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a,\(\frac{21}{25}.\frac{11}{9}.\frac{5}{7}=\frac{21.11.5}{25.9.7}=\frac{3.7.11.5}{5^2.3^2.7}=\frac{11}{5.3}=\frac{11}{15}\)
b,\(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)
c, \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}=1-\frac{29}{15}=-\frac{14}{15}\)
a , \(\frac{21}{25}\times\frac{11}{9}\times\frac{5}{7}\)
\(=\frac{21\times11\times5}{25\times9\times7}\)
\(=\frac{3\times7\times11\times5}{5\times5\times3\times3\times7}\)
\(=\frac{11}{5\times3}\)
\(=\frac{11}{15}\)
b , \(\frac{5}{23}\times\frac{17}{26}+\frac{5}{23}\times\frac{9}{26}\)
\(=\frac{5}{23}\times\left(\frac{17}{26}+\frac{9}{26}\right)\)
\(=\frac{5}{23}\times\frac{26}{26}\)
\(=\frac{5}{23}\times1\)
\(=\frac{5}{23}\)
c , \(\left(\frac{3}{29}-\frac{1}{5}\right)\times\frac{29}{3}\)
\(=\frac{3}{29}\times\frac{29}{3}-\frac{1}{5}\times\frac{29}{3}\)
\(=1-\frac{29}{15}\)
\(\frac{5}{23}x\left(\frac{17}{26}+\frac{9}{26}\right)\)=\(\frac{5}{23}x\frac{26}{26}\)=\(\frac{5}{23}x1\)=\(\frac{5}{23}\)
\(\frac{5}{23}\)x \(\frac{17}{26}+\frac{5}{23}\)x \(\frac{9}{26}\)
=\(\frac{5}{23}\left(\frac{17}{26}+\frac{9}{26}\right)\)
=\(\frac{5}{23}\)x \(\frac{26}{26}\)
=\(\frac{5}{23}\)x 1
=\(\frac{5}{23}\)
a) \(x-\frac{10}{3}=\frac{7}{15}\cdot\frac{3}{5}\) b) \(x+\frac{3}{22}=\frac{27}{121}\cdot\frac{11}{9}\)
\(\Leftrightarrow x-\frac{10}{3}=\frac{7}{25}\) \(\Leftrightarrow x+\frac{3}{22}=\frac{3}{11}\)
\(\Rightarrow x=\frac{7}{25}+\frac{10}{3}\) \(\Rightarrow x=\frac{3}{11}-\frac{3}{22}\)
\(x=\frac{271}{75}\) \(x=\frac{3}{22}\)
c) \(\frac{8}{23}.\frac{46}{24}-x=\frac{1}{3}\) d) \(1-x=\frac{49}{65}.\frac{5}{7}\)
\(\Leftrightarrow\frac{2}{3}-x=\frac{1}{3}\) \(\Leftrightarrow1-x=\frac{7}{13}\)
\(\Rightarrow x=\frac{2}{3}-\frac{1}{3}\) \(\Rightarrow x=1-\frac{7}{13}\)
\(x=\frac{1}{3}\) \(x=\frac{6}{13}\)
a,\(\frac{7.9-14}{3-17}=\frac{63-14}{-14}=\frac{49}{-14}=\frac{7}{-2}\)
b,\(\frac{14}{9}\) c,\(0\)
k mình nha đồng thời kb hihi
\(A=\frac{17}{23}\cdot\frac{8}{16}\cdot\frac{23}{17}\cdot\left(-80\right)\cdot\frac{3}{4}\)\(=\frac{17\cdot4\cdot2\cdot23\cdot16\cdot\left(-5\right)\cdot3}{23\cdot16\cdot17\cdot4}\)
=> \(A=\frac{2\cdot\left(-5\right)\cdot3}{1}=-30\)
\(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\left(\frac{1}{3}+\frac{1}{4}-\frac{7}{12}\right)\)
=> \(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\left(\frac{7}{12}-\frac{7}{12}\right)\)
=> \(B=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right)\cdot0=0\)
a)\(A=\frac{17}{23}.\frac{8}{16}.\frac{23}{17}.\left(-80\right).\frac{3}{4}\)
\(A=\left(\frac{17}{23}.\frac{23}{17}\right).\left(\frac{8}{16}.\frac{3}{4}\right).\left(-80\right)\)
\(A=\frac{3}{8}.\left(-80\right)\)
\(A=-30\)
b)\(C=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).\left(\frac{1}{3}+\frac{1}{4}-\frac{7}{12}\right)\)
\(C=\left(\frac{13}{23}+\frac{1313}{2323}-\frac{131313}{232323}\right).0\)
\(C=0\)
=-11/23(6/7+8/7)-1/23
=-11/23.2-1/23
=-22/23-1/23
=-1
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Câu a:
A = (1\(\frac16\) x \(\frac67\) x 6 : \(\frac35\)) : (4\(\frac15\) x \(\frac{10}{11}\) + 5\(\frac{2}{10}\))
A = (7/6 x 6/7 x 6 x 5/3) :(21/5 x 10/11 + 52/10)
A = (1 x 6 x 5/3) : (210/55 + 26/5)
A = 10 : (210/55 + 286/55)
A = 10 : (496/55)
A = 10 x 55/496
A = 275/248
Câu b:
B = \(1\)\(\frac{13}{15}\) x 25% x 3 + (8/15 - 79/60) : 1\(\frac{23}{4}\)
B = 28/15 x 1/4 x 3 + (32/60 - 79/60) : 27/4
B = 7/15 x 3 - 47/60 x 4/27
B = 7/5 - 47/405
B = 104/81
\(\dfrac{9}{23}\) x \(\dfrac{5}{8}\) + \(\dfrac{9}{23}\) x \(\dfrac{3}{8}\) - \(\dfrac{9}{23}\)= \(\dfrac{9}{23}\) x \(\left(\dfrac{5}{8}+\dfrac{3}{8}\right)-\dfrac{9}{23}\)
\(=\dfrac{9}{23}\) x \(1\) \(-\dfrac{9}{23}\)
\(=0\)
thanks
Thank you,Khanh!