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Bài 1: Thực hiện phép tính và phân tích kết quả ra thừa số nguyên tố
a) \(160-\left(2^3\times5^2-6.25\right)\)
\(=160-\left(8.25-150\right)\)
\(=160-\left(200-150\right)\)
\(=160-50\)
\(=110\)
\(110=2.5.11\)
b) \(4\times5^2-32\div2^4\)
\(=4\times25-32\div16\)
\(=100-2\)
\(=98\)
\(98=2.7^2\)
c) \(5871\div\left[928-\left(247-82.5\right)\right]\)
\(=5871\div\left[928-\left(247-410\right)\right]\)
\(=5871\div\left[928-\left(-163\right)\right]\)
\(=5871\div\left[928+163\right]\)
\(=5871\div1091\)
\(=\frac{5871}{1091}\)
d) \(777\div7+1331\div11^3\)
\(=111+1331\div1331\)
\(=111+1\)
\(=112\)
\(112=2^4.7\)
e) \(6^2\div4.3+2.5^2\)
\(=12\div4.3+2.25\)
\(=9+50\)
\(=59\)
g) \(5.4^2-18\div3^2\)
\(=5.16-18\div9\)
\(=80-2\)
\(=78\)
\(78=2.3.13\)
\(160-\left(2^3.5^2-6.25\right)\)
\(=160-\left(8.25-6.25\right)\)
\(=160-\left[\left(8-6\right).25\right]\)
\(=160-\left[2.25\right]\)
\(=160-50\)
\(=110\)
~ Hok tốt ~
a) \(2^5:8^4=2^5:\left(2^3\right)^4=2^5:2^{12}=2^{-7}=\frac{1}{2^7}\)\(=\left(\frac{1}{2}\right)^7\)
b) \(25^6:125^3=\left(5^2\right)^6:\left(5^3\right)^3=5^{12}:5^9=5^3\)
c) \(625^2:25^7=\left(5^4\right)^2:\left(5^2\right)^7=5^8:5^{14}=5^{-6}=\frac{1}{5^6}=\left(\frac{1}{5}\right)^6\)
d) \(12^3.3^3=\left(12.3\right)^3=36^3\)
e) \(32^2:2^4=\left(2^5\right)^2:2^4=2^{10}:2^4=2^6\)
g) \(64.2:2^5=2^6.2:2^5=2^7:2^5=2^2\)
Mk làm hộ bn rùi đó nhớ ủng hộ mk nha ^_^
a) (1 phần 2 ) mũ 7
b) 5 mũ 3
c) (1 phần 5 ) mũ 6
d) 36 mũ 3
e) 2 mũ 6
g) 2 mũ 2
câu a:
3\(^2\) x 5 + 2\(^3\) x 10 - 81 : 3
= 9 x 5 + 8 x 10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
Câu c:
100 : 5\(^2\) + 7 x 3\(^2\)
= 100 : 25 + 7 x 9
= 4 + 63
= 67
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
b) \(5^3\cdot2-100:4+2^3\cdot5\)
\(=125\cdot2-25+8\cdot5\)
\(=250-25+40\)
\(=225+40=265\)
c) \(6^2:9+50\cdot2+3^3-3\)
\(=36:9+100+27-3\)
\(=4+100+27-3\)
\(=104+27-3=131-3=128\)
d) \(3^2\cdot5+2^3\cdot10-81:3\)
\(=9\cdot5+8\cdot10-27\)
\(=45+80-27\)
\(=125-27=98\)
e) \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^{13-10}-5^2\cdot2^2\)
\(=5^3-\left(5\cdot2\right)^2\)
\(=125-10^2\)
\(=125-100=25\)
f) \(20:2^2+5^9:5^8\)
\(=20:4+5^{9-8}\)
\(=5+5^1=5+5=10\)
g) \(100:5^2+7\cdot3^2\)
\(=10^2:5^2+7\cdot9\)
\(=\left(10:5\right)^2+63\)
\(=2^2+63=4+63=67\)
h) \(84:4+3^9:3^7+5^0\)
\(=21+3^{9-7}+1\)
\(=21+3^2+1\)
\(=21+9+1=30+1=31\)
i) \(29-\left[16+3\cdot\left(51-49\right)\right]\)
\(=29-\left[16+3\cdot2\right]\)
\(=29-\left[16+6\right]\)
\(=29-22=7\)
j) \(\left(15^{19}:5^{17}+3\right)\cdot0:7\)
\(=\left[\left(3\cdot5\right)^{19}:5^{17}+3\right]\cdot0\)
Vì số nào nhân cho 0 cũng bằng 0 nên giá trị biểu thức trên bằng 0
k) \(7^9:7^7-3^2+2^3\cdot5\)
\(=7^{9-7}-9+8\cdot5\)
\(=7^2-9+40\)
\(=49-9+40=40+40=80\)
l) \(1200:2+6^2\cdot2^1+18\)
\(=600+36\cdot2+18\)
\(=600+72+18\)
\(=600+\left(72+18\right)=600+90=690\)
m) \(5^9:5^7+70:14-20\)
\(=5^{9-7}+5-20\)
\(=5^2+5-20\)
\(25+5-20=30-20=10\)
Những câu sau mình làm sau nhé bạn!!!!!!!
a: \(160-\left(2^3\cdot5^2-6\cdot25\right)\)
\(=160-\left(8\cdot25-150\right)\)
=160-(200-150)
=160-50
=110
\(=2\cdot5\cdot11\)
b: \(4\cdot5^2-32:2^4=4\cdot25-32:16=100-2=98=2\cdot7^2\)
c: \(5871:\left\lbrack928-\left(247-82\cdot5\right)\right\rbrack\)
\(=5871:\left\lbrack928-\left(247-410\right)\right\rbrack\)
=5871:[928-247+410]
=5871:1091
d: \(777:7+1331:11^3=111+1=112=2^4\cdot7\)
e: \(6^2:4\cdot3+2\cdot5^2=36:4\cdot3+2\cdot25\)
=27+50
=77
\(=7\cdot11\)
g: \(5\cdot4^2-18:3^2=5\cdot16-18:9=80-2=78=2\cdot3\cdot13\)
h: \(80-\left(4\cdot5^2-3\cdot2^3\right)=80-\left(4\cdot25-3\cdot8\right)\)
=80-(100-24)
=80-76
=4
=2^2
i: \(23\cdot75+25\cdot23+180\)
\(=23\left(75+25\right)+180\)
=2300+180
=2480
\(=2^4\cdot5\cdot31\)
k: \(2^4\cdot5-\left\lbrack131-\left(13-4\right)^2\right\rbrack\)
\(=16\cdot5-\left\lbrack131-81\right\rbrack\)
=80-50
=30
=2*3*5
m: 100:{250:[450-\(\left(4\cdot5^3-2^2\cdot25\right)\) ]}
=100:{250:[450-\(\left(4\cdot125-4\cdot25\right)\) ]}
=100:{250:[450-500+100]}
=100:{250:50}
=100:5
=20
=2^2*5