a, ta có: (2x-3).(6-2x)=0

=>(2x-3)=0 hoặc (6-2x)=0

+, nếu 2x-3=0 thì x= 2/3 (1)

+, nếu 6-2x=0 thì x= 3 (2)

vì x thuộc Z nên từ (1) và(2) => x=3

vậy x=3

a)TH1: 2x-3=0

              2x=3

                x=3/2

 TH2; 6-2x=0

             2x=6

               x=3

a) ( 2x - 3 )( 6 - 2x ) = 0

<=> \(\orbr{\begin{cases}2x-3=0\\6-2x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=3\end{cases}}\)

b) | 1/2x - 1/3 | - 3/2 = 1/4

<=> | 1/2x - 1/3 | = 7/4

<=> \(\orbr{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{7}{4}\\\frac{1}{2}x-\frac{1}{3}=-\frac{7}{4}\end{cases}}\)

<=> \(\orbr{\begin{cases}x=\frac{25}{6}\\x=-\frac{17}{6}\end{cases}}\)

c) ( 2x + 3/5 )² = 9/25

<=> ( 2x + 3/5 )² = ( ±3/5 )²

<=> \(\orbr{\begin{cases}2x+\frac{3}{5}=\frac{3}{5}\\2x+\frac{3}{5}=-\frac{3}{5}\end{cases}}\)

<=> \(\orbr{\begin{cases}x=0\\x=-\frac{3}{5}\end{cases}}\)

d) 11/3( 1/5 - 1/2 ) ≤ x ≤ 3/11( 1/5 + 2/3 - 1/2 )

<=> -11/10 ≤ x ≤ 1/10

e) 4, 25 - ( 25/8 - 1, 105 ) < x < 9,1 - ( 6, 85 - 11/4 )

<=> 223/100 < x < 5 

<=> 223/100 < x < 500/100 

ý d) với e) nó nhiều số lắm nên k liệt kê hết được đâu :))

b)  \(|\)1/2x-1/3\(|\)  - 3/2 = 1/4

      \(|\)1/2x-1/3\(|\)= 1/4+3/2=7/4

Th1: 1/2x-1/3=7/4

            1/2x=7/4+1/3

            1/2x=25/12

                 x=25/12:1/2

                 x=25/6

Th2: 1/2x-1/3=-7/4

              1/2x= -7/4+1/3

                1/2x=-17/12

                    x= -17/12:1/2

                     x=-17/6

\(a,\left(2x-3\right).\left(6-2x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-3=0\\6-2x=0\end{cases}}\Rightarrow\orbr{\begin{cases}2x=3\\2x=6\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=3\end{cases}}\)

\(b,|\frac{1}{2}.x-\frac{1}{3}|-\frac{3}{2}=\frac{1}{4}\)

\(|\frac{1}{2}.x-\frac{1}{3}|=\frac{1}{4}+\frac{3}{2}\)

\(|\frac{1}{2}.x-\frac{1}{3}|=\frac{7}{4}\)

\(\Rightarrow\orbr{\begin{cases}\frac{1}{2}x-\frac{1}{3}=\frac{7}{4}\\\frac{1}{2}x-\frac{1}{3}=-\frac{7}{4}\end{cases}}\Rightarrow\orbr{\begin{cases}\frac{1}{2}x=\frac{25}{12}\\\frac{1}{2}x=\frac{-17}{12}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{25}{6}\\x=\frac{-17}{6}\end{cases}}\)

\(c,\left(2x+\frac{3}{5}\right)^2=\frac{9}{25}\)

\(\left(2x+\frac{3}{5}\right)^2=\left(\frac{3}{5}\right)^2\)

\(\Rightarrow\orbr{\begin{cases}2x+\frac{3}{5}=\frac{3}{5}\\2x+\frac{3}{5}=\frac{-3}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}2x=0\\2x=\frac{-6}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{-3}{5}\end{cases}}\)

\(d,\frac{11}{3}.\left(\frac{1}{5}-\frac{1}{2}\right)\le x\le\frac{3}{11}.\left(\frac{1}{5}+\frac{2}{3}-\frac{1}{2}\right)\)

\(\Rightarrow\frac{11}{3}.\frac{-3}{10}\le x\le\frac{3}{11}.\frac{11}{30}\)

\(\Rightarrow\frac{-11}{10}\le x\le\frac{3}{10}\)

\(\Leftrightarrow x=\left\{\frac{-11}{10};\frac{-10}{10};\frac{-9}{10};...;\frac{2}{10};\frac{3}{10}\right\}\)

\(e,4,25-\left(\frac{25}{8}-1,105\right)< x< 9,1-\left(6,85-\frac{11}{4}\right)\)

\(\Rightarrow4,25-2,02< x< 9,1-4,1\)

\(\Rightarrow2,23< x< 5\)

\(\Leftrightarrow x=\left\{2,24;2,25;2,26;.....;4,99;5\right\}\)

Học tốt

úi e nhầm đè

cái kia phải là 4,85 cứ ko phải 4,25 sorry mn mong mn giúp e