1) \(25+37-48-25-37=\left(25-25\right)+\left(37-37\right)-48=-48\)

2) \(37+35+36+37-14-15-16-17\)

\(=\left(37-17\right)+\left(35-15\right)+\left(36-16\right)+\left(37-14\right)\)

\(=20+20+20+23=83\)

a)=<

b)=-1/6<1/12

25³⁶<36²⁵

^{Chúc bn học tốt}

^k mk nha

36²⁵ = 6⁵⁰ = 7776¹⁰ > 78 125¹⁰= (5⁷)¹⁰= 5⁷⁰ > 5⁷²= 25³⁶.

tất nhiên là 36 ²⁵

36²⁵ = 6⁵⁰ = 7776¹⁰ < 78125¹⁰ = (5⁷)¹⁰ = 5⁷⁰ < 5⁷² = 25³⁶

a, \(125^{20}\)và \(25^{30}\)

ta có : \(125^{20}=\left(5^3\right)^{20}\)\(=5^{3.20}=5^{60}\)

\(25^{30}=\left(5^2\right)^{30}=5^{2.30}=5^{60}\)

Vì \(5^{60}=5^{60}\)nên => \(125^{20}=25^{30}\)

b ,\(49^{16}\)và \(343^{20}\)

ta có : \(49^{16}=\left(7^2\right)^{16}=7^{2.16}=7^{32}\)

\(343^{20}=\left(7^3\right)^{20}=7^{3.20}=7^{60}\)

Vì \(7^{32}< 7^{60}\)nên => \(49^{16}< 343^{20}\)

c, \(121^{15}\)và \(1331^{16}\)

ta có : \(121^{15}=\left(11^2\right)^{15}=11^{2.15}=11^{30}\)

\(1331^{16}=\left(11^3\right)^{16}=11^{3.16}=11^{48}\)

Vì \(11^{30}< 11^{48}\)nên => \(121^{15}< 1331^{16}\)

d, \(199^{20}\)và \(2003^{15}\)

ta có : \(199^{20}=199^{5.4}=\left(199^4\right)^5=1568239201^5\)

\(2003^{15}=2003^{3.5}=\left(2003^3\right)^5=8036054027^5\)

Vì \(1568239201^5< 8036054027^5\)nên => \(199^{20}< 2003^{15}\)

e, \(4^{25}\)và \(3^{30}\)

=> \(4^{25}< 3^{30}\)

f, \(36^{82}\)và \(49^{123}\)

=> \(36^{82}< 49^{123}\)

mình làm rồi đó . k mình đi

>

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