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\(a,\) \(5.\left(4+6x\right)=290\)
\(4+6x=290:5\)
\(4+6x=58\)
\(6x=58-4\)
\(6x=54\)
\(x=54:6\)
\(x=9\left(tm\right)\)
Vậy ..................
\(b,x.3,7+x.6,3=120\)
\(x\left(3,7+6,3\right)=120\)
\(10x=120\)
\(x=120:10\)
\(x=12\left(tm\right)\)
Vậy ....................
c) \(\left(15.24-x\right):0,25=100:\dfrac{1}{4}\)
\(\left(360-x\right):\dfrac{1}{4}=400\)
\(360-x=400.\dfrac{1}{4}\)
\(360-x=100\)
\(x=360-100\)
\(x=260\left(tm\right)\)
Vậy ...................
a) 5. ( 4+6 . x ) = 290
( 4+6 . x ) = 290 : 5
4 + 6 . x = 58
6 .x = 58 - 4
6.x = 54
x = 54 : 6
x = 9
x.3,7+x.6,3=120b,x.3,7+x.6,3=120
x(3,7+6,3)=120x(3,7+6,3)=120
10x=12010x=120
x=120:10x=120:10
x=12(tm)
(15×24-x):0.25=100 : 1/4
(15×24-x):0.25 = 400
(15x24-x) = 100
360-x =100
x=260
(8.75+1.25 +5+1) x X=20
16 x X=20
X=20 :16
X=1.25
1. \(x-8+32=68\)
\(x-8=68-32\)
\(x-8=36\)
\(x=36+8\)
\(x=44\)
_____
2. \(x+8+32=68\)
\(x+8=68-32\)
\(x+8=36\)
\(x=36-8\)
\(x=28\)
_____
3. \(98-x+34=43\)
\(98-x=43-34\)
\(98-x=9\)
\(x=98-9\)
\(x=89\)
_____
4. \(98+x-34=43\)
\(98+x=43+34\)
\(98+x=77\)
\(x=77-98\)
\(x=-21\)
_____
5. \(x:5:4=800\)
\(x:5=800.4\)
\(x:5=3200\)
\(x=3200.5\)
\(x=16000\)
_____
6. \(18+x=384:8\)
\(18+x=48\)
\(x=48-18\)
\(x=30\)
_____
7. \(\left(84,6-2\times x\right):3,02=5,1\)
\(84,6-2.x=5,1.3,02\)
\(84,6-2.x=15,402\)
\(2.x=84,6-15,402\)
\(2.x=69,198\)
\(x=69,198:2\)
\(x=34,599\)
_____
8. \(x\times5=120:6\)
\(x.5=20\)
\(x=20:5\)
\(x=4\)
_____
9. \(\left(15\times24-x\right):0,25=100:0,25\)
\(\left(15.24-x\right):0,25=400\)
\(15.24-x=400.0,25\)
\(15.24-x=100\)
\(360-x=100\)
\(x=360-100\)
\(x=260\)
1,x-8+32=68
=>x-8=68-32=36
=>x=36+8=42
2,x+8+32=68
=>x+8=68-32=36
=>x=36-8=28
3,98-x+34=43
=>98-x=43-34=9
=>x=98-9=89
4,98+x-34=43
=>98+x=43+34=77
=>x=77-98=-21
5,x:5:4=800
=>x:20=800
=>x=800x20=16000
6,18+x=384:8=48
=>x=48-18=30
7,(84,6-2x):3,02=5,1
=>84,6-2x=5,1x3,02=15,402
=>2x=84,6-15,402=69,198
=>x=69,198:2=34,599
8,5x=120:6=20
=>x=20:5=4
9,(15x24-x):0,25=100:0,25=400
=>360-x=400x0,25=100
=>x=360-100=260.
