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B1a)\(11\frac34-\left(6\frac56-4\frac12\right)+1\frac23\)
=\(11\frac34-6\frac56+4\frac12+1\frac23\)
=\(\left(11-6+4+1\right)+\left(\frac34-\frac56+\frac12+\frac23\right)\)
=\(10+\left(\frac{9}{12}-\frac{10}{12}+\frac{6}{12}+\frac{8}{12}\right)\)
=\(10+\left(-\frac{1}{12}+\frac{6}{12}+\frac{8}{12}\right)\)
=10+\(\frac{13}{12}\)
=\(\frac{120}{12}+\frac{13}{12}\)
=\(\frac{133}{12}\)
b)\(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)
= \(\frac{57}{20}-\frac{16}{5}+\frac{129}{20}\times\frac13\)
=\(\frac{57}{20}-\frac{16}{5}+\frac{129}{60}\)
=\(\frac{171}{60}-\frac{192}{60}+\frac{129}{60}\)
=\(\frac{108}{60}\)
=\(\frac95\)
kazuto kirigaya thật là bt làm ko đó ko bt thì nói đi còn bt thì làm đi
a)\(=\frac{13}{4}-\frac{1}{3}\)
\(=\frac{35}{12}\)
b)\(=\left(\frac{7}{6}-\frac{1}{2}\right).\frac{2}{3}-\frac{1}{4}\)
\(=\frac{2}{3}.\frac{2}{3}-\frac{1}{4}\left(=1-\frac{1}{4}\right)\)
\(=\frac{4}{9}-\frac{1}{4}\left(=\frac{3}{4}\right)\)
\(=\frac{7}{36}\)










\(\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{9}{24}+-\frac{18}{24}+\frac{14}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}.\frac{6}{5}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{2}{4}\)
\(=\frac{3}{4}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\left(\frac{15}{20}-\frac{16}{20}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\frac{-1}{20}\)
\(=\frac{10}{20}+\frac{15}{20}-\frac{-1}{20}\)
\(=\frac{25}{20}-\frac{-1}{20}\)
\(=\frac{26}{20}\)
\(=\frac{13}{10}\)
1/2+3/4-(3/4-4/5)
1/2+3/4+3/4+4/5
1/2+6/4+4/5
10/20+30/20+16/20
56/20=14/5
\(6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}\left(\frac{1}{3}-\frac{1}{5}\right)\)
\(=\frac{77}{12}:\frac{11}{4}+\frac{45}{4}\left(\frac{5}{15}-\frac{3}{15}\right)\)
\(=\frac{77}{12}.\frac{4}{11}+\frac{45}{4}.\frac{2}{5}\)
\(=\frac{7}{3}.\frac{1}{1}+\frac{9}{2}.\frac{1}{1}\)
\(=\frac{7}{3}+\frac{9}{2}\)
\(=\frac{14}{6}+\frac{27}{6}\)
\(=\frac{41}{6}\)
\(\left(\frac{7}{8}-\frac{3}{4}\right).1\frac{1}{3}-\frac{2}{7}\left(3,5\right)^2\)
\(=\left(\frac{7}{8}-\frac{6}{8}\right).1\frac{1}{3}-\frac{2}{7}.\frac{49}{4}\)
\(=\frac{1}{8}.\frac{4}{3}-\frac{1}{1}.\frac{7}{2}\)
\(=\frac{4}{24}.\frac{7}{2}\)
\(=\frac{2}{24}.\frac{7}{1}\)
\(=\frac{14}{24}\)
\(=\frac{7}{12}\)