2^2.(1^2+2^2+...+10^2)

4 . 385

1540

A = 2² + 4² + 6² + 8² + ... + 20²

A = 2².(1² + 2² + 3² + 4² + ... + 10²)

A = 4.385

A = 1540

A = 2² + 4² + 6² + 8² + ... + 20²

A = 2² . (1² + 2² + 3² + 4² + ... + 10²)

A = 4 . 385

A = 1540

A = \(2^2.\left(1^2+2^2+3^2+...+10^2\right)=4.385=1540\)

B=\(3^2.\left(1^2+2^2+3^2+...+10^2\right)=385.9=3465\)

\(2^2+4^2+6^2+...+20^2\)

\(=\left(1.2\right)^2+\left(2.2\right)^2+\left(3.2\right)^2+...+\left(10.2\right)^2\)

\(=4\left(1^2+2^2+3^2+...+10^2\right)\)

\(=4.385=1540\)

2^2+4^2 + 6^2 +....+20^2 = 2^2(1+2^2+3^2+...+10^2) = 4 x 385 = 1540

2²+4²+6²+8²+10²+12²+14²+16²+18²+20²

=4+16+36+64+100+144+196+256+324+400

=1540

a: A=3^2(1^2+2^2+...+10^2)

=9*385

=3465

b: B=2^3(1^3+2^3+...+10^3)

=8*3025

=24200

Mình cảm ơn bạn nhiều

Đặt \(A=1^2+2^2+3^2+...+10^2\)

Đặt \(B=2^2+4^2+6^2+...+20^2\)

\(2^2.A=2^2+4^2+6^2+...+20^2=B=2^2.385=1540\)

= 1540          

Ta có: S=2²+4²+6²+...+20²

            =(2.1)²+(2.2)²+(2.3)²+...+(2.10)²

            =2².1²+2².2²+2².3²+...+2².10²

            =2².(1+2²+3²+...+10²)

Mà 1²+2²+3²+...+10²=385 nên:

S=2².385

  =4.385

  =1540

Vậy S=1540

S=2²+4²+6²+...+20²

S=(2*1)²+(2*2)²+(2*3)²+...+(2*10)²

=2²*1²+2²*2²+...+2²*10²=2²(1²+2²+3²+...+10²)=4*385=1540

Vậy S=1540