a,\(2,5.16,27.4+7,3=16,27.10+7,3=162,7+7,3=170\)
b,\(8.6.10+4.25.12+3.16.31+2.34.24=48.10+48.25+48.31+48.34\)
\(=48.\left(10+25+31+34\right)=48.100=4800\)
c,\(78.31+78.24+78.17+22.72=78\left(31+24+17\right)+22.72=78.72+22.72\)
\(=72.\left(78+22\right)=72.100=7200\)
d,\(102.67-34.51=102.67-17.102=102.\left(67-17\right)=102.50=5100\)
đéo hiểu thì cút nhé đéo ai khiến m trả lời cả . ngu thì nói ngu đi đừng bày đặt t ghét nhất là cái loại như m đấy ạ
Bài 2
a, \(1-\left(12,5+x-4,25\right):21,75=0\)
\(=>21,75-12,5-x+4,25=0\)
\(=>13,5-x=0=>x=13,5\)
b,\(x.101-x+72.99+72=21050\)
\(=>100x+72.100=21050\)
\(=>100\left(x+72\right)=21050\)
\(=>x+72=210,5\)\(=>x=138,5\)
c,\(151-2\left(x-6\right)=2227:17\)
\(=>151-2\left(x-6\right)=131\)
\(=>2\left(x-6\right)=20\)
\(=>2x=32=>x=16\)
d,\(\left(x+4\right)+\left(x+6\right)+\left(x+8\right)+...+\left(x+26\right)=210\)\(=>12x+\left(4+6+8+...+26\right)=210\)
\(=>12x+180=210=>12x=30\)
\(=>x=\frac{30}{12}=\frac{15}{6}=\frac{5}{2}\)
\(1.x^2+11x=0\)
\(\Leftrightarrow x\left(x+11\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+11=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-11\end{cases}}\)
\(2.\left(x^2-1\right)\left(x^2-9\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)\left(x+9\right)\left(x-9\right)=0\)
chia thành 4 TH :
\(TH1:X-1=0\)
\(\Leftrightarrow x=1\)
\(TH2:x+1=0\)
\(\Leftrightarrow x=-1\)
\(TH3:X+9=0\)
\(\Leftrightarrow X=-9\)
\(TH4:x-9=0\)
\(\Leftrightarrow x=9\)
Kết luận ....
\(3.\left(\left|x+1\right|-5\right)\left(x^2-9\right)\)
\(\Leftrightarrow\left(\left|x+1\right|-5\right)\left(x-3\right)\left(x+3\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|-5=0\\x-3=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}\left|x+1\right|=5\\x=3\\x=-3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x+1=+_-5\Leftrightarrow x+1=5,x+1=-5\Leftrightarrow x=4,x=-6\\x=3x\\x=-3\end{cases}}\)
kết luận x=.....
\(4.\left(3x-16\right)⋮\left(x+2\right)\)
\(\Leftrightarrow\left(3x+6\right)-22\)
\(\Leftrightarrow3\left(x+2\right)-22⋮\left(x+2\right)\)
Vì\(\left(x+2\right)⋮\left(x+2\right)\)
\(\Rightarrow\left(3x-16\right)⋮\left(x+2\right)\)
Kết luận x=.....
