1.tìm các cặp phân số = nhau trong các phân số sau đây:

\(\frac{-9}{33}\)\(\frac{15}{9}\)\(\frac{3}{-11}\)\(\frac{-12}{19}\)\(\frac{5}{3}\)\(\frac{60}{-95}\)

2.trong các phân số sau đây ,tìm phân số ko =phân số nào trong các phân số còn lại :

\(\frac{ }{\frac{-7}{42}\frac{12}{18}\frac{3}{-18}\frac{-9}{54}\frac{-10}{-15}\frac{14}{20}}\)

3.điền số thích hợp vào ô trống:

\(\frac{2}{3}\)₌ \(\frac{ }{60}\);\(\frac{3}{4}\)= \(\frac{ }{60}\);\(\frac{4}{5}\)=\(\frac{ }{60}\);\(\frac{5}{6}\)=\(\frac{ }{60}\)

a,{3849-2.[146-(2.14+6:2)]}.32

b,134-2.{156-6[54-2.(9+6)]}

c,\(\frac{5}{7}\).\(\frac{12}{11}\)+\(\frac{5}{7}\).\(\frac{17}{11}\)-\(\frac{5}{7}\).\(\frac{18}{11}\)+2\(\frac{1}{3}\)

d,\(\frac{2}{3}\)+\(\frac{3}{5}\)+\(\frac{5}{3}\)-\(\frac{1}{5}\)+1

e,\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+\(\frac{1}{30}\)+\(\frac{1}{42}\)+\(\frac{1}{56}\)+\(\frac{1}{72}\)(Lưu ý chỉ phân số \(\frac{1}{72}\)mới có thể quy đồng)

Tính a) (4 \(\frac{5}{37}\)- 3\(\frac{4}{5}\)+8\(\frac{15}{29}\)) - (3\(\frac{5}{37}\)- 6\(\frac{14}{29}\)

b) 60 \(\frac{7}{13}\)x (8\(\frac{7}{10}\)) +50\(\frac{8}{13}\)x (-8 \(\frac{7}{10}\)) - 11 \(\frac{2}{13}\)x (-8 \(\frac{7}{10}\)

c) (2 \(\frac{5}{6}\)+ 1\(\frac{4}{9}\)) : ( 10 \(\frac{1}{2}\)- 9 \(\frac{1}{2}\)

d) 1 \(\frac{5}{18}\)- \(\frac{5}{18}\)x (\(\frac{1}{15}\)+1\(\frac{1}{12}\))

e)\(\frac{-1}{7}\)x (9 \(\frac{1}{2}\) - 8,75) :\(\frac{2}{7}\) +0,625 :1 \(\frac{2}{3}\)

cau 1: So sanh cac day p/s

  a) \(\frac{1}{2}\),\(\frac{-2}{3}\),\(\frac{3}{4}\),\(\frac{-4}{5}\)

  b) \(\frac{1}{2}\),\(\frac{3}{5}\),\(\frac{-4}{3}\),\(\frac{-9}{8}\)

  c) \(\frac{3}{2}\),\(\frac{3}{4}\),\(\frac{4}{5}\)\(\frac{-7}{20}\)

  d) \(\frac{1}{2}\),\(\frac{-2}{3}\)\(\frac{5}{6}\),\(\frac{-7}{18}\)

Cau 2:

[6+\(\left(\frac{1}{2}\right)^3\)_\(\left|-\frac{1}{2}\right|\)]:\(\frac{3}{12}\)

\(\frac{18}{37}\)+\(\frac{8}{24}\)+\(\frac{19}{37}\)_\(1\frac{23}{24}\)+\(\frac{2}{3}\)

lm giup mk nhe mk minh se tick cho bn cam on

bài 2:

a,\(6\frac{4}{5}\)-(\(1\frac{2}{3}\)+\(3\frac{4}{5}\))

b,\(6\frac{5}{7}\)-(\(1\frac{3}{4}\)+\(2\frac{5}{7}\))

c,\(7\frac{5}{9}\)-(\(2\frac{3}{4}\)+\(3\frac{5}{9}\))

d,\(7\frac{5}{11}\)-(\(2\frac{3}{7}\)+\(3\frac{5}{11}\))

e,\(\frac{-3}{5}\).\(\frac{5}{7}\)+\(\frac{-3}{5}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)

f,\(\frac{1}{3}\).\(\frac{4}{5}\)+\(\frac{1}{3}\).\(\frac{6}{5}\)-\(\frac{4}{3}\)

