a)Ta có: \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)

\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}-\frac{-2}{15}\)

\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}=\right)\frac{-2}{5}\)

\(\Rightarrow y-\frac{2}{3}=\frac{-2}{5}:\frac{6}{5}=\frac{-1}{3}\)

\(\Rightarrow y=\frac{-1}{3}+\frac{2}{3}=\frac{1}{3}\)

Vậy x = \(\frac{1}{3}\)

b) Ta có: \(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)

        \(\Rightarrow\frac{-2}{5}+x.\left(\frac{2}{3}+\frac{1}{6}\right)=\frac{-4}{15}\)

        \(\Rightarrow x.\frac{5}{6}=\frac{-4}{15}-\frac{-2}{15}\)

         \(x.\frac{5}{6}=\frac{-2}{15}\)

\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)

Vậy x = \(\frac{-4}{25}\)

c) Ta có: \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}.x=\frac{-4}{15}\)

\(\Rightarrow\frac{3}{2}x-\frac{2}{3}x+\frac{-2}{5}=\frac{-4}{15}\)

\(\Rightarrow x.\left(\frac{3}{2}-\frac{2}{4}\right)=\frac{-4}{15}-\frac{-2}{15}\)

\(\Rightarrow x.\frac{5}{6}=\frac{-2}{15}\)

\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)

Vậy x = \(\frac{-4}{25}\)

Ủng hộ tớ nha m.n

a)Ta có: \(\frac{- 2}{5} + \frac{6}{5} . \left(\right. y - \frac{2}{3} \left.\right) = \frac{- 4}{15}\)

\(\Rightarrow \frac{6}{5} . \left(\right. y - \frac{2}{3} \left.\right) = \frac{- 4}{15} - \frac{- 2}{15}\)

\(\Rightarrow \frac{6}{5} . \left(\right. y - \frac{2}{3} = \left.\right) \frac{- 2}{5}\)

\(\Rightarrow y - \frac{2}{3} = \frac{- 2}{5} : \frac{6}{5} = \frac{- 1}{3}\)

\(\Rightarrow y = \frac{- 1}{3} + \frac{2}{3} = \frac{1}{3}\)

Vậy x = \(\frac{1}{3}\)

b) Ta có: \(\frac{- 2}{5} + \frac{2}{3} x + \frac{1}{6} x = \frac{- 4}{15}\)

        \(\Rightarrow \frac{- 2}{5} + x . \left(\right. \frac{2}{3} + \frac{1}{6} \left.\right) = \frac{- 4}{15}\)

        \(\Rightarrow x . \frac{5}{6} = \frac{- 4}{15} - \frac{- 2}{15}\)

         \(x . \frac{5}{6} = \frac{- 2}{15}\)

\(\Rightarrow x = \frac{- 2}{15} : \frac{5}{6} = \frac{- 4}{25}\)

Vậy x = \(\frac{- 4}{25}\)

c) Ta có: \(\frac{3}{2} x + \frac{- 2}{5} - \frac{2}{3} . x = \frac{- 4}{15}\)

\(\Rightarrow \frac{3}{2} x - \frac{2}{3} x + \frac{- 2}{5} = \frac{- 4}{15}\)

\(\Rightarrow x . \left(\right. \frac{3}{2} - \frac{2}{4} \left.\right) = \frac{- 4}{15} - \frac{- 2}{15}\)

\(\Rightarrow x . \frac{5}{6} = \frac{- 2}{15}\)

\(\Rightarrow x = \frac{- 2}{15} : \frac{5}{6} = \frac{- 4}{25}\)

Vậy x = \(\frac{- 4}{25}\)

\(a/\frac{7}{9}-\frac{x}{3}=\frac{1}{9}\)

\(\Rightarrow\frac{x}{3}=\frac{7}{9}-\frac{1}{9}\)

\(\Rightarrow\frac{x}{3}=\frac{2}{3}\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

\(b/\frac{1}{x}-\frac{-2}{15}=\frac{7}{15}\)

\(\Rightarrow\frac{1}{x}=\frac{7}{15}+\frac{-2}{15}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{3}\)

\(\Rightarrow x=3\)

Vậy \(x=3\)

\(c/\frac{-11}{14}-\frac{-4}{x}=\frac{-3}{14}\)

\(\Rightarrow\frac{-4}{x}=\frac{-11}{14}-\frac{-3}{14}\)

\(\Rightarrow\frac{-4}{x}=\frac{-4}{7}\)

\(\Rightarrow x=7\)

Vậy \(x=7\)

\(d/\frac{x}{21}-\frac{2}{3}=\frac{5}{21}\)

\(\Rightarrow\frac{x}{21}=\frac{5}{21}+\frac{2}{3}\)

\(\Rightarrow\frac{x}{21}=\frac{19}{21}\)

\(\Rightarrow x=19\)

Vậy \(x=19\)

