a) Ta có: \(15\frac{3}{13}-\left(3\frac{4}{7}+8\frac{3}{13}\right)\)

\(=15+\frac{3}{13}-3-\frac{4}{7}-8-\frac{3}{13}\)

\(=4-\frac{4}{7}=\frac{24}{7}\)

b) Ta có: \(\left(7\frac{4}{9}+4\frac{7}{11}\right)-3\frac{4}{9}\)

\(=7+\frac{4}{9}+4+\frac{7}{11}-3-\frac{4}{9}\)

\(=8+\frac{7}{11}=\frac{95}{11}\)

c) Ta có: \(\frac{-7}{9}\cdot\frac{4}{11}+\frac{-7}{9}\cdot\frac{7}{11}+5\frac{7}{9}\)

\(=\frac{-7}{9}\cdot\frac{4}{11}+\frac{-7}{9}\cdot\frac{7}{11}+\frac{-7}{9}\cdot\frac{-52}{7}\)

\(=\frac{-7}{9}\cdot\left(\frac{4}{11}+\frac{7}{11}-\frac{52}{7}\right)\)

\(=\frac{-7}{9}\cdot\frac{45}{-7}=5\)

d) Ta có: \(50\%\cdot1\frac{1}{3}\cdot10\cdot\frac{7}{35}\cdot0.75\)

\(=\frac{1}{2}\cdot\frac{4}{3}\cdot10\cdot\frac{7}{35}\cdot\frac{3}{4}\)

\(=5\cdot\frac{7}{35}=1\)

e) Ta có: \(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+...+\frac{3}{40\cdot43}\)

\(=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}\)

\(=1-\frac{1}{43}=\frac{43}{43}-\frac{1}{43}\)

\(=\frac{42}{43}\)

\(a,15\frac{3}{13}-\left(3\frac{4}{7}+8\frac{3}{13}\right)\\ =15\frac{3}{13}-3\frac{4}{7}-8\frac{3}{13}\\ =7\frac{3}{13}-3\frac{4}{7}\\ =\frac{94}{13}-\frac{25}{7}\\ =\frac{94\cdot7-25\cdot13}{13\cdot7}\\ =\frac{333}{91}\)

\(b,\left(7\frac{4}{9}+4\frac{7}{11}\right)-3\frac{4}{9}\\ =7\frac{4}{9}-3\frac{4}{9}+4\frac{7}{11}\\ =4\frac{4}{9}+4\frac{7}{11}\\ =\frac{40}{9}+\frac{51}{11}\\ =\frac{40\cdot11+51\cdot9}{11\cdot9}\\ =\frac{899}{99}\)

\(c,=-\frac{7}{9}\cdot\left(\frac{4}{11}+\frac{7}{11}\right)+\frac{52}{9}\\ =-\frac{7}{9}\cdot1+\frac{52}{9}\\ =\frac{-7+52}{9}\\ =\frac{45}{9}=5\)

\(d,=\frac{50}{100}\cdot\frac{4}{3}\cdot10\cdot\frac{7}{35}\cdot\frac{75}{100}\\ =\frac{50\cdot2\cdot2\cdot2\cdot5\cdot7\cdot25\cdot3}{50\cdot2\cdot3\cdot5\cdot7\cdot25\cdot2\cdot2}=1\)

\(e,=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{40}-\frac{1}{43}\\ =1-\frac{1}{43}\\ =\frac{42}{43}\)

\(a,\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)

\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(=\frac{3\left[\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right]}{11\left[\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right]}=\frac{3}{11}\)

Câu b tương tự

#)Giải :

b)\(\frac{5}{9}:\left(\frac{1}{3}+\frac{1}{4}\right)+\frac{5}{9}:\left(\frac{1}{9}+\frac{2}{3}\right)\)

\(=\frac{5}{9}:\frac{1}{3}+\frac{5}{9}:\frac{1}{4}+\frac{5}{9}:\frac{1}{9}+\frac{5}{9}:\frac{2}{3}\)

\(=\frac{5}{9}:\left(\frac{1}{3}+\frac{1}{4}+\frac{1}{9}+\frac{2}{3}\right)\)

\(=\frac{5}{9}:\frac{49}{36}\)

\(=\frac{20}{49}\)

a, \(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}.\frac{12}{7}\)

\(=\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{11}\right)+\frac{12}{7}\)

\(=\frac{-5}{7}.1+\frac{12}{7}=\frac{-5}{7}+\frac{12}{7}=\frac{7}{7}=1\)

Kết quả = 1

a) B = \(\frac{1}{2}.\frac{4}{3}.20.\frac{7}{35}.0,75\)

B = \(\frac{1.1.2.1.1}{1.1.1.1.1}\)

B= 2

b) \(\frac{1}{3}x=16\frac{1}{4}-13\frac{1}{4}\)

= > \(\frac{1}{3}x=3\)

= > x = 9

c)\(\frac{2}{3}x=\frac{-1}{4}-\frac{1}{3}\)

=> \(\frac{2}{3}x=-\frac{7}{12}\)

=> x = \(\frac{-7}{12}:\frac{2}{3}\)

=> x = \(\frac{-7}{8}\)

chuvh7uuyj

501.1/3.10.7/35.0,75 = 501.1/3.10.1/5.75/100

                            = 250 / 1 /2

bài 1

A= \(\frac{1}{2}.\frac{4}{3}.20.\frac{7}{35}.0,75=2\)

bài 2

a,\(\Leftrightarrow\frac{1}{3}x+\frac{53}{4}=\frac{65}{4}\)

\(\Leftrightarrow\frac{1}{3}x=3\)

\(\Leftrightarrow x=9\)

vậy....

b, \(\Leftrightarrow\frac{2}{3}x=\frac{-7}{12}\)

\(\Leftrightarrow x=-\frac{7}{8}\)

vậy.......

a)\(=\frac{-5}{2}:\left(\frac{3}{4}-\frac{2}{4}\right)\)

\(=\frac{-5}{2}:1=\frac{-5}{2}\)

b)\(=\frac{146}{13}-\left(\frac{18}{7}+\frac{68}{13}\right)\)

\(=\frac{146}{13}-\frac{18}{7}-\frac{68}{13}\)

\(=\frac{146}{13}-\frac{68}{13}-\frac{18}{7}\)

\(=\frac{78}{13}-\frac{18}{7}=6-\frac{18}{7}=\frac{42}{7}-\frac{18}{7}=\frac{24}{7}\)

c)\(=\left(\frac{-5}{24}+\frac{18}{24}+\frac{14}{24}\right):\left(\frac{-9}{4}\right)^2\)

\(=\frac{27}{24}:\frac{\left(-9\right)^2}{4^2}\)

\(=\frac{27\times16}{24\times81}=\frac{2}{9}\)

bài 2: Các số đó là :

           -2012 , -2011 , -2010 ,  ....., 0, 1 , ..., 2012

                Tổng cá số đó là 0

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