a)\(\left(2^2+3\right)\cdot\left(x-5\right)+14=5^2124:2^2\) 

b) \(3^2\cdot\left(x+1\right)-3=2^3+7^2\cdot2:14\)

c) \(2^2\cdot3\cdot\left(x+5\right)-6=\left(2^3+2^2\right)\cdot2^2\)

d) \(\left(2^2+1\right)\cdot\left(x+14\right)=5^2\cdot4+\left(2^5+3^2+7^2\right):2\)

e) \(\left(2^2-1\right)\cdot\left(x-1\right)=2^2+\left(6^2+2^6\right):\left(5^2\cdot2\right)\)

g) \(\left(3^2-2\right)\cdot\left(x-12\right)+35=5^2+279:3^2\)

nhìn thì cảm thấy khó nhưng lại rất dễ đó

Tính tổng :

a) \(A=\frac{5}{2\cdot1}+\frac{4}{1\cdot11}+\frac{3}{11\cdot14}+\frac{1}{14\cdot15}+\frac{13}{15\cdot28}\)

b) \(B=\frac{-1}{20}+\frac{-1}{30}+\frac{-1}{42}+\frac{-1}{56}+\frac{-1}{72}+\frac{-1}{90}\)

c) \(C=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+...+\frac{1}{n\left(n+1\right)\left(n+2\right)}\)

d) \(D=\frac{1}{1\cdot2\cdot3\cdot4}+\frac{1}{2\cdot3\cdot4\cdot5}+...+\frac{1}{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}\)

e) \(E=\left(\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+...+\frac{1}{37\cdot38\cdot39}\right)\cdot1482\cdot185\cdot8\)

Tính tổng :

a) \(A=\frac{5}{2\cdot1}+\frac{4}{1\cdot11}+\frac{3}{11\cdot14}+\frac{1}{14\cdot15}+\frac{13}{15\cdot28}\)

b) \(B=\frac{-1}{20}+\frac{-1}{30}+\frac{-1}{42}+\frac{-1}{56}+\frac{-1}{72}+\frac{-1}{90}\)

c) \(C=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+...+\frac{1}{n\left(n+1\right)\left(n+2\right)}\)

d) \(D=\frac{1}{1\cdot2\cdot3\cdot4}+\frac{1}{2\cdot3\cdot4\cdot5}+...+\frac{1}{n\left(n+1\right)\left(n+2\right)\left(n+3\right)}\)

e) \(E=\left(\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+...+\frac{1}{37\cdot38\cdot39}\right)\cdot1482\cdot185\cdot8\)

1,tìm x

a.\(3^x\)=81

b.\(5^{x+2}\)=125

c.\(2^3\)*\(2^{x-1}\)=64

d. 7*\(7^{n+1}\)=343

e.\(\left(x+3\right)^5\)=243

f.\(\left(2x-3\right)^6\)=64

g.\(\left(x-6\right)^3\)=\(\left(x-6\right)^2\)

h.\(\left\{\left[\left(2x+14\right):2^2-3\right]:3\right\}\)-1=0

i.\(\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)

2,tính

a.\(7^{3^1}\)         b.\(7^{1^3}\)      c.\(6^{1^{2^{3^4}}}\)       d.\(2017^{2^{0^{1^0}}}\)      e.\(6^3:6^2-6^2:6\)    f.\(\frac{11\cdot2^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)