(2x-1)⁵=x⁵
=>2x-1=x
=>2x-x=1
=>x=1

\(\left(2\cdot x-1\right)^5=x^5\)

=>  \(2x-1=x\)

=> \(2x-x=1\)

=>  \(x=1\)

mk chưa hc đến cái này lúc nào mk hc rồi mk sẽ giúp bn 

nhin loa mat qua. Khiep qua roi, con tam chi dau ma giai

?????

đừng ghi chắc kết quả đó 

a) \(3^{2x+2}=9^{x+3}\)

\(3^{2\left(x+1\right)}=9^{x+3}\)

\(9^{x+1}=9^{x+3}\)

\(\Rightarrow\)\(x+1=x+3\)

\(\Rightarrow x-x=3-1\)

\(\Rightarrow0x=2\)

\(\Rightarrow x\in\varnothing\)

vậy \(x\in\varnothing\)

a) \(9< 3^x< 243\)

\(\Leftrightarrow3^2< 3^x< 3^5\)

\(\Rightarrow x\in\left\{3;4\right\}\)

b) Sửa đề: \(3^4.3^x\div9=27\)

\(\Leftrightarrow3^{x+4}=3\)

\(\Rightarrow x+4=1\)

\(\Rightarrow x=-3\)

c) \(3^x\div3^2=243\)

\(\Leftrightarrow3^{x-2}=3^5\)

\(\Rightarrow x-2=5\)

\(\Rightarrow x=7\)

d) \(25< 5^x< 3125\)

\(\Leftrightarrow5^2< 5^x< 5^5\)

\(\Rightarrow x\in\left\{3;4\right\}\)

e) \(2^x-64=2^6\)

\(\Leftrightarrow2^x=64+64=128\)

\(\Leftrightarrow2^x=2^7\)

\(\Rightarrow x=7\)

f) \(2^x\div16=128\)

\(\Leftrightarrow2^x=2^7.2^4\)

\(\Leftrightarrow2^x=2^{11}\)

\(\Rightarrow x=11\)

bài cuối đây:

(x+1)+(x+2)+(x+3)+...+(x+100)=5750

[(x+100)+(x+1)].100 /2 =5750

(2x+101).100 /2 =5750

(2x+101).50=5750

2x+101=115

2x=14

x=7