\(\frac{1}{4^2}+\frac{1}{5^2}+...+\frac{1}{10^2}< \frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{9.10}< \frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...\frac{1}{9}-\frac{1}{10}\)

=> \(A< \frac{1}{4}-\frac{1}{10}=\frac{3}{30}=\frac{21}{210}\)

Ta lại có \(\frac{7}{44}=\frac{21}{132}>\frac{21}{210}\)

=> \(A< \frac{7}{44}\)

a) A=2¹+2²+2³+...+2²⁰¹⁰

    A=(2¹+2²)+(2³+2⁴)+.....+(2²⁰⁰⁹+2²⁰¹⁰)

    A=(2¹x3)+(2³x3)+.....+(2²⁰⁰⁹x3)

    A=3x(2¹+2³+.......+2²⁰⁰⁹)

Vậy A chia hết cho 3.

NHỮNG CÂU CÒN LẠI BẠN LÀM TƯƠNG TỰ !

c) \(M=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}...\frac{99}{100}< \frac{1}{2}.\frac{4}{4}.\frac{6}{6}...\frac{100}{100}=\frac{1}{2}\)

a) M . N = \(\left(\frac{1}{2.}.\frac{3}{4}.\frac{5}{6}...\frac{99}{100}\right).\left(\frac{2}{3}.\frac{4}{5}.\frac{6}{7}...\frac{100}{101}\right)=\frac{1.2.3.4....100}{2.3.4.5...101}=\frac{1}{101}\)

CMR A = 1/5 + 1/6 + 1/7 + ... + 1/17 < 2

A = 1/5 + 1/6 + 1/7 + ... + 1/17

Vì 1/6 < 1/7 < 1/8 < 1/9 < 1/5 và 1/10 < 1/11 < 1/12 < 1/13 < 1/14 <1/15 < 1/16 < 1/17 < 1/8 nên:

A = (1/5 + 1/6 + 1/7 + 1/8 + 1/9) + (1/10 + 1/11 + 1/12 + 1/13 + 1/14+ 1/15 + 1/16 + 1/17)

A < (1/5 + 1/5 + 1/5 + 1/5 + 1/5) + (1/8 + 1/8 + 1/8 + 1/8 + 1/8+1/8 + 1/8 + 1/8)

A < 1 + 1

A < 2

Vậy: A < 2 (đpcm)

A=\(\frac{10^8+2}{10^8-1}=1+\frac{3}{10^8-1}\)

\(B=\frac{10^8}{10^8-3}=1+\frac{3}{10^8-3}\)

Vì\(10^8-1>10^8-3\)

\(\Rightarrow\frac{3}{10^8-1}< \frac{3}{10^8-3}\)

\(\Rightarrow1+\frac{3}{10^8-1}< 1+\frac{3}{10^8-3}\)

Vậy \(A< B\)