1.Tìm x, biết:

a.\(\frac{1}{2}\)x\(x\)+\(\frac{2}{3}\)=\(\frac{5}{2}\)

b.\(\frac{x}{12}\)+\(\frac{5}{24}\)=\(\frac{5}{6}\)

c.(1234+\(x\)+766)x0,25=6,2:0,01

2.Tính bằng cách hợp lý.

A=\(\frac{1}{2}\)x\(\frac{5}{7}\)+\(\frac{9}{7}\)x0,3+\(\frac{1}{2}\)x\(\frac{4}{7}\)+\(\frac{9}{4}\)+\(\frac{9}{7}\)x0.2

B=\(\frac{2002\cdot15-1}{2001+2002\cdot14}\)

1.Tìm x, biết:

a.\(\frac{1}{2}\)x\(x\)+\(\frac{2}{3}\)=\(\frac{5}{2}\)

b.\(\frac{x}{12}\)+\(\frac{5}{24}\)=\(\frac{5}{6}\)

c.(1234+\(x\)+766)x0,25=6,2:0,01

2.Tính bằng cách hợp lý.

A=\(\frac{1}{2}\)x\(\frac{5}{7}\)+\(\frac{9}{7}\)x0,3+\(\frac{1}{2}\)x\(\frac{4}{7}\)+\(\frac{9}{4}\)+\(\frac{9}{7}\)x0.2

B=\(\frac{2002\cdot15-1}{2001+2002\cdot14}\)

CÁC BẠN YÊU QUÝ AK ,MÌNH THẤY TRONG OLM BẠN NÀO CŨNG THÔNG MINH CẢ ,BẠN NÀO BIẾT CÁNH LÀM GIẢI CHO MÌNH VỚI
a) \(\frac{24}{x}\):\(\frac{8}{3}\)=\(\frac{3}{5}\)
b) x+\(3\frac{1}{2}\)+x=\(24\frac{1}{4}\)
c)\(\frac{x}{27}\)-\(\frac{2}{9}\)=\(\frac{6}{18}\)
d) \(\frac{15}{26}\)+\(\frac{x}{13}\)=\(\frac{46}{52}\)
 

\(8\frac{7}{10}\)+\(2\frac{3}{4}\)=

\(2\frac{7}{8}\)-\(1\frac{3}{8}\)=

\(3\frac{1}{3}\)x\(2\frac{4}{5}\)=

\(4\frac{1}{2}\):\(2\frac{1}{7}\)=

\(2\frac{1}{5}\)+\(1\frac{7}{10}\)=

\(8\frac{1}{4}\)-\(5\frac{1}{2}\)=

\(3\frac{4}{5}\)x\(\frac{10}{21}\)=

\(1\frac{4}{7}\):\(2\frac{3}{8}\)

93 : x + 87 : x - 66 : x = 38

1\(\frac{1}{3}\): ( 1 \(\frac{2}{3}\)- x ) = \(\frac{8}{7}\)

\(\frac{1}{2}\)+ x : \(\frac{1}{6}\)= 2

( \(\frac{4}{5}\)+ \(\frac{3}{10}\)- \(\frac{1}{3}\)) 6 × \(\frac{4}{7}\)

( 8 × \(\frac{2}{3}\): \(\frac{1}{2}\)) × \(\frac{5}{8}\)- 3 \(\frac{1}{3}\)

Mình cần gấp

1.

\(\frac{1}{2}\)+\(\frac{2}{3}\)+\(\frac{3}{4}\)

\(\frac{4}{5}\)+\(\frac{4}{3}\)+\(\frac{6}{7}\)

\(\frac{1}{4}\)+\(\frac{2}{5}\)+\(\frac{1}{3}\)

\(\frac{3}{5}\)+\(\frac{5}{6}\)+\(\frac{7}{9}\)

\(\frac{8}{9}\)-\(\frac{5}{6}\)

\(\frac{99}{108}\)-\(\frac{40}{72}\)

\(\frac{16}{17}\)-\(\frac{12}{13}\)

\(\frac{99}{153}\)-\(\frac{75}{125}\)