143 + 187 + 209

= 11 x (13 + 17 + 20)

= 11 x 40

LIK-E mik nha bạn

Bài 4:

a: \(\overline{275x}\) ⋮5

=>x∈{0;5}

\(\overline{275x}\) ⋮25

=>\(\overline{5x}\) ⋮25

=>x=0

b: \(\overline{9xy4}\) ⋮2

=>(x;y)∈{(0;0);(0;1);...:(9;9)}

\(\overline{9xy4}\) ⋮4

=>\(\overline{y4}\) ⋮4

=>y∈{0;2;4;6;8}

=>(x;y)∈{(1;0);(1;2);(1;4);(1;6);(1;8);(2;0);(2;2);...;(9;0);(9;2);(9;4);(9;6);(9;8)}

\(\overline{9xy4}\) ⋮8

=>\(\overline{xy4}\) ⋮8

=>(x;y)∈{(1;0);(1;4);(1;8);(2;2);(2;6);(3;0);(3;4);(3;8);(4;2);(4;6);(5;0);(5;4);(5;8);(6;2);(6;6);(7;0);(7;4);(7;8);(8;2);(8;6);(9;0);(9;4);(9;8)}

Bài 2:

a chia 72 dư 18

=>a=72k+18

a=72k+18=2(36k+9)

=>a⋮2

a=72k+18=3(24k+6)

=>a⋮3

a=72k+18=72k+16+2=4(18k+4)+2

=>a không chia hết cho 4

a=72k+18=6(12k+3)⋮6

a=72k+18=72k+16+2=8(9k+2)+2

=>a không chia hết cho 8

a=72k+18

=9(8k+2)

=>a⋮9

\(A=132+77+198=12.11+7.11+18.11=37.11\)

\(B=5555+6767+7878=55.101+67.101+78.101=200.101\)

\(C=1997,1997+1998,1998+1999,1999\)

\(=1997\times1,0001+1998\times1,0001+1999\times1,0001\)

\(=5994\times1,0001\)

K biết

\(=4^{1010}\cdot125^{673}\\ =4^{337}\cdot4^{673}\cdot125^{673}\\ =4^{337}\cdot500^{673}\\=2^{674} \cdot500^{673}\\ =2\cdot2^{673}\cdot500^{673}\\ =2\cdot1000^{673}=200000...000\left(Có.2019.số.0\right)\\ Vậy.tổng.chữ.số.là=2+0\cdot2019=0\)

a) 144 + 77 + 143 = 264 \(⋮\)11

b) 132 - 55 = 77 \(⋮\)11

c) 143 + 99 + 12 = 254 \(⋮̸\)11

d) 243 - 89 =154 \(⋮\)11

                                                Bài giải

\(a,\text{ }144+77+143=364⋮̸11\)

\(b,\text{ }132-55=77\text{ }⋮\text{ }11\)

\(c,\text{ }143+99+12=254\text{ }⋮̸\text{ }11\)

\(c,\text{ }243-89=154\text{ }⋮̸\text{ }11\)

biến đổi tổng thành tích:(a+1)(b-2)-(ab-2a)

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