1.tính nhanh nếu có thể

a)\(\frac{4}{11}\)-\(\frac{7}{15}\)+\(\frac{7}{11}\)-\(\frac{5}{15}\)

b)\(\frac{7}{3}\)-\(\frac{4}{9}\)-\(\frac{1}{3}\)-\(\frac{5}{9}\)

c)\((\frac{-1}{4}\)+\(\frac{7}{33}\)-\(\frac{5}{3}\)\()\)

d)\(\frac{-3}{4}\)\(\times\frac{8}{11}\)-\(\frac{3}{11}\)\(\times\frac{1}{2}\)

e)\(\frac{1}{15}\)+\(\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)

bài 1: tính hợp lí

 A = \(\frac{1}{3}\). \(\frac{-6}{13}\) . \(\frac{-9}{10}\) . \(\frac{-13}{36}\)

B = \(\frac{-5}{12}\) .  \(\frac{4}{19}\)+ \(\frac{-7}{12}\) . \(\frac{4}{19}\) - \(\frac{40}{57}\)

C = \(\frac{3}{7}\) . \(\frac{9}{26}\) - \(\frac{1}{14}\) . \(\frac{1}{13}\) - \(\frac{1}{7}\)

D = \(\frac{1}{3}\) . \(\frac{4}{5}\) + \(\frac{1}{3}\) . \(\frac{6}{5}\) + \(\frac{2}{3}\)

Ai làm nhanh mình tik, giải rõ giúp mình, mình đang cần gấp, cảm ơn

bài 2:

a,\(6\frac{4}{5}\)-(\(1\frac{2}{3}\)+\(3\frac{4}{5}\))

b,\(6\frac{5}{7}\)-(\(1\frac{3}{4}\)+\(2\frac{5}{7}\))

c,\(7\frac{5}{9}\)-(\(2\frac{3}{4}\)+\(3\frac{5}{9}\))

d,\(7\frac{5}{11}\)-(\(2\frac{3}{7}\)+\(3\frac{5}{11}\))

e,\(\frac{-3}{5}\).\(\frac{5}{7}\)+\(\frac{-3}{5}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)

f,\(\frac{1}{3}\).\(\frac{4}{5}\)+\(\frac{1}{3}\).\(\frac{6}{5}\)-\(\frac{4}{3}\)

g,\(\frac{4}{19}\).\(\frac{-3}{7}\)+\(\frac{-3}{7}\).\(\frac{15}{19}\)+\(\frac{5}{7}\)

h,\(\frac{5}{9}\).\(\frac{7}{13}\)+\(\frac{5}{9}\).\(\frac{9}{13}\)-\(\frac{5}{9}\).\(\frac{3}{13}\)

mn ơi,giúp mk với ạ,mk cần gấp

Tính hợp lý (nếu được)

\(a\) \(19\frac{5}{8}\)\(:\)\(1\frac{5}{7}\)\(-\) \(15\frac{5}{8}\) \(:\) \(\frac{12}{17}\)\(-\)\(1\frac{1}{3}\)

\(b\) \(\frac{2}{5}\)\(.\)\(\frac{1}{3}\)\(-\) \(\frac{2}{15}\)\(:\) \(\frac{1}{5}\)\(+\) \(\frac{3}{5}\)\(.\) \(\frac{1}{3}\)

\(c\)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)

\(f\)\(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)

\(g\)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}.\left(4,5-2\right)+\frac{2^3}{\left(-4\right)}\)

\(h\)\(\frac{4}{9}.19\frac{1}{3}-\frac{4}{9}.39\frac{1}{3}\)

\(k\)\(125\%.\left(\frac{-1}{2}\right)^2:\left(1\frac{5}{16}-1,5\right)+2008^0\)

\(m\)\(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)

Làm bao nhiêu cũng được nha, càng nhiều càng tốt

\(\frac{4}{3.6}\)+ \(\frac{4}{6.9}\)+ \(\frac{4}{9.12}\)+\(\frac{4}{12.15}\)

= 4(\(\frac{1}{3.6}\)+\(\frac{1}{6.9}\)+\(\frac{1}{9.12}\)+\(\frac{1}{12.15}\))

