Nếu có lời giải thì đưa lun nha, ko thì thui!!!!!

huhu... ko ai giúp mik ak???

bạn vào link này xem nhé

http://olm.vn/hoi-dap/question/97037.html

minh ko tin dc ban oi

\(\left(-2\frac{3}{4}+\frac{1}{2}\right)^2\)

\(=\left(-\frac{11}{4}+\frac{1}{2}\right)^2\)

\(=\left(-\frac{11}{4}+\frac{2}{4}\right)^2\)

\(=\left(-\frac{9}{4}\right)^2\)

\(=\frac{81}{16}\)

\(\left(-2\frac{3}{4}+\frac{1}{2}\right)^2\)

\(=\left(\frac{-11}{4}+\frac{1}{2}\right)^2\)

\(=\left(\frac{-11}{4}+\frac{2}{4}\right)^2\)

\(=\left(\frac{-9}{4}\right)^2\)

\(=\frac{81}{16}\)

+ Với x < -5 thì |x + 5| = -(x + 5) = -x - 5

=> -x - 5 = 4x + 1

=> -x - 4x = 1 + 5

=> -5x = 6

=> \(x=-\frac{6}{5}\), không thỏa mãn x < -5

+ Với \(x\ge-5\) thì |x + 5| = x + 5

=> x + 5 = 4x + 1

=> 4x - x = 5 - 1

=> 3x = 4

=> \(x=\frac{4}{3}\), thỏa mãn \(x\ge-5\)

Vậy \(x=\frac{4}{3}\)

\(\left|x+5\right|=4x+1\)

\(=>\left[\begin{array}{nghiempt}x+5=4x+1\\x+5=-\left(4x+1\right)=-4x-1\end{array}\right.\)

\(=>\left[\begin{array}{nghiempt}3x=4\\5x=-6\end{array}\right.\)

\(=>\left[\begin{array}{nghiempt}x=\frac{4}{3}\\x=-\frac{6}{5}\end{array}\right.\)

đưa nick đây t đổi cho ko lấy đâu

no no no

tui ko phải là ko bít đổi mà là ko đổi đc !!!

4.

\(\left(0,36\right)^8=\left(\left(0,6\right)^2\right)^8=\left(0,6\right)^{16}\)

\(\left(0,216\right)^4=\left(\left(0,6\right)^3\right)^4=\left(0,6\right)^{12}\)

5. 

a, \(\left(3\times5\right)^3=15^3=1125\)

b, \(\left(\frac{-4}{11}\right)^2=\frac{16}{121}\)

c, \(\left(0,5\right)^4\times6^4=\left(0,5\times6\right)^4=3^4=81\)

d, \(\left(\frac{-1}{3}\right)^5\div\left(\frac{1}{6}\right)^5=\left(\frac{-1}{3}\right)^5\times6^5=\left(\frac{-1}{3}\times6\right)^5=\left(-2\right)^5=-32\)

6.

a, \(\frac{6^2\times6^3}{3^5}=\frac{6^5}{3^5}=\frac{2^5\times3^5}{3^5}=2^5=32\)

b, \(\frac{25^2\times4^2}{5^5\times\left(-2\right)^5}=\frac{100^2}{\left(-10\right)^5}=\frac{10^4}{\left(-10\right)^5}=\frac{-1}{10}\)

c, Mình không nhìn rõ đề 

d, \(\left(-2\frac{3}{4}+\frac{1}{2}\right)^2=\left(\frac{-11}{4}+\frac{1}{2}\right)^2=\left(\frac{-9}{4}\right)^2=\frac{81}{16}\)

7.

a, \(\left(\frac{1}{3}\right)^m=\frac{1}{81}\Rightarrow\left(\frac{1}{3}\right)^m=\left(\frac{1}{3}\right)^4\Rightarrow m=4\)

b, \(\left(\frac{3}{5}\right)^n=\left(\frac{9}{25}\right)^5\Rightarrow\left(\frac{3}{5}\right)^n=\left(\left(\frac{3}{5}\right)^2\right)^5\Rightarrow\left(\frac{3}{5}\right)^n=\left(\frac{3}{5}\right)^{10}\Rightarrow n=10\)

c, \(\left(-0,25\right)^p=\frac{1}{256}\Rightarrow\left(-0,25\right)^p=\left(\frac{1}{4}\right)^4\Rightarrow\left(-0,25\right)^p=\left(0,25\right)^4\Rightarrow p=4\)

8.

a, \(\left(\frac{2}{5}+\frac{3}{4}\right)^2=\left(\frac{23}{20}\right)^2=\frac{529}{400}\)

b, \(\left(\frac{5}{4}-\frac{1}{6}\right)^2=\left(\frac{1}{2}\right)^2=\frac{1}{4}\)

cam on ban nhieu