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a) \(\left(x-\frac{5}{8}\right).\frac{5}{18}=\frac{-15}{36}\)
\(\Rightarrow x-\frac{5}{8}=\frac{-15}{36}:\frac{5}{18}\)
\(\Rightarrow x-\frac{5}{8}=\frac{-3}{2}\)
\(\Rightarrow x=\frac{-3}{2}+\frac{5}{8}\)
\(\Rightarrow x=\frac{-7}{8}\)
c) \(x\)là ước của 4
\(\Rightarrow x\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
nhớ tk ^.^\(\)
\(\)
\(a)\) \(\left(x-\frac{5}{8}.\right).\frac{5}{18}=-\frac{15}{36}\)
\(\Rightarrow x-\frac{5}{8}=-\frac{15}{36}:\frac{5}{18}\)
\(\Rightarrow x-\frac{5}{8}=-\frac{15}{36}.\frac{18}{5}\)
\(\Rightarrow x-\frac{5}{8}=-\frac{3}{2}\)
\(\Rightarrow x=-\frac{3}{2}+\frac{5}{8}\)
\(\Rightarrow x=-\frac{12}{8}+\frac{5}{8}\)
\(\Rightarrow x=-\frac{7}{8}\)
Vậy \(x=-\frac{7}{8}\)
\(b)\frac{x+2}{5}=-\frac{15}{2}\)
\(\Rightarrow\left(x+2\right).2=-15.5\)
\(\Rightarrow\left(x+2\right).2=-75\)
\(\Rightarrow x+2=-75:2\)
\(\Rightarrow x+2=-37,5\)
\(\Rightarrow x=-37,5-2\)
\(\Rightarrow x=-39,5\)
\(c)\)Do x là Ư ( 4 )
\(\Rightarrow x\in\left\{1;-1;2;-2;4;-4\right\}\)
Chúc bạn học tốt !!!!
\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)
\(=\frac{11}{125}-\left(\frac{17}{18}-\frac{8}{18}\right)+\left(\frac{17}{14}-\frac{10}{14}\right)\)
\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)
\(=\frac{11}{125}+\left(\frac{1}{2}-\frac{1}{2}\right)\)= \(\frac{11}{125}\)
b) \(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=\left(6-5-3\right)+\left(\frac{7}{3}-\frac{5}{3}-\frac{2}{3}\right)+\left(\frac{1}{2}+\frac{3}{2}-\frac{5}{2}\right)\)
\(=-2+0+\frac{-1}{2}\)
= \(-2-\frac{-1}{2}=-\left(2+\frac{1}{2}\right)=-2\frac{1}{2}\)
Bài 1: Tự làm nha (hơi rối, chắc sai đề ấy bn\)
Bài 2:
Chuyển sag bị động:
1)They have done these exercises
=>These exercises have been done.
2)Are they watching TV now?
=>Is TV being watched now?
3)I don't play volleyball everyday
=>Volleyball is played everyday.
4)Can you paint this picture?
=>Can this picture be painted?
5)They are going to build this school
=>This school is going to be bult.
SS nhầm đề nha đề đúng đây:
Bài 1 đó:\(K=\frac{5^2}{1.5}+\frac{5^2}{5.10}+...+\frac{5^2}{45.50}\)
Ờ đã hiểu:
Bài 1:
\(K=\frac{5^2}{1.5}+\frac{5^2}{5.10}+...+\frac{5^2}{45.50}\)
\(=5\left(\frac{5}{1.5}+\frac{5}{5.10}+...+\frac{5}{45.50}\right)\)
\(=5\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+...+\frac{1}{45}-\frac{1}{50}\right)\)
\(=5\left(1-\frac{1}{50}\right)\)
\(=5.\frac{49}{50}\)
\(=\frac{5}{1}.\frac{49}{50}=\frac{245}{50}\)
Tự rút gọn nha
\(K=\frac{5^2}{1.2}+\frac{5^2}{2.3}+...+\frac{5^2}{49.50}\)
\(=5^2\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{49.50}\right)\)
\(=5^2\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\right)\)
\(=5^2\left(\frac{1}{1}-\frac{1}{50}\right)\)
\(=5^2.\frac{49}{50}\)
\(=\frac{245}{10}\)
mk thấy đề này đúng ko phải sai đâu bn
K=5mu2/1x2+5mu2/2x3+....+5mu2/49x50=5mu2x(1/1x2+1/2x3+...+1/49x50)=25x(1/1-1/2+1/2-1/3+...+1/49-1/50)=25x(1/1-1/50)=25x(50/50-1/50)=25x49/50=49/2
3) Volleyball isn't played everyday.
Còn lại tham khảo ◥ὦɧ◤ŤŔầŃ VăŃ ĤùŃĞ™