

= (x – y)[2 – (x – y)]

= (x – y)(2 – x + y)

c) x⁴ – 2x² = x²(x² – (√2)²) = x²(x - √2)(x + √2).

a) x³ + 2x²y + xy²– 9x = x(x² +2xy + y² – 9)

= x[(x² + 2xy + y²) – 9]

= x[(x + y)² – 3²]

= x(x + y – 3)(x + y + 3)

b) 2x – 2y – x² + 2xy – y² = (2x – 2y) – (x² – 2xy + y²)

= 2(x – y) – (x – y)²

= (x – y)[2 – (x – y)]

= (x – y)(2 – x + y)

c) x⁴ – 2x² = x²(x² – (√2)²) = x²(x - √2)(x + √2).

\(x^2-4y^2+4y-1=x^2-\left(2y-1\right)^2=\left(x+2y-1\right)\left(x-2y+1\right)\)

\(x^4+3x^3-9x-9\)

\(=x^4-9+3x^3-9x\)

\(=\left(x^2-3\right)\left(x^2+3\right)+3x\left(x^2-3\right)\)

\(=\left(x^2-3\right)\left(x^2+3+3x\right)\)

a) bt \(=\left(x-8\right)\left(x^2-x-2\right)=\left(x-8\right)\left(x+1\right)\left(x-2\right)\)

kl: ...

b) \(=\left(x+2\right)\left(x^2-8x-15\right)=\left(x+2\right)\left(x-5\right)\left(x-3\right)\)

kl:....

a, \(x^3-9x^2+6x+16\)

\(=x^3-8x^2-x^2+8x-2x+16\)

\(=x^2\left(x-8\right)-x\left(x-8\right)-2\left(x-8\right)\)

\(=\left(x-8\right)\left(x^2-x-2\right)\)

\(=\left(x-8\right)\left(x^2-2x+x-2\right)\)

\(=\left(x-8\right)\left[x\left(x-2\right)+\left(x-2\right)\right]\)

\(=\left(x-8\right)\left(x-2\right)\left(x+1\right)\)

b, \(x^3-6x^2-x+30\)

\(=x^3-5x^2-x^2+5x-6x+30\)

\(=x^2\left(x-5\right)-x\left(x-5\right)-6\left(x-5\right)\)

\(=\left(x-5\right)\left(x^2-x-6\right)\)

\(=\left(x-5\right)\left(x^2-3x+2x-6\right)\)

\(=\left(x-5\right)\left[x\left(x-3\right)+2\left(x-3\right)\right]\)

\(=\left(x-5\right)\left(x-3\right)\left(x+2\right)\)

Chúc bạn học tốt!!!

\(a.\left(xy+yz\right)-\left(5x+5z\right)\)
\(=y\left(x+z\right)-5\left(x+z\right)\)
\(=\left(x+z\right)\left(y-5\right)\)
\(b.\left(x^2+2xy+y^2\right)-9x^2\)
\(=\left(x+y\right)^2-9x^2\)
\(=\left(x+y-3x\right).\left(x+y+3x\right)\)
\(=\left(y-2x\right).\left(y+4x\right)\)

a. Đề=\(y\left(x+z\right)-5\left(x+z\right)\)\(=\left(x+z\right)\left(y-5\right)\)

b. Đề=\(\left(x+y\right)^2-\left(3x\right)^2\)\(=\left(x+y-3x\right)\left(x+y+3x\right)\)\(=\left(y-2x\right)\left(y+4x\right)\)

g) x² - 2xy + y² - z²

= ( x - y )² - z²

= ( x - y + z ) ( x - y - z )

h) 9x²y² + 6xy² + y² - 1  

= ( 3xy + y )² - 1

= ( 3xy + y - 1 ) ( 3xy + y + 1 )

i ) x² - x - 2

= x² - 2x + x - 2 

= x ( x - 2 ) + ( x - 2 )

= ( x - 2 ) ( x + 1 ) 

a. 2x²-xy

= x(2x-y)

b. x²-xy-x+y

= (x²-xy)-(x+y)

=x(x-y)-(x-y)

=(x-y)(x-1)

\(a.=x^3+3x^2y+3x^2y+9xy^2+3xy^2+9y^3\)

    \(=x^2\left(x+3y\right)+3xy\left(x+3y\right)+3y^2\left(x+3y\right)\)

    \(=\left(x+3y\right)\left(x^2+3xy+3y^2\right).\)

\(b.=9x^3+3x^2y+9x^2y+3xy^2+3xy^2+y^3\)

    \(=3x^2\left(3x+y\right)+3xy\left(3x+y\right)+y^2\left(3x+y\right)\)

    \(=\left(3x^2+3xy+y^2\right)\left(3x+y\right)\).

Chắc chắn rồi! Bạn gửi biểu thức:

Mình sẽ giải thích rõ từng bước nhé.

🔹 1. Phân tích biểu thức

Biểu thức gồm 2 phần:

1. \(x^{2} \left(\right. x - y \left.\right)\): là phần đa thức bậc 3
2. \(\left(\right. y - 1 \left.\right)^{2}\): là hằng đẳng thức — bình phương một hiệu

🔹 2. Khai triển từng phần

✅ Phần 1:

✅ Phần 2:

🔹 3. Gộp lại toàn bộ biểu thức

✅ Kết quả cuối cùng:

Nếu bạn muốn rút gọn, phân tích thành nhân tử hoặc thay giá trị cụ thể cho \(x\) và \(y\), bạn có thể nói thêm để mình giúp tiếp nhé!

hẹ hẹ gpt

Câu 2 nha

\(a,x^4+2x^3+x^2\)

\(=x^2\left(x^2+2x+1\right)\)

\(=x^2\left(x+1\right)^2\)

\(c,x^2-x+3x^2y+3xy^2+y^3-y\)

\(=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x+y\right)\)

\(=\left(x+y\right)^3-\left(x+y\right)\)

\(=\left(x+y\right)\left(x^2+2xy+y^2-1\right)\)