-37 + 14 +26 + 37
=-37 + 37 + 14 + 36
=0 + 50
=50
-24 + 6 + 10 + 24
=(-24 + 24) +(6+10)
= 0+16
= 16
\(\left(84,6-2\cdot x\right):3,02=5,1\)
\(\Rightarrow84,6-2\cdot x=15,402\)
\(\Rightarrow2\cdot x=69,198\)
\(\Rightarrow x=69,198:2\)
\(\Rightarrow x=34,599\)
_____________
\(\left(15\cdot24-x\right):0,25=100:0,25\)
\(\Rightarrow\left(360-x\right):0,25=400\)
\(\Rightarrow360-x=100\)
\(\Rightarrow x-360-100\)
\(\Rightarrow x=260\)
______________
\(128\cdot x-12\cdot x-16\cdot x=5200\)
\(\Rightarrow x\cdot\left(128-12-16\right)=5200\)
\(\Rightarrow x\cdot100=5200\)
\(\Rightarrow x=5200:100\)
\(\Rightarrow x=52\)
__________________
\(5\cdot x+3,75\cdot x+1,25\cdot x=20\)
\(\Rightarrow x\cdot\left(5+3,75+1,25\right)=20\)
\(\Rightarrow10\cdot x=20\)
\(\Rightarrow x=20:10\)
\(\Rightarrow x=2\)
\(x\cdot3,7+x\cdot6,3=360:120\)
\(\Rightarrow x\cdot\left(3,7+6,3\right)=3\)
\(\Rightarrow x\cdot10=3\)
\(\Rightarrow x=\dfrac{3}{10}\)
__________________
\(x\cdot23-6\cdot23+x\cdot69=320\)
\(\Rightarrow x\cdot\left(23+69\right)=320+6\cdot23\)
\(\Rightarrow x\cdot92=458\)
\(\Rightarrow x=458:92\)
\(\Rightarrow x=\dfrac{229}{46}\)
___________________
\(\left(x+1\right)\left(x+2\right)=72\)
\(\Rightarrow x^2+2x+x+2=72\)
\(\Rightarrow x^2+3x+2=72\)
\(\Rightarrow x^2+3x+2-72=0\)
\(\Rightarrow x^2+3x-70=0\)
\(\Rightarrow x^2+10x-7x-70=0\)
\(\Rightarrow\left(x-7\right)\left(x+10\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=7\\x=-10\end{matrix}\right.\)
___________________
\(\left(x+2\right)\cdot16\cdot x=160x\)
\(\Rightarrow16x^2+32x=160x\)
\(\Rightarrow16x^2+32x-160x=0\)
\(\Rightarrow16x^2-128x=0\)
\(\Rightarrow16x\left(x-8\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)
a.(84,6-2. x ):3,02=5,1
=>84,6 - 2x = 15,402
=>2x=69,198
=>x=34,599
b.(15.24-x):0,25=100:0,25
=>(360-x) : 0,25 = 400
=>360-x = 400 . 0,25
=>360-x=100
=>x=360-100
=>x=260
c.128.x-12.x-16.x=5200
=>(128-12-16)x=5200
=>100x=5200
=>x=52
d.5.x+3,75.x+1,25.x=20
=>(5+3,75+1,25)x=20
=>10x=20
=>x=2
e.x.3,7+x.6,3=360:120
=>x(3,7+6,3)=3
=>10x=3
=>x=3/10
f.x.23-6.23+x.69=230
=>23x + 6.23 + 3x . 23 = 230
=>23.(x+6+3x)=230
=>4x+6=10
=>4x=10-6
=>4x=4
=>x=1
g.(x+1).(x+2)=72
TH1:x là số dương
=>(x+1)(x+2)=8.9
=>x+1=8
=>x=7
TH2:x là số âm
=>(x+1)(x+2)=(-9).(-8)
=>x+1=-9
=>x=-10
Vậy x=-10 hoặc x=7
h.(x+2).16.x=160.x
=>x+2 = 160.x:x:16
=>x+2=10
=>x=8
Đổi:
f.x.23-6.23+x.69=230
=>23.(x-6+3x)=230
=>4x-6=10
=>4x=10+6
=>4x=16
=>x=4
h.(x+2).16.x=160.x
=>(16x+32).x = 160x
=>16x^2 + 32x = 160x
=>16x^2 = 128x
=>16x^2 - 128x=0
=>x(16x-128)=0
=>x=0 hoặc 16x-128=0
+)x=0=>x=0
+)16x-128=0
