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a) 3x52+15x22-26:3
=3x25+15x4-26/3
=75+60-26/3
=135-26/3
=379/3
b) 53x2-100:4+23x5
=125x2-25+8x5
=250-25+40
=225+40
=265
\(\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)
Câu a:
(7\(^{2017}\) - 7\(^{2015}\)) ⋮ (7\(^{2014}\).7)
= 7\(^{2015}\).(7\(^2\) - 1) ⋮ 7\(^{2015}\)
= (7\(^{2015}\) : 7\(^{2015}\)).(49 - 1)
= 1.48
= 48
Câu b:
(2\(^{13}\) + 2\(^5\)) : (2\(^{10}\) + 2\(^2\))
= 2\(^5.\)(2\(^8\) + 1):[2\(^2\).(2\(^8\) + 1)]
= (2\(^5:2^2\)).[(\(2^8+1):\left(2^8+1\right)\)]
= 2\(^3\).1
= 8
\(5^{12}:5^8=5^4\)
\(7^9:7^6=7^3\)
\(5^5.5^3=5^8\)
\(4^5.2=2^{10}.2=2^{11}\)
P = \(\frac{5.3^{11}+4.3^{12}}{3^9.5^2-3^9.2^2}\)
= \(\frac{\left(5+4.3\right).3^{11}}{3^9.\left(5^2-2^2\right)}\)
=\(\frac{17.3^{11}}{3^9.21}\)
= \(\frac{17.3^2}{7.3}\)
= \(\frac{17.3}{7}=\frac{51}{7}\)