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a) \(x-2\sqrt{x-1}-4=\left(x-1\right)-2\sqrt{x-1}+1-4\)
\(=\left(\sqrt{x-1}-1\right)^2-4=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(x-2\sqrt{x-6}-5-y^2=\left(x-6\right)-2\sqrt{x-6}+1-y^2\)
\(=\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-1+y\right)\left(\sqrt{x-6}-1-y\right)\)
c) \(x-2\sqrt{x-8}-7-a^2=\left(x-8\right)-2\sqrt{x-8}+1-a^2\)
\(=\left(\sqrt{x-8}-1\right)^2-a^2=\left(\sqrt{x-8}+a-1\right)\left(\sqrt{x-8}-a-1\right)\)
a) \(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c) \(\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a, \(x-\sqrt{x}\)= \(\sqrt{x}.\left(\sqrt{x}-1\right)\)
b, 3x+6\(\sqrt{x}\)= \(\sqrt{x}.\left(3\sqrt{x}+6\right)\)
c, x+2\(\sqrt{x}+1\)= \(\left(\sqrt{x}\right)^2+2\sqrt{x}+1=\left(\sqrt{x}+1\right)^2\)
d, \(3x-5\sqrt{x}+2=3x-3\sqrt{x}-2\sqrt{x}+2\)
=\(3\sqrt{x}.\left(\sqrt{x}-1\right)-2.\left(\sqrt{x}-1\right)\)
=\(\left(3\sqrt{x}-2\right).\left(\sqrt{x}-1\right)\)
a) 2a−4b=2(a−2b)2a−4b=2(a−2b)
c) 2ax−2ay+2a=2a(x−y+1)2ax−2ay+2a=2a(x−y+1)
e) 3xy(x−4)−9x(4−x)=3x(x−4)(y+3)3xy(x−4)−9x(4−x)=3x(x−4)(y+3)
b,d xem lại đề
úi sao bạn cũng là quản lý giống mình à, mình trả lời câu hỏi của bạn có được không nhỉ
\(A,ĐKXĐ:x;y\ge0\)
\(A=\sqrt{xy}-2\sqrt{y}-5\sqrt{x}+10\)
\(=\sqrt{y}\left(\sqrt{x}-2\right)-5\left(\sqrt{x}-2\right)\)
\(=\left(\sqrt{x}-2\right)\left(\sqrt{y}-5\right)\)
\(ĐKXĐ:x;y\ge0\)
\(B=a\sqrt{x}+b\sqrt{y}-\sqrt{xy}-ab\)
\(=\left(a\sqrt{x}-\sqrt{xy}\right)+\left(b\sqrt{y}-ab\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)+b\left(\sqrt{y}-a\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)
\(=\left(a-\sqrt{y}\right)\left(\sqrt{x}-b\right)\)
lll
a) (\(\sqrt{x}\)-1)(\(\sqrt{x}\)+7)
b) (\(\sqrt{x}\)-4)(\(\sqrt{x}\)-2)
c) (\(\sqrt{x}\)+1)(3\(\sqrt{x}\)+2)
a) x +6\(\sqrt{x}\) -7= x + 7\(\sqrt{x}\) -\(\sqrt{x}\) -7 = x(\(\sqrt{x}\)-1 )+ 7(\(\sqrt{x}\) -1 )=(\(\sqrt{x}\) -1 )(\(\sqrt{x}\) +7)
b) x -6\(\sqrt{x}\) +8= x - 4\(\sqrt{x}\) -2\(\sqrt{x}\) +8= \(\sqrt{x}\)(\(\sqrt{x}\)-2) -4(\(\sqrt{x}\)-2)= (\(\sqrt{x}\)-2)( \(\sqrt{x}\)-4)
c) 3x +5\(\sqrt{x}\) +2= 3x+3\(\sqrt{x}\) +2\(\sqrt{x}\) +2= 3\(\sqrt{x}\) (\(\sqrt{x}\) +1 ) +2( \(\sqrt{x}\) +1)=( \(\sqrt{x}\) +1)(3\(\sqrt{x}\) +2)
a/ \(\left(\sqrt{x}-7\right)\left(\sqrt{x}+1\right)\)
b/ \(\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c/ \(\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a) (\(\sqrt{x}-1\))(\(\sqrt{x}+7\))
b) (\(\sqrt{x}-4\))(\(\sqrt{x}-2\))
c) (\(\sqrt{x}+1\))(3\(\sqrt{x}+2\))
a) \(\left(\sqrt{x}+7\right)\left(\sqrt{x}-1\right)\)
b) \(\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c)\(\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)\)
a) \(\left(\sqrt{x}+7\right)\left(\sqrt{x}-1\right)\)
b) \(\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c) \(\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a) \(\left(\sqrt{x}+7\right)\left(\sqrt{x}-1\right)\)
b) \(\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c) \(\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a. \(x+6\sqrt{x}-7=\left(\sqrt{x^2}\right)+7\sqrt{x}-\sqrt{x}-7=\)\(\sqrt{x}\left(\sqrt{x}+7\right)-\left(\sqrt{x}+7\right)=\left(\sqrt{x}+7\right)\left(\sqrt{x}-1\right)\)
