BẠN LẤY CÁI 5/30+45/270 NHA

NHỚ K NHA

=13/12x14/13x15/14x16/15x...x2006/2005x2007/2006x2008/2007

=2008/12

=502/3

A = 1\(\dfrac{1}{12}\) \(\times\) 1\(\dfrac{1}{13}\) \(\times\) 1\(\dfrac{1}{14}\) \(\times\) 1\(\dfrac{1}{15}\) \(\times\) ... \(\times\) 1\(\dfrac{1}{2005}\) \(\times\) 1\(\dfrac{1}{2006}\) \(\times\) 1\(\dfrac{1}{2007}\)

A = ( 1 + \(\dfrac{1}{12}\)) \(\times\) ( 1 + \(\dfrac{1}{13}\)) \(\times\) ( 1 + \(\dfrac{1}{14}\)) \(\times\)...\(\times\) ( 1 + \(\dfrac{1}{2006}\))\(\times\)(1+\(\dfrac{1}{2007}\))

A = \(\dfrac{13}{12}\) \(\times\) \(\dfrac{14}{13}\) \(\times\) \(\dfrac{15}{14}\) \(\times\) ...\(\times\) \(\dfrac{2007}{2006}\) \(\times\) \(\dfrac{2008}{2007}\)

A = \(\dfrac{13\times14\times15\times...\times2007}{13\times14\times15\times...\times2007}\) \(\times\) \(\dfrac{2008}{12}\)

A = 1 \(\times\) \(\dfrac{502}{3}\)

A = \(\dfrac{502}{3}\)

a) \(\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{10}{15}+\dfrac{9}{15}=\dfrac{19}{15}\)

a) \(\dfrac{7}{12}-\dfrac{2}{7}+\dfrac{1}{12}=\dfrac{2}{3}-\dfrac{2}{7}=\dfrac{14}{21}-\dfrac{6}{21}=\dfrac{8}{21}\)

Ta có công thức tổng quát: 

\(\dfrac{k}{n\cdot\left(n+k\right)}=\dfrac{1}{n}-\dfrac{1}{n+k}\)

\(a,A=\dfrac{1}{5\cdot8}+\dfrac{1}{8\cdot11}+...+\dfrac{1}{x\left(x+3\right)}\\ =\dfrac{1}{3}\left(\dfrac{3}{5\cdot8}+\dfrac{3}{8\cdot11}+...+\dfrac{3}{x\left(x+3\right)}\right)\\ =\dfrac{1}{3}\left(\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+...+\dfrac{1}{x}-\dfrac{1}{x+3}\right)\\ =\dfrac{1}{3}\cdot\left(\dfrac{1}{5}-\dfrac{1}{x+3}\right)\\ =\dfrac{1}{3}\cdot\dfrac{x-2}{5\left(x+3\right)}\\ =\dfrac{x-2}{15\left(x+3\right)}\)

Theo đề bài ta có: 

\(A=\dfrac{101}{1540}\\ \Rightarrow\dfrac{x-2}{15\left(x+3\right)}=\dfrac{101}{1540}\\ \Rightarrow\dfrac{x-2}{x+3}=\dfrac{303}{308}\\ \Rightarrow\dfrac{x-2}{x+3}=\dfrac{305-2}{305+3}\\ \Rightarrow x=305\)

khó nhỉ

/3/5<1   2/2=1     9/4>1   1>7/8

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Bn lớp 5 suy nghĩ đi chứ

Lớp 4 học rồi 

dễ thế mà

 (-3,2) . -15/64 + (0,8 - 34/15) : 7/2

=(-3,2) . -15/64 + -22/15 :7/2

=3/4 + -44/105

=139/420

**** mik nha

\(\frac{3}{7}\cdot\left(\frac{2}{15}+\frac{1}{15}\right)=\frac{2}{15}\cdot\frac{3}{7}+\frac{1}{15}\cdot\frac{8}{7}\)

\(=\frac{3}{7}\cdot\frac{3}{15}\)

\(=\frac{3}{35}\)

=3/35

0,12

0,05

0,306

TL:

\(\frac{12}{100}\)= 0,12

\(\frac{5}{100}\)= 0,05

\(\frac{306}{1000}\)= 0,306

-HT-