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24 tháng 8

Bài giải: 1. Tìm N: N = 3 + a + 8 + 7 + 2 + 9 + b N = (3 + 8 + 7 + 2 + 9) + (a + b) N = 29 + (a + b) Thay a + b = 7 vào ta được: N = 29 + 7 = 36 2. Tìm a và b: Theo công thức tính số trung bình cộng, ta có: X = (2*3 + 3*a + 5*8 + 6*7 + 7*2 + 8*9 + 10*b) / N 6 = (6 + 3*a + 40 + 42 + 14 + 72 + 10*b) / 36 6 = (174 + 3*a + 10*b) / 36 174 + 3*a + 10*b = 6 * 36 174 + 3*a + 10*b = 216 3*a + 10*b = 216 - 174 3*a + 10*b = 42 Biến đổi biểu thức: 3*a + 3*b + 7*b = 42 3*(a + b) + 7*b = 42 Thay a + b = 7 vào: 3*7 + 7*b = 42 21 + 7*b = 42 7*b = 42 - 21 7*b = 21 b = 3 Tìm a: a = 7 - b a = 7 - 3 a = 4 Kết luận: N = 36, a = 4, b = 3.

27 tháng 11 2017

Vì x và y là 2 đại lượng tỉ lệ nghịch nên:

x=a/y với a thuộc Q

Lại có x=10;y=1,6 nên a=x.y=10.1,6=16

theo công thức ta có bảng sau:

x     1             2           -4          8/3       -8       10

y     16            8          -4          6          -2       1,6

27 tháng 11 2017

Hệ số tỉ lệ : 10 . 1,6 = 16

x12-46-810
y168-4\(\frac{8}{3}\)-21,6
...
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Cho a,b∈R;n∈N∗a,b∈R;n∈N∗. Chứng minh...
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Cho a,b∈R;n∈N∗" role="presentation" style="border:0px; color:rgb(40, 40, 40); direction:ltr; display:inline-block; float:none; font-family:helvetica,arial,sans-serif; font-size:16.38px; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; white-space:nowrap; word-wrap:normal" class="MathJax_CHTML mjx-chtml">a,b∈R;n∈N∗. Chứng minh rằng:

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