B1a)\(11\frac34-\left(6\frac56-4\frac12\right)+1\frac23\)

=\(11\frac34-6\frac56+4\frac12+1\frac23\)

=\(\left(11-6+4+1\right)+\left(\frac34-\frac56+\frac12+\frac23\right)\)

=\(10+\left(\frac{9}{12}-\frac{10}{12}+\frac{6}{12}+\frac{8}{12}\right)\)

=\(10+\left(-\frac{1}{12}+\frac{6}{12}+\frac{8}{12}\right)\)

=10+\(\frac{13}{12}\)

=\(\frac{120}{12}+\frac{13}{12}\)

=\(\frac{133}{12}\)

b)\(2\frac{17}{20}-1\frac{11}{5}+6\frac{9}{20}:3\)

= \(\frac{57}{20}-\frac{16}{5}+\frac{129}{20}\times\frac13\)

=\(\frac{57}{20}-\frac{16}{5}+\frac{129}{60}\)

=\(\frac{171}{60}-\frac{192}{60}+\frac{129}{60}\)

=\(\frac{108}{60}\)

=\(\frac95\)

Đăng lần lượt nhiều nhất 3 câu hỏi thôi, chứ đăng nhiều vậy, thấy nhát làm lắm. 

\(\text{a)}\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(4^2-2^4\right)\)

\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left[\left(2^2\right)^2-2^4\right]\)

\(=\left(2^{17}+17^2\right)\left(9^{15}-15^9\right)\left(2^4-2^4\right)\)

\(=\left(2^{17}-17^2\right)\left(9^{15}-15^9\right).0\)

\(=0\)

\(\text{b)}\left(7^{1997}-7^{1995}\right):\left(7^{1994}.7\right)=\frac{7^{1997}-7^{1995}}{7^{1994}.7}=\frac{7^{1995}\left(7^2-1\right)}{7^{1995}}=7^2-1=48\)

a) \(\frac{-5}{8}\cdot\left(\frac{4}{9}+\frac{-7}{12}\right)\)

\(=\frac{-5}{8}\cdot\frac{-5}{36}\)

\(=\frac{25}{288}\)

b) \(\left(-3,2\right)\cdot\frac{-15}{64}+\left(0,8-2\frac{4}{5}\right):3\frac{1}{2}\)

\(=\frac{3}{4}+\left(-2\right):\frac{7}{2}\)

\(=\frac{3}{4}+\frac{-4}{7}\)

\(=\frac{5}{28}\)

=))

b1: a, 6¹².(15+19-34)=6¹².0=0

b,4¹⁴.(37.4+23.4-240)=4¹⁴.0=0

c,(5¹⁷.125-5¹⁸.25)+6³:2³=(5¹⁷.5³-5¹⁸.5²)+3³=0+27=27

b2:a,143+7.(n-17)=206

===> 7.(n-17)=206-143=63

====>n-17=63:7=9

=====>n=9+17=26

vậy n=26

b,128-28:(15-n)=124

====>28:(15-n)=128-124=4

=====> 15-n=28:4=7

=====> n=15-7=8

vậy n=8

c,3ⁿ.2+48=210

====>3ⁿ.2=210-48=162

====>3ⁿ=162:2=81=3⁴

====>n=4

vậy n=4

\(A=-\frac{2}{3}+1\frac{1}{4}-\frac{1}{6}=-\frac{2}{3}+\frac{5}{4}-\frac{1}{6}=\frac{5}{12}\)

\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right)\div1\frac{23}{24}\)

\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right)\div\frac{47}{24}\)

\(B=\frac{13}{20}-\frac{47}{60}\cdot\frac{24}{47}\)

\(B=\frac{13}{20}-\frac{2}{5}=\frac{1}{4}\)

vào câu hỏi tương tự nha bạn

tick cho tui nha

bài 1 a)

\(\frac{15}{7}\times\frac43+\frac63\)

=\(\frac{60}{21}+\frac63\)

=\(\frac{60}{21}+\frac{42}{21}\)

=\(\frac{102}{21}\)

=\(\frac{34}{7}\)

b)\(\frac{-13}{41}\times\frac{17}{11}\times\frac{11}{17}\)

=\(\frac{-13}{41}\times\left(\frac{17}{11}\times\frac{11}{17}\right)\)

=\(\frac{-13}{41}\times1\)

=\(\frac{-13}{41}\)