b. \(x-6\sqrt{x}+8=x-2\sqrt{x}-4\sqrt{x}+8=\sqrt{x}\left(\sqrt{x}-2\right)-4\left(\sqrt{x}-2\right)=\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c.\(3x+5\sqrt{x}+2=3x+3\sqrt{x}+2\sqrt{x}+2=3\sqrt{x}\left(\sqrt{x}+1\right)+2\left(\sqrt{x}+1\right)=\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a) \(x+6\sqrt{x}-7=\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b)\(x-6\sqrt{x}+8=\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c)\(3x+5\sqrt{x}+2=\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)\)
a)\(x+6\sqrt{x}-7=x+7\sqrt{x}-\sqrt{x}-7=\left(\sqrt{x}+7\right)\left(\sqrt{x}-1\right)\)
b)\(x-6\sqrt{x}+8=x-4\sqrt{x}-2\sqrt{x}+8=\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c)\(3x+5\sqrt{x}+2=3x+3\sqrt{x}+2\sqrt{x}+2=\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)\)
a) x+6\sqrt{x}-7=\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)x+6x−7=(x−1)(x+7)
b) x-6\sqrt{x}+8=\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)x−6x+8=(x−2)(x−4)
c) 3x+5\sqrt{x}+2=\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)3x+5x+2=(3x+2)(x+1)
a) \(\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b) \(\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c) \(\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a)\(\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b)\(\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c)
a) \(\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b) \(\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c) \(\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)\)
a) \(x+6\sqrt{x}-7=x-\sqrt{x}+7\sqrt{x}-7=\sqrt{x}\left(\sqrt{x}-1\right)+7\left(\sqrt{x}-1\right)=\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b) \(x-6\sqrt{x}+8=x-2\sqrt{x}-4\sqrt{x}+8=\sqrt{x}\left(\sqrt{x}-2\right)-4\left(\sqrt{x}-2\right)=\left(\sqrt{x}-2\right)\left(\sqrt{x}-4\right)\)
c) \(3x+5\sqrt{x}+2=3x+3\sqrt{x}+2\sqrt{x}+2=3\sqrt{x}\left(\sqrt{x}+1\right)+2\left(\sqrt{x}+1\right)=\left(\sqrt{x}+1\right)\left(3\sqrt{x}+2\right)\)
a) x+6√x-7
=x+7√x-√x-7
=(√x+7).(√x-1)
b) x-6√x+8
=x-4√x-2√x+8
=(√x-4).(√x-2)
c)3x+5√x+2
=3x+3√x+2√x+2√x+2
=(3√x+2).(√x+1)
a, \(x+6\sqrt{x}-7=\left(\sqrt{x}-1\right)\left(\sqrt{x}+7\right)\)
b, \(x-6\sqrt{x}+8=\left(\sqrt{x}-4\right)\left(\sqrt{x}-2\right)\)
c, \(3x+5\sqrt{x}+2=\left(3\sqrt{x}+2\right)\left(\sqrt{x}+1\right)\)
\(c.=3x+3\sqrt{X}+2\sqrt{X}+2\\ \\ =3\sqrt{X}\left(\sqrt{X}+1\right)+2\left(\sqrt{X}+1\right)\)\(a.=\left(\sqrt{x}+7\right)\left(\sqrt{X}-1\right)\)\(b.=\left(\sqrt{X}+4\right)\left(\sqrt{X}-2\right)\)
a)x+6\(\sqrt{x}\)-7=x+7\(\sqrt{x}\)-\(\sqrt{x}\)-7=(x-\(\sqrt{x}\))(7\(\sqrt{x}\)-7)=\(\sqrt{x}\)(\(\sqrt{x}\)-1)+7(\(\sqrt{x}\)-1)=(\(\sqrt{x}\)-1)(\(\sqrt{x}\)-7)
b)x-6\(\sqrt{x}\)+8=x-4\(\sqrt{x}\)-2\(\sqrt{x}\)+8=(x-2\(\sqrt{x}\))-(4\(\sqrt{x}\)-8)=\(\sqrt{x}\)(\(\sqrt{x}\)-2)-4(\(\sqrt{x}\)-2)=(\(\sqrt{x}\)-2)(\(\sqrt{x}\)-4)
c)3x+5\(\sqrt{x}\)+2=3x+2\(\sqrt{x}\)+3\(\sqrt{x}\)+2=(3x+3\(\sqrt{x}\))+(2x+2\(\sqrt{x}\))=3\(\sqrt{x}\)(\(\sqrt{x}\)+1)+2(\(\sqrt{x}\)+1)=(\(\sqrt{x}\)+1)(\(3\sqrt{x}\)+2)
a) x + 6\(\sqrt{x}\) - 7= (\(\sqrt{x}-1\))(\(\sqrt{x}+7\))
b) x - 6\(\sqrt{x}\) + 8=(\(\sqrt{x}-4\))(\(\sqrt{x}-2\))
c) 3x + 5\(\sqrt{x}\) + 2= (3\(\sqrt{x}\)+2)(\(\sqrt{x}+1\))