a) (-2)+ (-5) = -7

Vì: -7< -5

=> (-2)+ (-5) < -7

b) (-3)+ (-8)= -11

Vì: (-10) > (-11)

=> -10> (-3)+ (-8)

a)(-2)+(-5)<(-5)

b)(-10)>(-3)+(-8)

ĐS. a) b) ;

c) ; d)

a)( -11) .(8.9)= (-11) .8 - (-11) .9= 11

b) (-12).10 - (-9) . 10= [ -12 - (-9) ] . 10 = -30

a) \(\left(-11\right)\cdot\left(8-9\right)=\left(-11\right)\cdot8-\left(-11\right)\cdot9=11\)

b) \(\left(-12\right)\cdot10-\left(-9\right)\cdot10=\left[-12-\left(-9\right)\right]\cdot10=-30\)

Coi phân số phải tìm là x rồi vận dụng quy tắc chuyển vế để tìm x.

Chẳng hạn:

\(c)\) \(\dfrac{1}{4}-x=\dfrac{1}{20}\) . Chuyển vế thì ta đc :

\(x=\dfrac{1}{5}\)

Đáp số:

\(a)-\dfrac{3}{4}\)

b) \(\dfrac{11}{15}\)

c) \(\dfrac{1}{5}\)

d) \(-\dfrac{8}{13}\)

a. \(\dfrac{6}{12}\)

b.\(\dfrac{-5}{-7}\)

c.\(\dfrac{-7}{8}\)

d.\(\dfrac{3}{-6}\)

a)6/12

b)-5/-7

c)-7/8

d)3/-6

Ta có:

                \(\frac{a}{b}=\frac{a\times\left(b+m\right)}{b\times\left(b+m\right)}=\frac{a\times b+a\times m}{b\times b+b\times m}\)

                \(\frac{a+m}{b+m}=\frac{\left(a+m\right)\times b}{\left(b+m\right)\times b}=\frac{a\times b+m\times b}{b\times b+b\times m}\)

vì \(\frac{a}{b}>1\) nên \(a>b\), ta suy ra \(a\times m>b\times m\)

hay \(a\times b+a\times m>a\times b+m\times b\)

hay \(\frac{a\times b+a\times m}{b\times b+b\times m}>\frac{a\times b+m\times b}{b\times b+b\times m}\)

hay \(\frac{a}{b}>\frac{a+m}{b+m}\)

Vì \(\frac{a}{b}>1\)

=> a > b

=> a.m > b.m

=> a.m + a.b > b.m + a.b

=> a.(b + m) > b.(a + m)

=> \(\frac{a}{b}>\frac{a+m}{b+m}\)

\(a\)) \(3< 5\)

\(b\)) \(-3>-5\)

\(c\))\(4>-6\)

\(d\)) \(10>-10\)

a) 3 _< 5

b) -3 > -5

c) 4 > -6

d) 10 > -10

a, \(\frac{3}{8}+\frac{11}{13}-\frac{9}{13}\)

  =\(\frac{3}{8}+\frac{2}{13}\)

  =\(\frac{55}{104}.\)

b, \(\frac{2}{7}.\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{2}{7}\)

  =\(\frac{2}{7}.\frac{9}{9}+\frac{2}{7}\)

  =\(\frac{2}{7}+\frac{2}{7}\)

  =\(\frac{4}{7}\)

c, \(\frac{3}{11}.\left(\frac{3}{5}-\frac{5}{3}\right)-\frac{3}{10}.\left(\frac{1}{3}-\frac{2}{5}\right)\)

  =\(\frac{3}{11}.-\frac{16}{15}-\frac{3}{10}.-\frac{1}{15}\)

  =\(-\frac{16}{55}--\frac{1}{50}\)

  =\(-\frac{149}{550}.\)

d, \(\frac{-3}{4}.\frac{11}{23}+\frac{3}{23}.\frac{31}{17}-\frac{3}{17}.\frac{19}{23}\)

  =\(-\frac{33}{92}+\frac{93}{391}-\frac{57}{391}\)

  =\(-\frac{417}{1564}\)

e, \(\frac{3}{17}.\frac{11}{23}+\frac{3}{23}.\frac{31}{17}-\frac{3}{17}.\frac{19}{23}\)

  =\(\frac{33}{391}+\frac{93}{391}--\frac{254}{391}\)

  =\(\frac{380}{391}.\)

g, \(\frac{3}{7}.\frac{-5}{12}+\frac{11}{17}:\frac{5}{-12}\)

  =\(-\frac{5}{28}+-\frac{132}{85}\)

  = \(-1.731512605.\)

k cho mình nha làm mỏi tay quá ,.....................kết bạn với mình nha.......................

THANK  Ngô Bùi Hoa  làm cho mình bài 2 với 

a) \(\dfrac{3}{4}=\dfrac{15}{20}\)

b) \(\dfrac{4}{5}=\dfrac{12}{15}\)

c) \(\dfrac{-4}{9}=\dfrac{-16}{36}\)

d) \(\dfrac{7}{-13}=\dfrac{21}{-39}\)

a ) \(\dfrac{3}{4}\)= \(\dfrac{15}{20}\)

b )\(\dfrac{4}{5}\)= \(\dfrac{12}{15}\)

c) \(\dfrac{-4}{9}\)=\(\dfrac{-16}{36}\)

d) \(\dfrac{7}{-13}\)=\(\dfrac{21}{-39}\)