@Lê Phước Thịnh cứu em

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CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCGCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

D là điểm trên cạnh AC chứ ko phải trên cạnh BC ??nếu nằm trên cạnh bc thì làm sao vẽ hình hả bn

bn tự vẽ hình bài này nha

từ D VẼ DI VUÔNG GÓC VỚI AH TẠI I (I THUỘC AH)MÀ EH VUÔNG GÓC VỚI AH TẠI H SUY RA DI SONG SONG VỚI EH

MÀ TA CŨNG CMĐ DE SONG SONG VỚI IH

TỪ 2 ĐIỀU TRÊN TA CŨNG CMĐ DI=EH 

TA CÓ CAH+HAB=90

MÀ HAB+ABC=90(TG AHB VUÔNG TẠI H)

TỪ 2 ĐIỀU TRÊN SUY RA CAH=ABC

CMĐ TG DIA=AHB(CH GN) SUY RA DI=AH

MÀ DI=EH(CMT)

TƯ 2 ĐIỀU TRÊN SUY A EH=AH

CHỖ NÀO KO HIỂU THÌ HỎI MÌNH

Vì AH vuông góc với BC,DE vuông góc với BC
=>AH//DE
Kẻ DK vuông với AH
Vì AH//DE mà DK⊥AH
=>DK⊥DE
Chứng minh được △KDH = △EHD (cạnh huyền - góc nhọn)=>KD=EH
Mà HA = KD (do △ABH = △DAK) => HE = HA

Nếu ko hiểu đâu bảo mình nhé!

chúc bạn học tốt!!!

desai ha hna256898u

a: ΔAHB vuông tại H

=>AH<AB

b: Xét ΔKAD vuông tại K và ΔHBA vuông tại H có

AD=BA

góc KAD=góc HBA

=>ΔKAD=ΔHBA

=>KD=HB và AK=BH

Ta có: ΔABC đều

=>\(\hat{ABC}=\hat{ACB}=\hat{BAC}=60^0\)

ΔFDC vuông tại F

=>\(\hat{FDC}+\hat{FCD}=90^0\)

=>\(\hat{FDC}=90^0-60^0=30^0\)

Ta có: \(\hat{EDB}+\hat{EDF}+\hat{FDC}=180^0\)

=>\(\hat{EDF}=180^0-30^0-90^0=60^0\)

Đặt AB=BC=CD=a

BC=3BD

=>\(BD=\frac{BC}{3}=\frac{a}{3}\)

BD+CD=BC

=>\(CD=a-\frac{a}{3}=\frac23a\)

Xét ΔBDE vuông tại D có tan B=\(\frac{DE}{DB}\)

=>\(DE=DB\cdot\tan B=\frac{a}{3}\cdot\tan60=\frac{a\sqrt3}{3}\)

Xét ΔDFC vuông tại F có sin C=\(\frac{DF}{DC}\)

=>\(DF=DC\cdot\sin60=\frac23a\cdot\frac{\sqrt3}{2}=\frac{a\sqrt3}{3}\)

=>DE=DF

Xét ΔDEF có DE=DF và \(\hat{EDF}=60^0\)

nên ΔDEF đều

a: Xét ΔABD và ΔEBD có

BA=BE

\(\widehat{ABD}=\widehat{EBD}\)

BD chung

Do đó: ΔABD=ΔEBD