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Bài làm:
Bài 1
a) \(\left(x-\frac{1}{2}\right)^2=0\)
\(\rightarrow\left(x-\frac{1}{2}\right)^2=0^2\)
\(\rightarrow x-\frac{1}{2}=0\)
\(\Rightarrow x=\frac{1}{2}\)
Bài 2
a) \(25^3\div5^2=\left(5^2\right)^3\div5^2=5^6\div5^2=5^4\)
b) \(\left(\frac{3}{7}\right)^{21}\div\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}\div\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}\div\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
c) \(3-\left(\frac{-6}{7}\right)^0+\left(\frac{1}{2}\right)^2\div2=3-1+\frac{1}{4}\times\frac{1}{2}=2+\frac{1}{8}=\frac{17}{8}\)
Bài 3
a) \(9\times3^3\times\frac{1}{81}\times3^2=3^2\times3^3\times\frac{1}{3^4}\times3^2=3^3\)
b) \(4\times2^5\div\left(2^3\times\frac{1}{16}\right)=2^2\times2^5\div\left(2^3\times\frac{1}{2^4}\right)=2^7\div\frac{1}{2}=2^6\)
c) \(3^2\times2^5\times\left(\frac{2}{3}\right)^2=3^2\times2^5\times\frac{2^2}{3^2}=3^2\times\frac{2^7}{3^2}=2^7\)
d) \(\left(\frac{1}{3}\right)^2\times\frac{1}{3}\times9^2=\left(\frac{1}{3}\right)^3\times3^4=\frac{1}{3^3}\times3^4=3^1\)
a: \(=3^2\cdot3^5:3^4=3^{2+5-4}=3^3\)
b: \(=2^3\cdot2^4:\left(\dfrac{8}{16}\right)=\dfrac{2^7}{2}=2^6\)
c: \(=3^7\cdot3^3=3^{10}\)
d: \(=5^3\cdot5^2\cdot\dfrac{1}{5^4}=5^1\)
a: \(B=\left(4\cdot2^5\right):\left(2^3\cdot\frac{1}{16}\right)\)
\(=\left(4\cdot32\right):\left(\frac{8}{16}\right)\)
\(=128:\frac12=128\cdot2=256\)
b: \(B=3^2\cdot\frac{1}{243}\cdot81^2\cdot\frac{1}{3^3}\)
\(=3^2\cdot\frac{1}{3^5}\cdot3^8\cdot\frac{1}{3^3}=\frac{3^8}{3^8}\cdot3^2=3^2=9\)
c: \(D=\left\lbrace\left(0,1\right)^2\right\rbrace^0+\left\lbrack\left(\frac17\right)^1\right\rbrack^2:\frac{1}{49}\cdot\left\lbrack\left(2^2\right)^3:2^5\right\rbrack\)
\(=1+\left(\frac17\right)^2\cdot49\cdot2^6:2^5\)
\(=1+49\cdot\frac{1}{49}\cdot2=1+2=3\)
d: \(C=\left(-0,5\right)^5:\left(-0,5\right)^3-\left(\frac{17}{2}\right)^7:\left(\frac{17}{2}\right)^6\)
\(=\left(-0,5\right)^{5-3}-\left(\frac{17}{2}\right)\)
\(=\left(-0,5\right)^2-\frac{17}{2}=0,25-\frac{17}{2}=\frac14-\frac{34}{4}=-\frac{33}{4}\)
a/
\(9.3^2.\frac{1}{81}.27=\frac{9.3^2.27}{81}=\frac{3^2.3^2.3^3}{3^4}=\frac{3^7}{3^4}=3^3\)
b/
\(4.32:\left(2^3.\frac{1}{16}\right)=4.32:\left(\frac{2^3}{16}\right)=4.32:\left(\frac{2^3}{2^4}\right)=4.32:\frac{1}{2}=4.32.2=4.64=4.4^3=4^4\)
c/
\(3^4.3^5:\frac{1}{27}=3^4.3^5.27=3^4.3^5.3^3=3^{12}\)
d/(ý bạn là (-2)^2 hay -2^2 , mình làm theo cách (-2)^2 nhé!)
\(2^2.4.\frac{32}{\left(-2\right)^2}.2^5=2^2.2^2.\frac{2^5}{2^2}.2^5=2^2.2^2.2^3.2^5=2^{12}\)
7^6+7^5+7^4 chia hết cho 11
= 7^4.2^2+7^4.7+7^4
= 7^4.(2^2+7+1)
= 7^4. 11
Vì tích này có số 11 nên => chia hết cho 7
mong các bạn giúp đỡ mình nhé! Mình đang cần gấp!