g,\(\frac{4}{19}\).\(\frac{-3}{7}\)+\(\frac{-3}{7}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)

h,\(\frac{5}{9}\).\(\frac{7}{13}\)+\(\frac{5}{9}\).\(\frac{9}{13}\)-\(\frac{5}{9}\).\(\frac{3}{13}\)

mn ơi,giúp mk với ạ,mk cần gấp

Câu 1 : Tính

a) \(\frac{2}{3}\)+\(\frac{1}{3}\)x ( \(\frac{-4}{9}\)+\(\frac{5}{6}\)) : \(\frac{7}{12}\)

b) S = \(\frac{1}{2}\)x \(\frac{1}{3}\)+\(\frac{1}{3}\)x\(\frac{1}{4}\)+\(\frac{1}{4}\)x\(\frac{1}{5}\)+\(\frac{1}{5}\)x\(\frac{1}{6}\)+\(\frac{1}{6}\)x\(\frac{1}{7}\)+\(\frac{1}{7}\)x\(\frac{1}{8}\)+\(\frac{1}{8}\)x\(\frac{1}{9}\)

c) A = \(\frac{5}{5.7}\)+\(\frac{5}{7.9}\)+...+\(\frac{5}{59.61}\)

d) M = \(\frac{3}{4}\)x\(\frac{8}{9}\)x\(\frac{15}{16}\)x\(\frac{24}{25}\)x...x\(\frac{99}{100}\)

e) N = \(\frac{1}{2}\)x\(\frac{-2}{3}\)x\(\frac{3}{4}\)x\(\frac{-4}{5}\)x\(\frac{5}{6}\)x\(\frac{-6}{7}\)x...x\(\frac{-98}{99}\)x\(\frac{99}{100}\)

[ Các bạn trả lời cách tính nhanh mà đúng nhá :)) ]

[ Cảm ơn các bạn nhiều <3 ]

Tính hợp lý (nếu được)

\(a\) \(19\frac{5}{8}\)\(:\)\(1\frac{5}{7}\)\(-\) \(15\frac{5}{8}\) \(:\) \(\frac{12}{17}\)\(-\)\(1\frac{1}{3}\)

\(b\) \(\frac{2}{5}\)\(.\)\(\frac{1}{3}\)\(-\) \(\frac{2}{15}\)\(:\) \(\frac{1}{5}\)\(+\) \(\frac{3}{5}\)\(.\) \(\frac{1}{3}\)

\(c\)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)

\(f\)\(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)

\(g\)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}.\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\)

\(h\)\(\frac{4}{9}.19\frac{1}{3}-\frac{4}{9}.39\frac{1}{3}\)

\(k\)\(125\%.\left(\frac{-1}{2}\right)^2:\left(1\frac{5}{16}-1,5\right)+2008^0\)

\(m\)\(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

Làm bao nhiêu cũng được nha, càng nhiều càng tốt

bài 1

a,\(\frac{x}{5}\)=\(\frac{2}{3}\)

b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)

c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)

d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)

e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)

h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)

i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)

k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)

l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)

m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)

n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)

p,(3x-1)(\(-\frac{1}{2}\)x+5)=0

q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)

s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)

t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)

u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)

mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<

So sánh hai phân số: \(\frac{-7}{31}va\frac{6}{31}\);\(\frac{-97}{128}va\frac{-99}{128}\) ;\(\frac{3}{7}va\frac{-6}{7}\);\(\frac{2}{5}va\frac{4}{5}\)\(\frac{-2}{5}va\frac{13}{5}\)\(\frac{4}{9}va\frac{7}{9}\)\(\frac{5}{12}va\frac{7}{12}\)\(\frac{-7}{15}va\frac{-8}{15}\)\(\frac{-2}{5}va\frac{4}{5}\)\(\frac{4}{7}va\frac{3}{7}\)\(\frac{-11}{13}va\frac{-15}{13}\)\(\frac{-2}{7}va\frac{-4}{14}\)\(\frac{_{-5}}{7}va\frac{-10}{7}\)\(\frac{-13}{5}va\frac{1}{5}\)\(\frac{-6}{7}va\frac{-3}{7}\)\(\frac{3}{7}va\frac{5}{7}\)\(\frac{-7}{9}va\frac{-5}{9}\)\(\frac{-3}{7}va\frac{-5}{7}\)\(\frac{-13}{9}va\frac{1}{9}\) so sánh số cùng mẫu số \(\frac{-7}{13};\frac{-4}{13}\) \(\frac{1}{7};\frac{-4}{-7}\)