Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1:
a) \(\frac{13.23-13}{26.21+26}\)=\(\frac{13.22}{26.22}\)=\(\frac{13}{26}\)=\(\frac{1}{2}\)
b) \(\frac{16.21-16}{4.19+4}\)=\(\frac{16.20}{4.20}\)=\(\frac{16}{4}\)= 4
a, ( - 168 ) + 72 . ( - 168 ) + ( - 168 ) . 27
= ( - 168 ) + ( - 12096 ) + ( - 4536 )
= - 12264 + - 4536
= - 16800
b, 22 . ( - 3 ) - ( 110 + 8 ) : ( - 3 )2
= 4 . ( - 3 ) - ( 1 + 8 ) : 9
= ( - 12 ) - 9 : 9
= ( - 12 ) - 1
= - 13
c, ( - 1075 ) - ( 29 - 1075 )
= ( - 1075 ) - ( - 1046 )
= - 29
d, ( - 9 ) + ( - 11 ) + 21 + ( - 1 )
= - 20 + 21 + ( - 1 )
= 1 + - 1
= 0
e, 30 + 12 + ( - 20 ) + ( - 12 ) - ( 30 - 20 ) + ( 12 - 12 )
= 42 + ( - 20 ) + ( - 12 ) - 10 + 0
= 22 + ( - 12 ) - 10 + 0
= 10 - 10 + 0
= 0 + 0
= 0
g, ( 13 - 135 + 49 ) - ( 13 + 49 )
= [( - 122 ) + 49 ] - 62
= ( - 73 ) - 62
= - 135
h, 35 - { 12 - [ ( - 14 ) + ( - 2 ) } ]
= 35 - { 12 - ( - 16 ) }
= 35 - 28
= 7
Bài 2:
a. x - 35 = ( - 12 ) - 3
x - 35 = - 15
x = - 15 + 35
x = 20
b, \(\frac{1}{4}\)+ \(\frac{1}{3}\): 3x = - 5
\(\frac{3}{12}+\frac{4}{12}\): 3x = - 5
\(\frac{7}{12}\): 3x = - 5
3x = \(\frac{7}{12}\): - 5
3x = \(\frac{-7}{60}\)
x = \(\frac{-7}{60}\): 3
x = \(\frac{-7}{180}\)
c,2x-1 = 8
2x-1 = 24
x = 4 + 1
x = 5
a)-2-13-14-19=-48
b)221+4[-40-4]=221-176=45
c)(-2)^5+32=-32+32=0
d)=93
Bài 2:Tim x, biết
a)-3x=-7-8<=>x=5
b)(x-6).(7-x)=0
=>_x-6=0=>x=6
_7-x=0=>x=7
Bài 1 .Tính
a, (-2)-13+(-14)-19
= -15+(-14)-19
= -29-19
= -48
b,221+4[(-5).8-4]
=221+4[-40-4]
=221+4(-44)
=221+(-176)
=-45
c,(-2)3.(-2)2+32
=-8.4+32
=-32+32
=0
d,-15.12-8.(-12)
=-15.12-(-8).12
=12.[-15-(-8)]
=12.(-7)
=-84
Bài 2 .Tìm x , biết
a, -3x+8=-7
-3x=-7-8
-3x=-15
x=-15:(-3)
x=5
Vậy x=5
b, (x-6).(7-x)=0
\(\Rightarrow\orbr{\begin{cases}x-6=0\\7-x=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0+6=6\\x=7-0=7\end{cases}}\)
Vậy..............................
\(a,13-18-\left(-42\right)-15\)
\(=13-18+42-15\)
\(=\left(13-15\right)-\left(18+42\right)\)
\(=-2-60\)
\(=-62\)
\(b,369-4\left[\left(-5\right)+4.\left(-8\right)\right]\)
\(=369-4\left[\left(-5\right)+\left(-32\right)\right]\)
\(=369-4.\left(-37\right)\)
\(=369-\left(-148\right)\)
\(=369+148\)
\(=517\)
\(c,\left(-8\right)^3:\left(-8\right)^2+8\)
\(=-512:64+8\)
\(=-8+8\)
\(=0\)
\(d,\left(-12\right)\left(-13\right)+13.\left(-29\right)\)
\(=156+-377\)
\(=156-377\)
\(=-221\)
Bài 1:
a) 143-18-(-42)-15 = 125-(-42)-15= 167-15= 152
b) 369-4[(-5)+4.(-8)] = 369-4.(-37)= 369- (-148)= 517
c) (-8)3:(-8)2 +8 = (-512):64+8=(-8)+8= 0
d) (-12).(-13)+13.(-29)= 156+(-377)= -221
Bài 1 câu a:
1/-8 + -5/8
= -1/8 - 5/8
= -6/8
= -3/4
Câu b:
-1/21 + -1/28
= -4/84 - 3/84
= - 7/854
Câu c:
-5/9 + 8/15 + -2/11 + 4/-9 + 7/15
= (8/15+ 7/15) - (5/9 + 4/9) - 2/11
= 1 - 1 - 2/11
= 0 - 2/11
= - 2/11
Câu d:
-25/-75 + 17/34 + 121/- 132
= 1/3 + 1/2 - 11/12
= 4/12 + 6/12 - 11/12
= 10/12 - 11/12
= - 1/12
Bài 2a:
51/23 = 5151/2323 = 515151/232323
\(\frac{5151}{2323}\) = \(\frac{5151:101}{2323:101}\) = \(\frac{51}{23}\) (1)
\(\frac{515151}{232323}\) = \(\frac{515151:10101}{232323:10101}\) = \(\frac{51}{23}\) (2)
Từ (1) và (2) ta có:
\(\frac{51}{23}=\frac{5151}{2323}=\frac{515151}{232323}\) (đpcm)
\(-10< x< 8\)
\(\Rightarrow x\in\left\{-9;-8;...;7\right\}\)
\(x=-9+\left(-8\right)+...+7\)
\(\Rightarrow x=\left(-9\right)+\left(-8\right)=-17\)
P/s: Các câu còn lại tương tự ((:
a, \(-6x=18\)
\(\Rightarrow-x=3\)
\(\Rightarrow x=-3\)
b, \(2x-\left(-3\right)=7\)
\(2x+3=7\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
c, \(\left(x-5\right)\left(x+6\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+6=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-6\end{cases}}}\)
A=1+2+22+23+...+263
2A=2+22+23+...+263+264
\(-\)
\(A=1+2+2^2+....+2^{63}\)
\(A=2^{64}-1\)
Vậy A=264-1
A)=-8+8=0
B)=-221
2) chua lam duoc
cho minh nha
cho minh nha
A h cho minh nha
Bài 1:
a, (-8)3:(-8)2+8
=(-8)3-2 + 8
= -8+8=0
b, (-12).(-13)+13.(-29)
=-13(-12+29)
=-13.17
=-221
Bài 2:
A=(-a-b+c)-(-a-b-c)
=-a-b+c+a+b+c
=2c
bài 1
a,(-8)\(^3\):(-8)\(^2\)+8
=(-8)+8
=0
b,(-12)*(-13)+13*(-29)
=12*13+13*(-29)
=13*[12+(-29)]
=13*(-17
=-221
bai de the nay ma ko lam duoc hihihihihihihi
bài 1
=(-8)^3chia8^2+8
=-512chia 64+8
=-8+8
=0