=>16x=128
=>x=8
Câu thứ 2 a ghi nhầm đầu bài ạ
a.(84,6-2. x ):3,02=5,1
=>84,6 - 2x = 15,402
=>2x=69,198
=>x=34,599
b.(15.24-x):0,25=100:0,25
=>(360-x) : 0,25 = 400
=>360-x = 400 . 0,25
=>360-x=100
=>x=360-100
=>x=260
c.128.x-12.x-16.x=5200
=>(128-12-16)x=5200
=>100x=5200
=>x=52
d.5.x+3,75.x+1,25.x=20
=>(5+3,75+1,25)x=20
=>10x=20
=>x=2
e.x.3,7+x.6,3=360:120
=>x(3,7+6,3)=3
=>10x=3
=>x=3/10
f.x.23-6.23+x.69=230
=>23x - 6.23 + 3x . 23 = 230
=>23.(x-6+3x)=230
=>4x-6=16
=>4x=10+6
=>4x=16
=>x=4
g.(x+1).(x+2)=72
TH1:x là số dương
=>(x+1)(x+2)=8.9
=>x+1=8
=>x=7
TH2:x là số âm
=>(x+1)(x+2)=(-9).(-8)
=>x+1=-9
=>x=-10
Vậy x=-10 hoặc x=7
h.(x+2).16.x=160.x
=>(16x+32).x=160x
=>16x^2 + 32x - 160x = 0
=>16x^2 -128x=0
=>x(16x - 128)=0
=>x=0 hoặc 16x-128=0
16x-128=0
=>16x=128
=>x=8
Vậy x = 0 hoặc 8
Sửa yêu cầu. Tìm x (không phải tính nhanh)
(84,6 - 2.x) : 3,02 = 5,1
84,6 - 2x = 5,1 . 3,02
84,6 - 2x = 15,402
2x = 84,6 - 15,402
2x = 69,198
x = 69,198 : 2
x = 34,599
--------------------
(15.24 - x) : 0,25 = 100 : 0,25
(360 - x) : 0,25 = 400
360 - x = 400 . 0,25
360 - x = 100
x = 360 - 100
x = 260
--------------------
128.x - 12.x - 16.x = 5200
(128 - 12 - 16)x = 5200
100x = 5200
x = 5200 : 100
x = 52
--------------------
5.x + 3,75.x + 1,25.x = 20
(5 + 3,75 + 1,25)x = 20
10x = 20
x = 20 : 10
x = 2
--------------------
x.3,7 + x.6,3 = 360 : 120
(3,7 + 6,3)x = 3
10x = 3
x = 3/10
--------------------
x.23 - 6.23 + x.69 = 230
(23 + 69)x = 230 + 6.23
92x = 230 + 138
92x = 368
x = 368 : 92
x = 4
--------------------
(x + 1)(x + 2) = 72
x² + 2x + x + 2 - 72 = 0
x² + 3x - 70 = 0
x² - 7x + 10x - 70 = 0
(x² - 7x) + (10x - 70) = 0
x(x - 7) + 10(x - 7) = 0
(x - 7)(x + 10) = 0
x - 7 = 0 hoặc x + 10 = 0
*) x - 7 = 0
x = 7
*) x + 10 = 0
x = -10
Vậy x = -10; x = 7
--------------------
(x + 2).16.x = 160x
16x² + 32x - 160x = 0
16x² - 128x = 0
16x(x - 8) = 0
16x = 0 hoặc x - 8 = 0
*) 16x = 0
x = 0
*) x - 8 = 0
x = 8
Vậy x = 0; x = 8
a.(84,6-2. x ):3,02=5,1
=>84,6 - 2x = 15,402
=>2x=69,198
=>x=34,599
b.(15.24-x):0,25=100:0,25
=>(360-x) : 0,25 = 400
=>360-x = 400 . 0,25
=>360-x=100
=>x=360-100
=>x=260
c.128.x-12.x-16.x=5200
=>(128-12-16)x=5200
=>100x=5200
=>x=52
d.5.x+3,75.x+1,25.x=20
=>(5+3,75+1,25)x=20
=>10x=20
=>x=2
e.x.3,7+x.6,3=360:120
=>x(3,7+6,3)=3
=>10x=3
=>x=3/10
f.x.23-6.23+x.69=230
=>23x + 6.23 + 3x . 23 = 230
=>23.(x+6+3x)=230
=>4x+6=10
=>4x=10-6
=>4x=4
=>x=1
g.(x+1).(x+2)=72
TH1:x là số dương
=>(x+1)(x+2)=8.9
=>x+1=8
=>x=7
TH2:x là số âm
=>(x+1)(x+2)=(-9).(-8)
=>x+1=-9
=>x=-10
Vậy x=-10 hoặc x=7
h.(x+2).16.x=160.x
=>x+2 = 160.x:x:16
=>x+2=10
=>x=8