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A=1x2+2x3+3x4+...+49x50
3A= 3(1.2+2.3+3.4+...+49.50)
3A= 1.2.3+2.3.3+3.4.3+...+49.50.3
3A= 1.2.(3-0)+2.3(4-1)+3.4(5-2)+...+49.50.(51-48)
3A= 0.1.2-1.2.3+1.2.3-2.3.4+2.3.4-3.4.5+...+48.49.50-49.50.51
3A= 49.50.51
A= 49.50.51/3=41650
B=1x3+3x5+5x7+...+99x101
B=1/1.3 +1/3.5 +...+1/99.101
2B=2/1.3 + 2/3.5 +...+2/99.101
2B=1-1/3+1/3-1/5+...+1/99-1/101
2B=1-1/101
2B=100/101
B=100/101:2=100/202
ta có:
4s=1.2.3.(4-0)+2.3.4.(5-1)+3.4.5.(6-2)+.........+k(k+1)(k+2)((k+3)-(k-1))
4s=1.2.3.4-1.2.3.0+2.3.4.5-1.2.3.4+3.4.5.6-2.3.4.5+........+k(k+1)(k+2)(k+3)-(k-1)k(k+1)(k+2)
4s=k(k+1)(k+2)(k+3)
ta biết rằng tích 4 số tự nhiên liên tiếp khi cộng thêm 1 luôn là 1 số chính phương
=>4s+1 là 1 số chính phương
Câu a:
A = 2/1.3 + 2/3.5 + ...+ 2/37.39
A = 1/1 - 1/3 + 1/3 - 1/5 + ...+ 1/37 - 1/39
A = 1/1 - 1/39
A = 39/39 - 1/39
A = 38/39
Câu b:
B = 3/1.4 + 3/4.7 + ..+ 3/97.100
B = 1/1 - 1/4 + 1/4 - 1/7 + ...+ 1/97 - 1/100
B = 1/1- 1/100
B = 100/100 - 1/100
B = 99/100
Câu a:
A = 1.2 + 2.3 + 3.4 + ...+ 99.100
3A = 1.2.3 + 2.3.3 +..+ 99.100.3
1.2.3 = 1.2.3
2.3.3 = 2.3(4 - 1) = 2.3.4 - 1.2.3
3.4.4 = 3.4(5 - 2) = 3.4.5 - 2.3.4
.............................................................
99.100.3 = 99.100.(101 - 98)=99.100.101-98.99.100
Cộng vế với vế ta có:
3A = 99.100.101
A = 99.100.101 : 3
A = 333300
Câu b:
1.3 + 3.5 + 5.7 + ..+ 97.99
6.A = 1.3.6 + 3.5.6 + 5.7.6 + ...+ 97.99.6
1.3.6 = 1.3.(5 + 1) = 1.3.5 + 1.3.1
3.5.6 = 3.5.(7 - 1) = 3.5.7 - 1.3.5
5.7.6 = 5.7.(9 - 3) = 5.7.9 - 3.5.7
.......................................................
97.99.6 = 97.99.(101 - 95) = 97.99.101-95.97.99
Cộng vế với vế ta có:
6A = 1.3.1 + 97.99.101
A = (1.3.1 + 97.99.101) : 6
A = (3 + 9603.101) : 6
A = (3+ 969903) : 6
A = 969906 : 6
A = 161651
\(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{6.7.8}\)
\(=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{6.7}-\frac{1}{7.8}\)
\(=\frac{1}{1.2}-\frac{1}{7.8}\)
\(=\frac{1}{2}-\frac{1}{56}\)
\(=\frac{28}{56}-\frac{1}{56}=\frac{27}{56}\)
Dấu . là nhân nha
\(\frac{2}{1.2.3}=\frac{1}{1.2}-\frac{1}{2.3}\)
\(\frac{2}{2.3.4}=\frac{1}{2.3}-\frac{1}{3.4}\)
.......................................
\(\frac{2}{6.7.8}=\frac{1}{6.7}-\frac{1}{7.8}\)
S= \(\frac{1}{1.2}-\frac{1}{7.8}=\frac{27}{56}\)
a)\(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99.101}\)
= \(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\)
= \(1-\dfrac{1}{101}\)
=\(\dfrac{100}{101}\)
\(\dfrac{5}{1.3}+\dfrac{5}{3.5}+\dfrac{5}{5.7}+...+\dfrac{5}{99.101}\)
=\(\dfrac{5}{2}.\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99+101}\right)\)
=\(\dfrac{5}{2}.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\)
=\(\dfrac{5}{2}.\left(1-\dfrac{1}{101}\right)\)
= \(\dfrac{5}{2}-\dfrac{100}{101}\)
= \(\dfrac{305}{202}\)
A = 1.3 + 3.5 + ..+ 99.101
6A = 1.3.6 + 3.5.6 + 5.7.6 + ...+99.101.6
1.3.6 = 1.3.(5 + 1) = 1.3.5 + 1.3.1
3.5.6 = 3.5.(7 - 1) = 3.5.7 - 1.3.5
5.7.6 = 5.7.(9- 3) = 5.7.9 - 3.5.7
.........................................................
99.101.6 = 99.101.(103 - 97) = 99.101.103-97.99.101
Cộng vế với vế ta có:
6A = 1.3.1 + 99.101.103
6A = 3 + 9999.103
6A = 3 + 1029897
6A = 1029900
A = 1029900 : 6
A = 171650
Câu b:
B = 1.2.3 + 2.3.4 + 3.4.5 + ...+99.100.101
4B = 1.2.3.4 + 2.3.4.4 + 3.4.5.4 +..+ 99.100.101.4
1.2.3.4 = 1.2.3.4
2.3.4.4 = 2.3.4.(5-1) = 2.3.4.5 - 1.2.3.4
3.4.5.4 = 3.4.5.(6 - 2) = 3.4.5.6 - 2.3.4.5
..............................................................................
99.100.101.4 = 99.100.101.(102 - 98) = 99.100.101.102 - 98.99.100.101
Cộng vế với vế ta có:
4B = 99.100.101.102
B = 99.100.101.102 : 4
B = 25497450