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B1 : x + (x+1) + (x+2) + ...+ (x+35) = 0
x + x +1 + x+ 2+...+ x +35 = 0
x + x.35 + (1+2+...+35) = 0
x.36 + 630 =0
x.36 = -630
x = -630 : 36
x =- 17.5
Câu a:
2.(x + 2/5) + 1 1 /4 = 11/20
2x + 4/5 + 5/4 = 11/20
2x = 11/20 - 5/4 - 4/5
2x = 11/20 - 25/20 - 16/20
2x = -30/20
2x = -3/2
x = -3/2 : 2
x = - 3/4
Vậy x = - 3/4
Câu b:
x - 1 1/8 - 2/3x - 5/6x = 75%
(x - 2/3x - 5/6x) = 75% + 1 1/8
x (1 - 2/3 - 5/6) = 3/4 + 9/8
x (6/6 - 4/6 - 5/6) = 6/8 + 9/8
x.(-1/2) = 15/8
x = 15/8 : (-1/2)
x = 15/8 x (-2)
= -15/4
a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
Câu a:
x - 1: 4/3 + 9/16 = - 5^2/4^2
x - 1 x 3/4 + 9/16 = - 25/16
x - 3/4 + 9/16 = - 25/16
x - 3/4 = -25/16 - 9/16
x - 3/4 = -17/8
x = - 17/8 + 3/4
x = -11/8
Vậy x = -11/8
Câu b:
5/2x + 2 - 3 1/2 = 1/6
5/2x + 2 - 7/2 = 1/6
5/2x = 1/6 + 7/2 - 2
5/2x = 1/6 + 21/6 - 12/6
5/2x = 5/3
x = 5/3 : 5/2
x = 2/3
\(\frac{-2}{3}\) \(-\) \(\frac{1}{3}\) X \(\left(2.x-5\right)\) \(=\frac{3}{2}\)
\(-1\) X \(\left(2.x-5\right)\) \(=\frac{3}{2}\)
\(\left(2.x-5\right)\) \(=\frac{3}{2}\) \(:-1\)
\(\left(2.x-5\right)\) \(=\frac{3}{2}\)
\(2.x\) \(=\frac{3}{2}\) \(+\) \(5\)
\(2.x\) \(=\frac{7}{2}\)
\(x=\) \(\frac{7}{2}\) \(:2\)
\(x=\frac{7}{4}\)
* Mới lớp 5 nên không chắc, sai thongcam *
#Ninh Nguyễn
\(\frac{-2}{3}-\frac{1}{3}\cdot\left(2x-5\right)=\frac{3}{2}\)
\(\frac{1}{3}\left(2x-5\right)=\frac{-2}{3}-\frac{3}{2}\)
\(2x-5=\frac{-13}{6}:\frac{1}{3}\)
\(2x=\frac{-13}{2}+5\)
\(x=\frac{-3}{2}:2\)
\(x=\frac{-3}{4}\)
1: =>|3x-3/2|=x-1/2+1/4=x-1/4
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{1}{4}\\\left(3x-\dfrac{3}{2}-x+\dfrac{1}{4}\right)\left(3x-\dfrac{3}{2}+x-\dfrac{1}{4}\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=\dfrac{1}{4}\\\left(2x-\dfrac{5}{4}\right)\left(4x-\dfrac{7}{4}\right)=0\end{matrix}\right.\Leftrightarrow x\in\left\{\dfrac{5}{8};\dfrac{7}{16}\right\}\)
2: =>|1/3x+2/3|=5/3-1+x=x+2/3
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-\dfrac{2}{3}\\\left(\dfrac{1}{3}x+\dfrac{2}{3}-x-\dfrac{2}{3}\right)\left(\dfrac{1}{3}x+\dfrac{2}{3}+x+\dfrac{2}{3}\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x>=-\dfrac{2}{3}\\\left(-\dfrac{2}{3}x\right)\cdot\left(\dfrac{4}{3}x+\dfrac{4}{3}\right)=0\end{matrix}\right.\Leftrightarrow x=0\)