tic cho mình hết âm nhé

cái nào đúng zậy các bạn

1=5 =>5=1 ^-^

5=25 cho mik nha

2

kick

kb

Bạn làm ơn gõ có dấu được không? Mình chẳng hiểu gì cả?

Mình chỉ trả lời được: Mình rất muốn kết bạn với bạn

Mình thích chứ không hâm mộ khởi my

Còn cái còn lại thì mình không hiểu?

 mất dép và mất dạy

bpt tuong duong voi: 
{ x - 1 > 0 
{ x - 3 > 0 
hoac 
{ x - 1 < 0 
{x - 3 < 0 
<=> 
{ x > 1 
{ x > 3 
hoac 
{ x < 1 
{ x < 3 
<=> x>3 hoac x <1 k mik nha

2x^2 + 0,82 = 1

2x^2 = 0,18

x^2 = 0,09

=> x = -0,3 hoặc 0,3

cho mik nha chế

X=-0,3 HOAC 0,3

a) \(\left(x-\dfrac{1}{2}\right)^2=0\)

\(\Rightarrow x-\dfrac{1}{2}=0\)

\(\Rightarrow x=\dfrac{1}{2}\)

b) \(\left(x-2\right)^2=1\)

\(\Rightarrow x-2=1\)

\(\Rightarrow x=3\)

c) \(\left(2x-1\right)^3=-8\)

\(\Rightarrow\left(2x-1\right)^3=\left(-2\right)^3\)

\(\Rightarrow2x-1=-2\)

\(\Rightarrow2x=-1\)

\(\Rightarrow x=\dfrac{-1}{2}\)

d) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)

\(\Rightarrow\left(x+\dfrac{1}{2}\right)^2=\left(\dfrac{1}{4}\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{4}\\x+\dfrac{1}{2}=-\dfrac{1}{4}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-1}{4}\\x=\dfrac{-3}{4}\end{matrix}\right.\).

a , \(\left(x-\dfrac{1}{2}\right)^2=0\)

<=> \(x-\dfrac{1}{2}=0\Rightarrow x=\dfrac{1}{2}\)

b , \(\left(x-2\right)^2=1\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

c , \(\left(2x-1\right)^3=-8\Rightarrow2x-1=-2\Rightarrow x=\dfrac{-1}{2}\)

d , \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{4^2}\)

<=> \(\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{4}\\x+\dfrac{1}{2}=\dfrac{-1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{4}\\x=\dfrac{-3}{4}\end{matrix}\right.\)

a, Ta có: 

\(M=\frac{1}{11.13}+\frac{1}{13.15}+...+\frac{1}{33.35}\)

\(=\frac{1}{2}\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{33}-\frac{1}{35}\right)\)

\(=\frac{1}{2}\left(\frac{1}{11}-\frac{1}{35}\right)=\frac{1}{2}\cdot\frac{24}{385}=\frac{12}{385}\)

\(N=\frac{12}{11.13.15}+\frac{12}{13.15.17}+...+\frac{12}{31.33.35}\)

\(=3\left(\frac{1}{11.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.17}+...+\frac{1}{31.33}-\frac{1}{33.35}\right)\)

\(=3\left(\frac{1}{11.13}-\frac{1}{33.35}\right)=3\cdot\frac{92}{15015}=\frac{92}{5005}\)

\(\Rightarrow M:N=\frac{12}{385}:\frac{92}{5005}=\frac{39}{23}\)

b, \(S=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2011}-\frac{1}{2012}+\frac{1}{2013}\)

\(=\left(1+\frac{1}{3}+...+\frac{1}{2011}+\frac{1}{2013}\right)-\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2012}\right)\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}\right)-2\left(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{2012}\right)\)

\(=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}-\left(1+\frac{1}{2}+...+\frac{1}{1006}\right)\)

\(=\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\)

\(\Rightarrow S-P-1=\left(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\right)-\left(\frac{1}{1007}+\frac{1}{1008}+...+\frac{1}{2013}\right)-1=0-1=-1\)

cam on nha