Bài 2: 

a: =>x/4=1/8

hay x=1/2

b: \(\Leftrightarrow\dfrac{x}{-5}=\dfrac{11}{6}\)

hay x=-55/6

c: \(\Leftrightarrow\dfrac{-3.5}{x}=\dfrac{4.25}{8}\)

hay x=-112/17

\(1.\)

\(a,\)

\(7.\left(-28\right)=\left(-49\right).4\)

Ta có :   \(\frac{7}{-49}=\frac{4}{-28}\)                                                     \(\frac{-28}{4}=\frac{-49}{7}\)

                 \(\frac{7}{4}=\frac{-49}{-28}\)                                                      \(\frac{-28}{-49}=\frac{4}{7}\)

\(b,\)

\(0,36.4,25=0,9.1,7\)

Ta có :   \(\frac{0,36}{0,9}=\frac{1,7}{4,25}\)                                                        \(\frac{0,36}{1,7}=\frac{0,9}{4,25}\)

              \(\frac{4,25}{0,9}=\frac{1,7}{0,36}\)                                                        \(\frac{4,25}{1,7}=\frac{0,9}{0,36}\)

Bài 1a:

\(\frac{4,6}{1,4}\) = \(\frac{11,5}{5x}\)

4,6 x 5\(x\) = 11,5 x 1,4

23\(x\) = 16,1

\(x\) = 16,1 : 23

\(x\) = 0,7

Vậy \(x\) = 0,7

Bài 1b:

\(\frac{x^2}{6}\) = \(\frac{24}{25}\)

25\(x^2\) = 24.6

25\(x^2\) = 144

\(x^2\) = 144/25

\(x\) = - 12/5 hoặc \(x\) = 12/5

Vậy \(x\) ∈ {-12/5; 12/5}

Bài 1c:

\(\frac{x+2}{2}\) = \(\frac{1}{1-x}\)

(\(x\) + 2)(1 - \(x\)) = 1.2

\(x\) - \(x^2\) + 2 - 2\(x\) = 2

\(x^2\) + (2\(x\) - \(x\)) + 2 - 2 = 0

\(x^2\) + \(x\) + 0 = 0

\(x\)(\(x\) + 1) = 0

\(x\) = 0

\(x\) + 1 = 0

\(x\) = - 1

Vậy \(x\) ∈ {-1; 0}

29/1/4=117/4

6/1/2=13/2

suy ra      các tỉ lệ thức là:6/27=117/4/13/2 ;-6/13/2 =117/4/-27 và đảo mẫu với tử nữa nhé

thấy hợp lý thì k cho mình nha

6:(-27)=-6/1/2:29/1/4=6x29/1/4=-6/1/2x(-27)

\(\dfrac{6}{-6\dfrac{1}{2}}=\dfrac{29\dfrac{1}{4}}{-27};\dfrac{6}{29\dfrac{1}{4}}=\dfrac{-6\dfrac{1}{2}}{-27};\dfrac{-6\dfrac{1}{2}}{6}=\dfrac{-27}{29\dfrac{1}{4}};\dfrac{29\dfrac{1}{4}}{6}=\dfrac{-27}{-6\dfrac{1}{2}}\)

giải :

\(\frac{6}{-27}=\frac{-6\frac{1}{2}}{29\frac{1}{4}};\frac{-27}{6}=\frac{29\frac{1}{4}}{-6\frac{1}{2}};\frac{-6\frac{1}{2}}{6}=\frac{29\frac{1}{4}}{-27};\frac{6}{-6\frac{1}{2}}=\frac{-27}{29\frac{1}{4}}\)

Study well