Ghi số cụ thể nha (ko ghi phân số)

4C_xH_y(COOH)₂ + (2x+y+2)O₂ -------> (4x+8)CO₂ + (2y+4)H₂O

bạn nào giúp mình với T_T

a) \(C_xH_yCOOH\) + \(\left(x+\frac{y}{4}+\frac{1}{4}\right)O_2\rightarrow\left(x+1\right)CO_2+\left(\frac{y}{2}+\frac{1}{2}\right)H_2O\)

b) \(C_xH_y\left(COOH\right)_2+\left(x+\frac{y}{4}+\frac{1}{2}\right)O_2\rightarrow\left(x+1\right)CO_2+\left(\frac{y}{2}+1\right)H_2O\)

4CxHy(COOH)2 + (2x+y+2)O2 → (2y+4)H2O + (4x+8)CO2

Bn có thể lm chi tiết hơn đc không

2K₃PO₄ + 3MgCl₂ → 6KCl + Mg₃(PO₄)₂

Fe_xO_y + yH₂ → xFe + yH₂O

2C_xH_y + (4x+y)O₂ → 2xCO₂ + yH₂O

2Al + 6HCl → 2AlCl₃ + 3H₂

\(1) Fe_xO_y + (y-x)H_2 \xrightarrow{t^o}xFeO + (y-x)H_2O\\ 2) C_xH_y + (x + \dfrac{y}{4})O_2 \xrightarrow{t^o} xCO_2 + \dfrac{y}{2}H_2O\\ 3) 2KMnO_4 + 16HCl \to 2MnCl_2 + 2KCl + 5Cl_2 + 8H_2O\)

1.\(Fe_xO_y+2yHCl-->xFeCl_{\dfrac{2y}{x}}+yH_2O\)

2.\(2C_xH_y+\left(\dfrac{4x+y}{2}\right)O_2-->2xCO_2+yH_2O\)

3.\(C_nH_{2n}+\dfrac{3n}{2}O_2-->nCO_2+nH_2O\)

4.\(C_nH_{2n+2}+\left(\dfrac{3n+1}{2}\right)O_2-->nCO_2+\left(n+1\right)H_2O\)

5. \(2C_xH_yO_z+\left(\dfrac{4x+y-2z}{2}\right)O_2-->2xCO_2+yH_2O\)

6. (pthh này giống pt 3)