Câu hỏi của Khổng Thị Thanh Thanh

Question

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phạm khánh linh · Accepted Answer

a, x=132

b,x=10

bài 2:

a, 22/55+25/125+1020/5100

=2/5+1/5+1/5=4/5

b, 22/77+56/98+25/105

=2/7+4/7+5/21

=6/21+12/21+5/21=23/21

Câu trả lời:

a, x=132

b,x=10

bài 2:

a, 22/55+25/125+1020/5100

=2/5+1/5+1/5=4/5

b, 22/77+56/98+25/105

=2/7+4/7+5/21

=6/21+12/21+5/21=23/21

Nguyễn Lê Phước Thịnh · Answer

a: Ta có: $\dfrac{x}{33}=4$

nên x=132

b: Ta có: $\dfrac{5}{x}=\dfrac{1}{2}$

nên x=10

Câu trả lời:

a: Ta có: $\dfrac{x}{33}=4$

nên x=132

b: Ta có: $\dfrac{5}{x}=\dfrac{1}{2}$

nên x=10

Lấp La Lấp Lánh · Answer

a) $\dfrac{x}{33}=4\Rightarrow x=33.4=132$

b) $\dfrac{5}{x}=\dfrac{1}{2}\Rightarrow x=5.2=10$

a) $\dfrac{22}{55}+\dfrac{25}{125}+\dfrac{1020}{5100}=\dfrac{2}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{4}{5}$

b) $\dfrac{22}{77}+\dfrac{56}{98}+\dfrac{25}{105}=\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{5}{21}=\dfrac{6+12+5}{21}=\dfrac{23}{21}$

Câu trả lời:

a) $\dfrac{x}{33}=4\Rightarrow x=33.4=132$

b) $\dfrac{5}{x}=\dfrac{1}{2}\Rightarrow x=5.2=10$

a) $\dfrac{22}{55}+\dfrac{25}{125}+\dfrac{1020}{5100}=\dfrac{2}{5}+\dfrac{1}{5}+\dfrac{1}{5}=\dfrac{4}{5}$

b) $\dfrac{22}{77}+\dfrac{56}{98}+\dfrac{25}{105}=\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{5}{21}=\dfrac{6+12+5}{21}=\dfrac{23}{21}$