=\(\frac{4}{3}\)( \(\frac{1}{3}-\frac{1}{6}+\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+\frac{1}{12}-\frac{1}{15}\) )

=\(\frac{4}{3}\)(\(\frac{1}{3}-\frac{1}{15}\))

=\(\frac{4}{3}\).\(\frac{4}{15}\)

=\(\frac{16}{45}\)

mk làm đúng chưa

\(19\frac{5}{8}\): \(\frac{7}{12}\)- \(15\frac{1}{4}\): \(\frac{7}{12}\)

\(\frac{2}{5}\). \(\frac{1}{3}\)-\(\frac{2}{15}\): \(\frac{1}{5}\)+\(\frac{3}{5}\). \(\frac{1}{3}\)

\(\frac{4}{9}\). \(19\frac{1}{3}\)- \(\frac{4}{9}\). \(39\frac{1}{3}\)

tính hợp lí .giúp mk với ạ.cảm ơn mọi người nhiều

Câu 1 : Tính

a) \(\frac{2}{3}\)+\(\frac{1}{3}\)x ( \(\frac{-4}{9}\)+\(\frac{5}{6}\)) : \(\frac{7}{12}\)

b) S = \(\frac{1}{2}\)x \(\frac{1}{3}\)+\(\frac{1}{3}\)x\(\frac{1}{4}\)+\(\frac{1}{4}\)x\(\frac{1}{5}\)+\(\frac{1}{5}\)x\(\frac{1}{6}\)+\(\frac{1}{6}\)x\(\frac{1}{7}\)+\(\frac{1}{7}\)x\(\frac{1}{8}\)+\(\frac{1}{8}\)x\(\frac{1}{9}\)

c) A = \(\frac{5}{5.7}\)+\(\frac{5}{7.9}\)+...+\(\frac{5}{59.61}\)

d) M = \(\frac{3}{4}\)x\(\frac{8}{9}\)x\(\frac{15}{16}\)x\(\frac{24}{25}\)x...x\(\frac{99}{100}\)

e) N = \(\frac{1}{2}\)x\(\frac{-2}{3}\)x\(\frac{3}{4}\)x\(\frac{-4}{5}\)x\(\frac{5}{6}\)x\(\frac{-6}{7}\)x...x\(\frac{-98}{99}\)x\(\frac{99}{100}\)

[ Các bạn trả lời cách tính nhanh mà đúng nhá :)) ]

[ Cảm ơn các bạn nhiều <3 ]

bài 1

a,\(\frac{x}{5}\)=\(\frac{2}{3}\)

b,\(\frac{x}{3}\)-\(\frac{1}{2}\)=\(\frac{1}{5}\)

c,\(\frac{x}{5}\)+\(\frac{1}{2}\)=\(\frac{6}{10}\)

d,\(\frac{x+3}{15}\)=\(\frac{1}{3}\)

e,\(\frac{x-12}{4}\)=\(\frac{1}{2}\)

h,\(\frac{4}{5}\)+x=\(\frac{2}{3}\)

i,\(\frac{3}{4}\)-x=\(\frac{1}{3}\)

k,\(\frac{-5}{6}\)-x=\(\frac{2}{3}\)

l,x-\(\frac{5}{9}\)=\(\frac{-2}{3}\)

m,\(\frac{1}{2}\)x+\(\frac{1}{2}\)=\(\frac{5}{2}\)

n,\(\frac{-2}{3}\)-\(\frac{1}{3}\)(2x-5)=\(\frac{3}{2}\)

p,(3x-1)(\(-\frac{1}{2}\)x+5)=0

q,\(3\frac{1}{3}\)+\(\frac{5}{6}\)x=\(3\frac{1}{2}\)

s,\(\frac{1}{2}\)-\(\frac{2}{3}\)x=\(\frac{7}{12}\)

t,\(\frac{3}{4}\)x+\(\frac{1}{5}\)=\(\frac{1}{6}\)

u,\(\frac{3}{8}\)-\(\frac{1}{6}\)x=\(\frac{1}{4}\)

mn ơi'-' xin hãy giúp mk với ạ>^<,mk cần rất gấp,mai nộp r ạ,mong mn giúp mk với ạ:(( huhuhu r mk tik cho:<<