#Mạt Mạt#

Mình cảm ơn bạn rất nhiều, nếu muốn bạn có thể cho mình biết gmail của bạn nếu bạn có đc chứ Vương Mạt Mạt

a) \(\left(x-\frac{5}{8}\right).\frac{5}{18}=\frac{-15}{36}\)

\(\Rightarrow x-\frac{5}{8}=\frac{-15}{36}:\frac{5}{18}\)

\(\Rightarrow x-\frac{5}{8}=\frac{-3}{2}\)

\(\Rightarrow x=\frac{-3}{2}+\frac{5}{8}\)

\(\Rightarrow x=\frac{-7}{8}\)

c) \(x\)là ước của 4

\(\Rightarrow x\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)

nhớ tk ^.^\(\)

\(\)

\(a)\) \(\left(x-\frac{5}{8}.\right).\frac{5}{18}=-\frac{15}{36}\)

\(\Rightarrow x-\frac{5}{8}=-\frac{15}{36}:\frac{5}{18}\)

\(\Rightarrow x-\frac{5}{8}=-\frac{15}{36}.\frac{18}{5}\)

\(\Rightarrow x-\frac{5}{8}=-\frac{3}{2}\)

\(\Rightarrow x=-\frac{3}{2}+\frac{5}{8}\)

\(\Rightarrow x=-\frac{12}{8}+\frac{5}{8}\)

\(\Rightarrow x=-\frac{7}{8}\)

Vậy \(x=-\frac{7}{8}\)

\(b)\frac{x+2}{5}=-\frac{15}{2}\)

\(\Rightarrow\left(x+2\right).2=-15.5\)

\(\Rightarrow\left(x+2\right).2=-75\)

\(\Rightarrow x+2=-75:2\)

\(\Rightarrow x+2=-37,5\)

\(\Rightarrow x=-37,5-2\)

\(\Rightarrow x=-39,5\)

\(c)\)Do x là Ư ( 4 ) 

\(\Rightarrow x\in\left\{1;-1;2;-2;4;-4\right\}\)

Chúc bạn học tốt !!!! 

\(a.\)\(\Rightarrow\) \(3x-2=\frac{5}{7}\)hoặc \(3x-2=-\frac{5}{7}\)

    \(\Rightarrow x=\frac{19}{21}\)         hoặc \(x=\frac{3}{7}\)

tíc mình nha

Câu 1a:

\(-\frac36\) = \(\frac{x}{-10}\) = \(\frac{-7}{y}\) = \(\frac{z}{18}\)

-3/6 = x/-10 ⇒ x = -3/6 x (-10) = 5

- 3/6 = - 7/y ⇒ y = -7 : (-3/6) = 14

-3/6 = z/18 ⇒ z = -3/6 x 18 = - 9

Vậy (x; y; z) = (5; 14; -9)

Câu 1b:

\(\frac{x+5}{x-2}=\frac23\)

3.(x+5) = 2.(x -2)

3x + 15 = 2x - 4

3x - 2x = - 15 - 4

x = - 19

Vậy x = - 19

Tìm \(x\) câu a:

\(\frac13.x\) + \(\frac25.\left(x+1\right)\) = 0

\(\frac{5}{15}x\) + \(\frac{6}{15}x\) + \(\frac25\) = 0

\(\frac{11}{15}x\) = - \(\frac25\)

\(x=-\frac25:\frac{11}{15}\)

\(x\) = - \(\frac25\times\frac{15}{11}\)

\(x\) = - \(\frac{6}{11}\)

Vậy \(x=-\frac{6}{11}\)

Tìm \(x\) câu b:

\(x\) x 25% = 0,5

\(x\times0,25\) = 0,5

\(x=0,5:0,25\)

\(x=2\)

Vậy \(x=2\)

Câu 1a:

1/3x + 2/5(x + 1) = 0

1/3x + 2/5x + 2/5 = 0

1/3x + 2/5x = - 2/5

x(1/3 + 2/5) = -2/5

x.(5/15 + 6/15) = -2/5

x.11/15 = - 2/5

x = - 2/5 : 11/15

x = - 6/11

Vậy x = -6/11

Câu b:

x . 25%. x = 0,5

x.x = 0,5 : 25%

x^2 = 2

x = - \(\sqrt2\); x = \(\sqrt2\)

Vậy x ∈ {- \(\sqrt2\); \(\sqrt2\) )

Câu 1a:

1/3x + 2/5(x + 1) = 0

1/3x + 2/5x + 2/5 = 0

1/3x + 2/5x = - 2/5

x(1/3 + 2/5) = -2/5

x.(5/15 + 6/15) = -2/5

x.11/15 = - 2/5

x = - 2/5 : 11/15

x = - 6/11

Vậy x = -6/11

Câu b:

x . 25%. x = 0,5

x.x = 0,5 : 25%

x^2 = 2

x = - \(\sqrt2\); x = \(\sqrt2\)

Vậy x ∈ {- \(\sqrt2\); \(\sqrt2\) )